Question Number 163099 by HongKing last updated on 03/Jan/22 $$\mathrm{1}.\:\mathrm{u}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{x}}} \:=\:\boldsymbol{\mathrm{x}}\:+\:\boldsymbol{\mathrm{y}} \\ $$$$\mathrm{2}.\:\boldsymbol{\mathrm{u}}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{y}}} \:=\:\boldsymbol{\mathrm{x}}\:-\:\boldsymbol{\mathrm{y}} \\ $$ Answered by mr W last updated on 04/Jan/22 $$\left.\mathrm{1}\right)…
Question Number 163098 by amin96 last updated on 03/Jan/22 Answered by Rasheed.Sindhi last updated on 03/Jan/22 $${f}\left({x}+{y}\right)={f}\left({x}\right)×{f}\left({y}\right)\:,\:{f}^{\:'} \left(\mathrm{0}\right)=\mathrm{2} \\ $$$${f}\:'\left({x}\right)=? \\ $$$$\: \\ $$$${f}\left({x}+{y}\right)={f}\left({x}\right)×{f}\left({y}\right) \\…
Question Number 163082 by HongKing last updated on 03/Jan/22 $$\mathrm{1}.\:\mathrm{u}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{x}}} \:-\:\mathrm{2u}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{y}}} \:+\:\mathrm{3u}_{\boldsymbol{\mathrm{y}}\:\boldsymbol{\mathrm{y}}} \:-\:\mathrm{u}_{\boldsymbol{\mathrm{x}}} \:=\:\mathrm{0} \\ $$$$\mathrm{2}.\:\mathrm{xu}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{x}}} \:+\:\mathrm{2xu}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{y}}} \:+\:\mathrm{3u}_{\boldsymbol{\mathrm{y}}\:\boldsymbol{\mathrm{y}}} \:+\:\mathrm{u}_{\boldsymbol{\mathrm{y}}} \:=\:\mathrm{0} \\ $$ Commented by mahdipoor…
Question Number 32002 by rahul 19 last updated on 18/Mar/18 $${If}\:\:\boldsymbol{{z}}^{\mathrm{3}} =\bar {\boldsymbol{{z}}}\:{prove}\: \\ $$$${then}\:\mid\boldsymbol{{z}}\mid=\mathrm{1}. \\ $$ Answered by Tinkutara last updated on 18/Mar/18 $${z}^{\mathrm{3}}…
Question Number 163075 by tounghoungko last updated on 03/Jan/22 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{{x}^{\mathrm{3}} +\mathrm{1}}{{x}^{\mathrm{2}} −\mathrm{1}}\:=\:{x}+\sqrt{\frac{\mathrm{6}}{{x}}} \\ $$ Answered by Rasheed.Sindhi last updated on 03/Jan/22 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{{x}^{\mathrm{3}} +\mathrm{1}}{{x}^{\mathrm{2}} −\mathrm{1}}\:=\:{x}+\sqrt{\frac{\mathrm{6}}{{x}}} \\…
Question Number 31991 by gunawan last updated on 17/Mar/18 $${g}_{{n}} =\sqrt{{g}_{{n}−\mathrm{1}} +{g}_{{n}−\mathrm{2}} } \\ $$$${g}_{\mathrm{1}} =\mathrm{1} \\ $$$${g}_{\mathrm{2}} =\mathrm{3} \\ $$$${g}_{{n}} =.. \\ $$ Commented…
Question Number 31990 by gunawan last updated on 17/Mar/18 $${a}_{{n}} =\mathrm{2}{a}_{{n}−\mathrm{1}} +\mathrm{3}{a}_{{n}−\mathrm{2}} \\ $$$${a}_{\mathrm{0}} =\mathrm{1} \\ $$$${a}_{\mathrm{1}} =\mathrm{2} \\ $$$${a}_{{n}} =… \\ $$ Commented by…
Question Number 163048 by mnjuly1970 last updated on 03/Jan/22 Answered by mahdipoor last updated on 03/Jan/22 $${sin}^{\mathrm{2}} {x}={m}\:\:\:{cos}^{\mathrm{2}} {x}={n} \\ $$$$\Rightarrow{m}^{'} =−{n}^{'} =\mathrm{2}{cosx}.{sinx} \\ $$$$\:{f}\:'=\left({nm}^{\mathrm{3}}…
Question Number 97512 by bemath last updated on 08/Jun/20 $$\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:\mathrm{k}\:\mathrm{for}\:\mathrm{which}\:\mathrm{the} \\ $$$$\mathrm{quadratic}\:\mathrm{equation}\:\left(\mathrm{1}−\mathrm{2k}\right)\mathrm{x}^{\mathrm{2}} −\mathrm{6kx}−\mathrm{1}=\mathrm{0} \\ $$$$\mathrm{and}\:\mathrm{kx}^{\mathrm{2}} −\mathrm{x}+\mathrm{1}=\mathrm{0}\:\mathrm{have}\:\mathrm{atleast} \\ $$$$\mathrm{one}\:\mathrm{roots}\:\mathrm{in}\:\mathrm{common}\:\mathrm{are}\:\_\_\_ \\ $$ Commented by john santu last…
Question Number 97501 by bemath last updated on 08/Jun/20 $$\mathrm{The}\:\mathrm{natural}\:\mathrm{number}\:\mathrm{n}\:\mathrm{for}\:\mathrm{which}\: \\ $$$$\mathrm{the}\:\mathrm{expression}\:\mathrm{y}\:=\:\mathrm{5log}^{\mathrm{2}} \:_{\mathrm{3}} \left(\mathrm{n}\right)\:− \\ $$$$\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{n}^{\mathrm{12}} \right)+\mathrm{9}\:,\:\mathrm{has}\:\mathrm{the}\:\mathrm{minimum} \\ $$$$\mathrm{value}\:\mathrm{is}\:\_\_\_ \\ $$ Commented by bobhans…