Question Number 30594 by abdo imad last updated on 23/Feb/18 $${let}\:{p}\left({x}\right)={x}^{\mathrm{3}} \:+\mathrm{1}\:{and}\:{q}\left({x}\right)={x}^{\mathrm{4}} \:+\mathrm{1}\:{prove}\:{that} \\ $$$${D}\left({p},{q}\right)=\mathrm{1}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 96131 by bemath last updated on 30/May/20 $$\sqrt[{\mathrm{3}\:\:}]{\left({x}+\mathrm{4}\right)^{\mathrm{2}} }\:+\:\mathrm{4}\:\sqrt[{\mathrm{3}\:\:}]{\left({x}−\mathrm{3}\right)^{\mathrm{2}} }\:+\:\mathrm{5}\:\sqrt[{\mathrm{3}\:\:}]{{x}^{\mathrm{2}} +{x}−\mathrm{12}}\:=\:\mathrm{0} \\ $$ Answered by john santu last updated on 30/May/20 $$\mathrm{let}\:\sqrt[{\mathrm{3}\:\:}]{{x}+\mathrm{4}}\:=\:{u}\:\&\:\sqrt[{\mathrm{3}\:\:}]{{x}−\mathrm{3}}\:=\:{v}\: \\…
Question Number 30593 by abdo imad last updated on 23/Feb/18 $${factorize}\:{inside}\:{C}\left[{x}\right]\:{p}\left({x}\right)=\left(\mathrm{1}+{i}\frac{{x}}{{n}}\right)^{{n}} \:−\left(\mathrm{1}−{i}\frac{{x}}{{n}}\right)^{{n}} . \\ $$ Answered by sma3l2996 last updated on 23/Feb/18 $${p}\left({x}\right)=\left(\mathrm{1}+{ix}/{n}\right)^{{n}} −\left(\mathrm{1}−{ix}/{n}\right)^{{n}} \\…
Question Number 30592 by abdo imad last updated on 23/Feb/18 $${let}\:{p}\left({x}\right)={x}^{\mathrm{2}{n}} \:−\mathrm{2}{cos}\alpha\:{x}^{{n}} \:+\mathrm{1} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{roots}\:{lf}\:{p}\left({x}\right) \\ $$$$\left.\mathrm{2}\right){factorize}\:{p}\left({x}\right)\:{inside}\:{C}\left[{x}\right] \\ $$$$\left.\mathrm{3}\right){factorize}\:{p}\left({x}\right)\:{inside}\:{R}\left[{x}\right]. \\ $$ Answered by sma3l2996 last…
Question Number 161666 by mathlove last updated on 21/Dec/21 $${if}\:\:\frac{{g}\left(\mathrm{5}\right){f}\left(\mathrm{5}\right)}{{g}\left(\mathrm{5}\right)+{f}\left(\mathrm{5}\right)}=\mathrm{1}\:\:\:{then}\frac{{f}\left(\mathrm{4}\right)+{g}\left(\mathrm{4}\right)}{{f}\left(\mathrm{4}\right)+\mathrm{1}}=? \\ $$$${when}\:{is}\:\:\:\:\:{Gis}\:{a}\:{I}\:{function}\:\:{and}\:{F}\:{is}\:{a}\:{constant} \\ $$ Commented by mr W last updated on 21/Dec/21 $${the}\:{language}\:{is}\:{not}\:{clear}. \\ $$$${what}\:{are}\:{G}\:{and}\:{F}?…
Question Number 30589 by abdo imad last updated on 23/Feb/18 $${let}\:{U}_{{n}} =\:\left\{{z}\in{C}\:/\:{z}^{{n}} =\mathrm{1}\right\}\:\:{find} \\ $$$${S}=\:\sum_{{z}\in{U}_{{n}} } \:\:\frac{{z}}{\left({x}−{z}\right)^{\mathrm{2}} }\:\:. \\ $$ Terms of Service Privacy Policy…
Question Number 30590 by abdo imad last updated on 23/Feb/18 $${decompose}\:{sur}\:{R}\left[{x}\right]\:\:{x}^{\mathrm{2}{n}+\mathrm{1}} \:−\mathrm{1}. \\ $$ Answered by sma3l2996 last updated on 23/Feb/18 $${let}\:{P}\left({x}\right)={x}^{\mathrm{2}{n}+\mathrm{1}} −\mathrm{1} \\ $$$$\alpha_{{k}}…
Question Number 30588 by abdo imad last updated on 23/Feb/18 $$\left({n}_{{k}} \right)_{\mathrm{1}\leqslant{k}\leqslant{n}} \:{is}\:{a}\:{family}\:{of}\:{integrs}\:{numbers}\:{let}\:{put} \\ $$$${p}\left({x}\right)=\sum_{{k}=\mathrm{1}} ^{{n}} \:{x}^{{n}_{{k}} } \:\:\:{and}\:{q}\left({x}\right)=\:\sum_{{j}=\mathrm{0}} ^{{n}−\mathrm{1}} \:{x}^{{j}} \: \\ $$$${if}\:{n}_{{k}} \equiv{k}−\mathrm{1}\left[{n}\right]\:{prove}\:{that}\:{q}\:{divide}\:{p}.…
Question Number 30587 by abdo imad last updated on 23/Feb/18 $${find}\:\sum_{{k}=\mathrm{0}} ^{{n}−\mathrm{1}} \:\left(−\mathrm{1}\right)^{{k}} \:{cos}^{{n}} \left(\frac{{k}\pi}{{n}}\right). \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 30586 by abdo imad last updated on 23/Feb/18 $${let}\:{p}=\mathrm{1}+{x}+{x}^{\mathrm{2}} \:+….+{x}^{\mathrm{2}^{{n}+\mathrm{1}} −\mathrm{1}} \:{and}\:\:{q}=\:\mathrm{1}+{x}^{\mathrm{2}^{{n}} } \\ $$$${find}\:\alpha=\:\frac{{p}}{{q}}\:. \\ $$ Terms of Service Privacy Policy Contact:…