Question Number 169713 by mathlove last updated on 06/May/22 Commented by Shrinava last updated on 06/May/22 $$\mathrm{E}\:=\:\mathrm{2018} \\ $$ Commented by mathlove last updated on…
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Question Number 38636 by pieroo last updated on 27/Jun/18 $$\mathrm{Three}\:\mathrm{variables}\:\mathrm{u},\mathrm{v}\:\mathrm{and}\:\mathrm{w}\:\mathrm{are}\:\mathrm{related}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{u}\:\mathrm{varies}\:\mathrm{directly}\:\mathrm{as}\:\mathrm{v}\:\mathrm{and}\:\mathrm{inversely}\:\mathrm{as}\:\mathrm{the}\:\mathrm{square}\:\mathrm{of}\: \\ $$$$\mathrm{w}.\:\mathrm{If}\:\mathrm{v}\:\mathrm{increases}\:\mathrm{by}\:\mathrm{15\%}\:\mathrm{and}\:\mathrm{w}\:\mathrm{decreased}\:\mathrm{by}\:\mathrm{10\%}, \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{percentage}\:\mathrm{change}\:\mathrm{in}\:\mathrm{u}. \\ $$ Answered by MrW3 last updated on 28/Jun/18…
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Question Number 38587 by tawa tawa last updated on 27/Jun/18 $$\mathrm{solve}\:\mathrm{for}\:\mathrm{x}:\:\:\:\:\:\mathrm{e}^{\mathrm{x}} \:+\:\mathrm{e}^{\mathrm{x}^{\mathrm{2}} } \:+\:\mathrm{e}^{\mathrm{x}^{\mathrm{3}} } \:=\:\:\mathrm{3}\:+\:\mathrm{x}\:+\:\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{x}^{\mathrm{3}} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on…
Question Number 169653 by infinityaction last updated on 05/May/22 $$ \\ $$$$\:\:\:{solve}\:{for}\:{x} \\ $$$$\:\:\:\:\:\:{x}^{\mathrm{2}} \:+\:\frac{{x}^{\mathrm{2}} }{\left({x}+\mathrm{1}\right)^{\mathrm{2}} }\:\:\:=\:\:\mathrm{3} \\ $$ Answered by mr W last updated…
Question Number 169655 by Shrinava last updated on 05/May/22 Answered by mr W last updated on 07/May/22 Commented by Shrinava last updated on 07/May/22 $$\mathrm{Professor},\:\mathrm{the}\:\mathrm{picture}\:\mathrm{is}\:\mathrm{perfect}…
Question Number 169650 by mnjuly1970 last updated on 05/May/22 $$ \\ $$$$\:\:\:\:\:\:\:{f}\left({x}\right)=\:\mathrm{3}\mid\:{sin}\left({x}\right)\mid\:−\mathrm{4}\mid{cos}\left({x}\right)\mid \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:{R}_{\:{f}} \:=? \\ $$ Commented by mkam last updated on…
Question Number 104115 by bobhans last updated on 19/Jul/20 Answered by nimnim last updated on 19/Jul/20 $$\frac{{xy}}{{x}+{y}}={a},\:\frac{{xz}}{{x}+{z}}={b},\:\frac{{yz}}{{y}+{z}}={c} \\ $$$$\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{y}}=\frac{\mathrm{1}}{{a}},\:\:\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{z}}=\frac{\mathrm{1}}{{b}},\:\:\frac{\mathrm{1}}{{y}}+\frac{\mathrm{1}}{{z}}=\frac{\mathrm{1}}{{c}} \\ $$$$\mathrm{2}\left(\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{y}}+\frac{\mathrm{1}}{{z}}\right)=\frac{\mathrm{1}}{{a}}+\frac{\mathrm{1}}{{b}}+\frac{\mathrm{1}}{{c}}=\frac{{bc}+{ac}+{ab}}{{abc}} \\ $$$$\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{c}}=\frac{{bc}+{ac}+{ab}}{\mathrm{2}{abc}} \\ $$$$\frac{\mathrm{1}}{{x}}=\frac{{bc}+{ac}+{ab}}{\mathrm{2}{abc}}−\frac{\mathrm{1}}{{c}}…
Question Number 38570 by Sr@2004 last updated on 27/Jun/18 Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jun/18 $${pls}\:{post}\:{question}\:{clearly}…{bhalo}\:{kore}\:{photo}\:{tolo} \\ $$$${tar}\:{por}\:{post}\:{karo}…{bangla}\:{language}\:{hole}\:{adubidha} \\ $$$${nai} \\ $$ Commented by…