Question Number 167664 by Ari last updated on 22/Mar/22 $${a}=\mathrm{3}{k},{b}=\mathrm{4}{k},{c}=\mathrm{5}{k} \\ $$$$\mathrm{3}{k}+\mathrm{4}{k}+\mathrm{5}{k}=\mathrm{1000}\Rightarrow{k}=\mathrm{500}/\mathrm{6} \\ $$$${a}=\mathrm{1500}/\mathrm{6},{b}=\mathrm{200}/\mathrm{6},{c}=\mathrm{2500}/\mathrm{6} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 167648 by mathlove last updated on 22/Mar/22 $$\mathrm{log}_{{sinx}} \mathrm{2}+\mathrm{log}_{{cosx}} \mathrm{2}+{log}_{\mathrm{sin}\:{x}} \mathrm{2}×{log}_{\mathrm{cos}\:{x}} \mathrm{2}=\mathrm{0} \\ $$$${x}=? \\ $$ Commented by Rasheed.Sindhi last updated on 22/Mar/22…
Question Number 102109 by Jamshidbek2311 last updated on 06/Jul/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 167627 by HongKing last updated on 21/Mar/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 102078 by Jamshidbek2311 last updated on 06/Jul/20 Answered by mr W last updated on 06/Jul/20 $$\boldsymbol{{METHOD}}\:\boldsymbol{{I}} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} \:{is}\:{the}\:{square}\:{of}\:{the}\:{distance} \\ $$$${from}\:{point}\:\left({x},{y}\right)\:{to}\:{the}\:{origin}\:\left(\mathrm{0},\mathrm{0}\right). \\…
Question Number 167612 by infinityaction last updated on 20/Mar/22 Commented by Rasheed.Sindhi last updated on 21/Mar/22 $$\mathcal{D}{etermine}\:{all}\:{the}\:{possible}\:{triples} \\ $$$$\left({a},{b},{c}\right)\:{of}\:{positive}\:{integers}\:{for}\:{which} \\ $$$${ab}−{c},{bc}−{a}\:{and}\:{ca}−{b}\:{are}\:{powers}\:{of} \\ $$$$\mathrm{2}. \\ $$…
Question Number 167601 by HongKing last updated on 20/Mar/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 167566 by infinityaction last updated on 19/Mar/22 Answered by MJS_new last updated on 19/Mar/22 $${x}={u}−{v}\wedge{y}={u}+{v} \\ $$$${z}=\mathrm{1}−\mathrm{2}{u} \\ $$$${z}^{\mathrm{2}} =\mathrm{1}−\mathrm{2}\left({u}^{\mathrm{2}} +{v}^{\mathrm{2}} \right) \\…
Question Number 167550 by mathlove last updated on 19/Mar/22 Answered by MJS_new last updated on 19/Mar/22 $$\mathrm{pythagorean}\:\mathrm{triple}\:\mathrm{5}^{\mathrm{2}} +\mathrm{12}^{\mathrm{2}} =\mathrm{13}^{\mathrm{2}} \\ $$$$\Rightarrow\:{x}=\mathrm{4} \\ $$ Answered by…
Question Number 102002 by Jamshidbek2311 last updated on 06/Jul/20 Commented by mr W last updated on 06/Jul/20 $${please}\:{don}'{t}\:{post}\:{the}\:{same}\:{question} \\ $$$${again}\:{and}\:{again}.\:{if}\:{you}\:{have}\:{doubt}, \\ $$$${give}\:{comment}\:{in}\:{the}\:{old}\:{thread},\:{don}'{t} \\ $$$${open}\:{a}\:{new}\:{thread}. \\…