Question Number 205431 by hardmath last updated on 21/Mar/24 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{in}\:\mathrm{any}\:\:\bigtriangleup\mathrm{ABC} \\ $$$$\frac{\mathrm{cotA}\:\mathrm{cotB}\:\mathrm{cotC}}{\mathrm{sinA}\:\mathrm{sinB}\:\mathrm{sinC}}\:\leqslant\:\frac{\mathrm{8}}{\mathrm{27}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 205420 by hardmath last updated on 20/Mar/24 $$\mathrm{If} \\ $$$$\mathrm{a}^{\mathrm{3}} \:+\:\mathrm{b}^{\mathrm{3}} \:+\:\mathrm{a}^{\mathrm{2}} \:+\:\mathrm{b}^{\mathrm{2}} \:=\:\mathrm{4} \\ $$$$\mathrm{Then}: \\ $$$$\mathrm{a}^{\mathrm{4}} \:+\:\mathrm{b}^{\mathrm{4}} \:\geqslant\:\mathrm{2} \\ $$ Answered…
Question Number 205422 by hardmath last updated on 20/Mar/24 $$\mathrm{If} \\ $$$$\left(\mathrm{a}\:+\:\mathrm{1}\right)\left(\mathrm{b}\:+\:\mathrm{1}\right)\left(\mathrm{c}\:+\:\mathrm{1}\right)\:=\:\mathrm{8} \\ $$$$\mathrm{Then}: \\ $$$$\mathrm{a}^{\mathrm{2}} \:+\:\mathrm{b}^{\mathrm{2}} \:+\:\mathrm{c}^{\mathrm{2}} \:\geqslant\:\mathrm{3} \\ $$ Answered by A5T last…
Question Number 205421 by hardmath last updated on 20/Mar/24 $$\mathrm{If} \\ $$$$\mathrm{a},\mathrm{b},\mathrm{c}>\mathrm{0}\:\:\:\mathrm{and}\:\:\:\mathrm{abc}=\mathrm{1} \\ $$$$\mathrm{Then}: \\ $$$$\frac{\mathrm{a}}{\mathrm{b}^{\mathrm{2024}} }\:+\:\frac{\mathrm{b}}{\mathrm{c}^{\mathrm{2024}} }\:+\:\frac{\mathrm{c}}{\mathrm{a}^{\mathrm{2024}} }\:\geqslant\:\mathrm{a}\:+\:\mathrm{b}\:+\:\mathrm{c} \\ $$ Terms of Service Privacy…
Question Number 205423 by hardmath last updated on 20/Mar/24 $$\mathrm{If} \\ $$$$\mathrm{a}\:,\:\mathrm{b}\:\in\:\mathbb{R} \\ $$$$\mathrm{Then}: \\ $$$$\mathrm{a}^{\mathrm{2}} \:+\:\mathrm{b}^{\mathrm{2}} \:\geqslant\:\mathrm{ab}\:+\:\sqrt{\frac{\mathrm{a}^{\mathrm{4}} \:+\:\mathrm{b}^{\mathrm{4}} }{\mathrm{2}}} \\ $$ Answered by Berbere…
Question Number 205380 by cortano12 last updated on 19/Mar/24 Commented by Rasheed.Sindhi last updated on 19/Mar/24 $$\boldsymbol{{please}}\:{don}'{t}\:{write}\:{your}\:{solution} \\ $$$${as}\:{a}\:{comment}!\:{Instead}\:{write}\:{it}\:{as} \\ $$$${answer}\:\boldsymbol{{in}}\:\boldsymbol{{order}}\:\boldsymbol{{to}}\:\boldsymbol{{prserve}}\:\boldsymbol{{chronological}} \\ $$$$\boldsymbol{{order}}\:\boldsymbol{{of}}\:\boldsymbol{{answers}}! \\ $$…
Question Number 205367 by hardmath last updated on 18/Mar/24 Answered by Ghisom last updated on 18/Mar/24 $$\left(\frac{{n}^{\mathrm{3}/\mathrm{2}} }{\mathrm{3}^{{n}} }+\frac{{n}^{\mathrm{2}} }{\mathrm{4}^{{n}} }+\frac{{n}^{\mathrm{5}/\mathrm{2}} }{\mathrm{5}^{{n}} }\right)^{\mathrm{1}/{n}} = \\…
Question Number 205353 by MATHEMATICSAM last updated on 17/Mar/24 $$\mathrm{If}\:{ax}^{\mathrm{2}} \:+\:{bx}\:+\:{c}\:=\:\mathrm{0}\:\mathrm{had}\:\mathrm{two}\:\mathrm{roots}\:{p}\:\mathrm{and}\:{q} \\ $$$$\mathrm{and}\:{p}^{\mathrm{2}} \:+\:{q}^{\mathrm{2}} \:=\:{p}^{\mathrm{3}} \:+\:{q}^{\mathrm{3}} \:\mathrm{then}\:\mathrm{show}\:\mathrm{that} \\ $$$${b}^{\mathrm{3}} \:−\:\mathrm{2}{a}^{\mathrm{2}} {c}\:+\:{ab}^{\mathrm{2}} \:=\:\mathrm{3}{abc}. \\ $$ Answered…
Question Number 205324 by hardmath last updated on 16/Mar/24 $$\mathrm{Compare}: \\ $$$$\mathrm{37}^{\mathrm{37}} \:\:\:\mathrm{and}\:\:\:\mathrm{36}^{\mathrm{38}} \\ $$ Answered by nikif99 last updated on 16/Mar/24 $$\mathrm{37}^{\mathrm{37}} \:\lessgtr\:\mathrm{36}^{\mathrm{38}} \:\Rightarrow…
Question Number 205319 by saifu018 last updated on 16/Mar/24 Terms of Service Privacy Policy Contact: info@tinkutara.com