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Category: Algebra

Question-99430

Question Number 99430 by I want to learn more last updated on 20/Jun/20 Answered by mr W last updated on 20/Jun/20 $${f}\left({x}\right)={x}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{6}}{x}^{\mathrm{2}} −\frac{\mathrm{44}}{\mathrm{9}}{x}−\frac{\mathrm{40}}{\mathrm{9}}=\mathrm{0} \