Menu Close

Category: Algebra

Question-99430

Question Number 99430 by I want to learn more last updated on 20/Jun/20 Answered by mr W last updated on 20/Jun/20 $${f}\left({x}\right)={x}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{6}}{x}^{\mathrm{2}} −\frac{\mathrm{44}}{\mathrm{9}}{x}−\frac{\mathrm{40}}{\mathrm{9}}=\mathrm{0} \

Given-positive-numbers-a-b-c-d-Prove-that-a-3-b-3-c-3-a-b-c-b-3-c-3-d-3-b-c-d-c-3-d-3-a-3-c-d-a-d-3-a-3-b-3-d-a-b-

Question Number 164926 by Zaynal last updated on 23/Jan/22 Givenpositivenumbersa,b,c,dProvethat;$$\:\:\:\:\:\:\:\:\lfloor\frac{\boldsymbol{{a}}^{\mathrm{3}} +\boldsymbol{{b}}^{\mathrm{3}} +\boldsymbol{{c}}^{\mathrm{3}} }{\boldsymbol{{a}}+\boldsymbol{{b}}+\boldsymbol{{c}}}\:+\:\frac{\boldsymbol{{b}}^{\mathrm{3}} +\boldsymbol{{c}}^{\mathrm{3}} +\boldsymbol{{d}}^{\mathrm{3}} }{\boldsymbol{{b}}+\boldsymbol{{c}}+\boldsymbol{{d}}}\:+\:\frac{\boldsymbol{{c}}^{\mathrm{3}} +\boldsymbol{{d}}^{\mathrm{3}} +\boldsymbol{{a}}^{\mathrm{3}} }{\boldsymbol{{c}}+\boldsymbol{{d}}+\boldsymbol{{a}}}\:+\:\frac{\boldsymbol{{d}}^{\mathrm{3}} +\boldsymbol{{a}}^{\mathrm{3}} +\boldsymbol{{b}}^{\mathrm{3}}…