Question Number 163632 by HongKing last updated on 08/Jan/22 $$\frac{\left(\mathrm{x}^{\mathrm{2}} \:-\:\mathrm{y}^{\mathrm{2}} \right)\centerdot\sqrt{\mathrm{3}}}{\:\sqrt{\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{3x}^{\mathrm{2}} \mathrm{y}\:+\:\mathrm{3xy}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{3}} }}\:=\:-\mathrm{1} \\ $$$$\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{y}^{\mathrm{3}} \:=\:\left(\mathrm{x}\:+\:\mathrm{y}\right)^{\mathrm{2}} \\ $$$$\mathrm{find}:\:\:\boldsymbol{\mathrm{x}}\:\:\mathrm{and}\:\:\boldsymbol{\mathrm{y}} \\ $$ Answered…
Question Number 163624 by amin96 last updated on 08/Jan/22 Answered by mr W last updated on 09/Jan/22 $${A}=\mathrm{2}^{\mathrm{21}} ×\mathrm{17}^{\mathrm{24}} \\ $$$${full}\:{squares}: \\ $$$$\mathrm{1}\:\Rightarrow\:\mathrm{1} \\ $$$$\mathrm{2}^{\mathrm{2}}…
Question Number 163631 by HongKing last updated on 08/Jan/22 $$\mathrm{x}\:+\:\frac{\mathrm{1}}{\mathrm{x}}\:=\:\sqrt{\mathrm{3}}\:\:\Rightarrow\:\mathrm{x}^{\mathrm{3579}} \:+\:\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{3579}} }\:=\:? \\ $$ Answered by MathsFan last updated on 09/Jan/22 $$\mathrm{x}^{\mathrm{2}} −\mathrm{x}\sqrt{\mathrm{3}}+\mathrm{1}=\mathrm{0}\:\rightarrow\:\mathrm{x}=\frac{{i}\pm\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$\left(\frac{{i}\pm\sqrt{\mathrm{3}}}{\mathrm{2}}\right)^{\mathrm{3579}}…
Question Number 32541 by rahul 19 last updated on 27/Mar/18 $${Coefficient}\:{of}\:{x}^{\mathrm{5}} \:{in}\:{the}\:{expansion} \\ $$$${of}\:\left({x}^{\mathrm{2}} −{x}−\mathrm{2}\right)^{\mathrm{5}} \:{is} \\ $$ Answered by MJS last updated on 27/Mar/18…
Question Number 32543 by rahul 19 last updated on 27/Mar/18 $$\boldsymbol{{T}}{he}\:{coefficient}\:{of}\:{x}^{\mathrm{4}} \:{in}\:{the}\:{expansion} \\ $$$${of}\:\left(\mathrm{1}+\mathrm{5}{x}+\mathrm{9}{x}^{\mathrm{2}} +…..\infty\right)\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{\mathrm{11}} {is} \\ $$$$\left.{a}\right)\:\mathrm{171} \\ $$$$\left.{b}\right)\:\mathrm{172} \\ $$$$\left.{c}\right)\:\mathrm{173} \\ $$$$\left.{d}\right)\:\mathrm{176}…
Question Number 98077 by Lekhraj last updated on 11/Jun/20 Commented by MJS last updated on 11/Jun/20 $$\mathrm{it}\:\mathrm{only}\:\mathrm{makes}\:\mathrm{sense}\:\mathrm{if}\:{a},\:{b}\:\mathrm{are}\:\mathrm{digits}\:\mathrm{and}\:{ab} \\ $$$$\mathrm{doesn}'\mathrm{t}\:\mathrm{mean}\:{a}×{b}\:\mathrm{but}\:\mathrm{10}{a}+{b}: \\ $$$${a},\:{b}\:\in\mathbb{N}\wedge\mathrm{1}\leqslant{a}\leqslant\mathrm{9}\wedge\mathrm{0}\leqslant{b}\leqslant\mathrm{9} \\ $$$$\mathrm{now}\:\mathrm{try}\:\mathrm{all}\:\mathrm{possible}\:\mathrm{pairs} \\ $$$$\mathrm{1}!+\mathrm{0}!=\mathrm{10}^{\mathrm{2}}…
Question Number 98073 by bobhans last updated on 11/Jun/20 $$\mathrm{solve}\:\sqrt{\mathrm{6}−\mathrm{x}}\:=\:\mathrm{6}−\mathrm{x}^{\mathrm{2}} \\ $$ Commented by john santu last updated on 11/Jun/20 $$\mathrm{equation}\:\mathrm{defined}\:\mathrm{in}\:\mathrm{6}−\mathrm{x}\geqslant\mathrm{0}\:\wedge\:\mathrm{6}−\mathrm{x}^{\mathrm{2}} \:\geqslant\mathrm{0} \\ $$$$\Leftrightarrow\:\mathrm{x}\:\leqslant\:\mathrm{6}\:\wedge\:−\sqrt{\mathrm{6}}\:\leqslant\:\mathrm{x}\:\leqslant\:\sqrt{\mathrm{6}} \\…
Question Number 32532 by rahul 19 last updated on 28/Mar/18 $$\boldsymbol{{I}}{f}\:{a},{b},{c}\:{are}\:\mathrm{3}\:{positive}\:{numbers}\:{in}\:{an} \\ $$$$\boldsymbol{{A}}.\boldsymbol{{P}}\:{and}\: \\ $$$${T}=\:\frac{{a}+\mathrm{8}{b}}{\mathrm{2}{b}−{a}}+\frac{\mathrm{8}{b}+{c}}{\mathrm{2}{b}−{c}}. \\ $$$${Then}\:{the}\:{value}\:{of}\:{T}^{\:\:\mathrm{2}\:} \:{is}\:? \\ $$$${Ans}.\:{given}\:{is}\:\mathrm{361}. \\ $$ Commented by Rasheed.Sindhi…
Question Number 98067 by 995563401 last updated on 11/Jun/20 Answered by Farruxjano last updated on 11/Jun/20 Answered by 1549442205 last updated on 12/Jun/20 $$\mathrm{The}\:\mathrm{given}\:\mathrm{inequality}\:\mathrm{is}\:\mathrm{equivalent}\:\mathrm{to} \\…
Question Number 32524 by Bindugirish107@gmail.com last updated on 27/Mar/18 $$\frac{\mathrm{1}}{\mathrm{2}}{x}^{\mathrm{2}} +\sqrt{\mathrm{2}}= \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com