Question Number 164191 by mathlove last updated on 15/Jan/22 Answered by cortano1 last updated on 15/Jan/22 Commented by MJS_new last updated on 15/Jan/22 $$\mathrm{there}'\mathrm{s}\:\mathrm{only}\:\mathrm{1}\:\mathrm{solution}\:\mathrm{and}\:\mathrm{it}'\mathrm{s} \\…
Question Number 164177 by mathlove last updated on 15/Jan/22 $${x}+\frac{\mathrm{1}}{{x}}=\mathrm{3} \\ $$$$\frac{{x}}{\:\sqrt{{x}}+\mathrm{1}}=? \\ $$ Answered by mr W last updated on 15/Jan/22 $${x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{1}=\mathrm{0} \\…
Question Number 164156 by HongKing last updated on 14/Jan/22 $$\mathrm{if}\:\:\mathrm{ABC}\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with}\:\mathrm{usual} \\ $$$$\mathrm{notations},\:\mathrm{then}\:\mathrm{prove}\:\mathrm{the}\:\mathrm{following} \\ $$$$\mathrm{inequality}: \\ $$$$\left(\mathrm{4R}\:+\:\mathrm{r}\right)^{\mathrm{3}} \:-\:\mathrm{4r}^{\mathrm{2}} \left(\mathrm{2R}\:-\:\mathrm{r}\right)\:-\:\mathrm{3s}^{\mathrm{2}} \left(\mathrm{2R}\:+\:\mathrm{r}\right)\:\geqslant\:\mathrm{0} \\ $$ Terms of Service Privacy…
Question Number 164157 by HongKing last updated on 14/Jan/22 $$\mathrm{let}\:\:\mathrm{a};\mathrm{b};\mathrm{c}\geqslant\mathrm{0}\:\:\mathrm{and}\:\:\mathrm{ab}+\mathrm{bc}+\mathrm{ca}+\mathrm{2abc}\geqslant\mathrm{1} \\ $$$$\mathrm{find}\:\boldsymbol{\mathrm{min}}\:-\:\mathrm{value}\:\mathrm{of}\:\boldsymbol{\mathrm{S}} \\ $$$$\boldsymbol{\mathrm{S}}\:=\:\sqrt{\mathrm{a}\:+\:\mathrm{1}}\:+\:\sqrt{\mathrm{b}\:+\:\mathrm{1}}\:+\:\sqrt{\mathrm{c}\:+\:\mathrm{1}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 164154 by HongKing last updated on 14/Jan/22 $$\begin{cases}{\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{xy}\:+\:\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{9}}\\{\mathrm{y}^{\mathrm{2}} \:+\:\mathrm{yz}\:+\:\mathrm{z}^{\mathrm{2}} \:=\:\mathrm{16}}\\{\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{xz}\:+\:\mathrm{z}^{\mathrm{2}} \:=\:\mathrm{25}}\end{cases} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{S}\:=\:\mathrm{xy}\:+\:\mathrm{yz}\:+\:\mathrm{xz} \\ $$ Answered by behi834171 last updated…
Question Number 164155 by HongKing last updated on 14/Jan/22 $$\mathrm{if}\:\mathrm{the}\:\mathrm{root}\:\mathrm{of}\:\mathrm{equation} \\ $$$$\mathrm{x}^{\mathrm{9}} \:-\:\mathrm{10x}\:+\:\mathrm{1}\:=\:\mathrm{0}\:\:\mathrm{are}\:\:\mathrm{x}_{\mathrm{1}} \:\:\mathrm{and}\:\:\mathrm{x}_{\mathrm{2}} \\ $$$$\mathrm{x}_{\mathrm{1}} \mathrm{x}_{\mathrm{2}} \:=\:\mathrm{1} \\ $$$$\mathrm{find}:\:\:\mathrm{x}_{\mathrm{1}} \:+\:\mathrm{x}_{\mathrm{2}} \:=\:? \\ $$ Commented…
Question Number 164148 by mathlove last updated on 14/Jan/22 $${ln}\left(\frac{\mathrm{3}^{{x}} }{\frac{\mathrm{27}}{\mathrm{81}}}\right)=\mathrm{0}\:\:\:\:\:\:\:\:\:{then}\:\:\:\:{x}=? \\ $$ Answered by nikif99 last updated on 14/Jan/22 $$\mathrm{log}\:_{{b}} \mathrm{1}=\mathrm{0}\:\Rightarrow \\ $$$$\left(\frac{\mathrm{3}^{{x}} }{\frac{\mathrm{27}}{\mathrm{81}}}\right)=\mathrm{1}\:\Rightarrow\mathrm{3}^{{x}}…
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Question Number 164135 by mathlove last updated on 14/Jan/22 $${p}\left({x}\right)+{xp}\left(−{x}\right)={x}^{\mathrm{2}} +\mathrm{1} \\ $$$${faind}\:\:\:{p}\left(\mathrm{2}\right)=? \\ $$ Answered by mr W last updated on 14/Jan/22 $${p}\left({x}\right)+{xp}\left(−{x}\right)={x}^{\mathrm{2}} +\mathrm{1}\:\:\:…\left({i}\right)…
Question Number 164125 by HongKing last updated on 14/Jan/22 $$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\underset{\:\mathrm{0}} {\overset{\:\frac{\boldsymbol{\pi}}{\mathrm{2}}} {\int}}\underset{\:\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:\mathrm{arctan}\:\left(\frac{\mathrm{sin}\boldsymbol{\mathrm{x}}}{\mathrm{u}\:+\:\mathrm{cos}\boldsymbol{\mathrm{x}}}\right)\:\mathrm{dudx}\:=\:\frac{\pi^{\mathrm{2}} }{\mathrm{16}}\:+\:\frac{\mathrm{3}}{\mathrm{2}}\:\mathrm{ln}\left(\mathrm{2}\right)\:-\:\frac{\pi}{\mathrm{4}} \\ $$ Answered by Kamel last updated on…