Question Number 166431 by BagusSetyoWibowo last updated on 20/Feb/22 $$\mathrm{2}\frac{\mathrm{2}^{{x}} }{\mathrm{16},\mathrm{0}}\:=\:\mathrm{5},\mathrm{7}^{\mathrm{2}} \:−\:\mathrm{0},\mathrm{49}\:+\:\mathrm{0} \\ $$$${How}\:{much}\:{the}\:{x}\:{is}? \\ $$ Answered by alephzero last updated on 20/Feb/22 $$\mathrm{2}\frac{\mathrm{2}^{{x}} }{\mathrm{16}}\:=\:\mathrm{32}…
Question Number 35345 by jasno91 last updated on 18/May/18 $${yes}\:\sqrt{\mathrm{2}}{x}^{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 166419 by ajfour last updated on 19/Feb/22 Commented by ajfour last updated on 19/Feb/22 $${Blue}\:{curve}\:\:{y}={x}^{\mathrm{3}} −{x} \\ $$$${Red}\:{curve}\:\:\:\:{y}=\left({x}−{h}\right)−\left({x}−{h}\right)^{\mathrm{3}} +{k} \\ $$$${Find}\:{x}=\:{p}\:\:{when}\:\:{y}={c}. \\ $$…
Question Number 100879 by Tony6400 last updated on 29/Jun/20 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{2}^{\mathrm{x}} +\mathrm{8x}=\mathrm{4} \\ $$ Commented by bemath last updated on 29/Jun/20 $$\mathrm{approximation}\:\mathrm{x}\:=\:\mathrm{0}.\mathrm{342} \\ $$ Answered by…
Question Number 35336 by jasno91 last updated on 18/May/18 $$\sqrt{\mathrm{2}{x}^{\mathrm{2}} }+\mathrm{7}{x}+\mathrm{5}\sqrt{\mathrm{2}}=\mathrm{0} \\ $$ Commented by Rasheed.Sindhi last updated on 18/May/18 $$\mathrm{Is}\:\mathrm{it}\:\sqrt{\mathrm{2}}\:{x}^{\mathrm{2}} \:? \\ $$ Answered…
Question Number 35338 by jasno91 last updated on 18/May/18 $$\frac{\mathrm{14}{x}^{\mathrm{2}} +\mathrm{16}}{\mathrm{21}}−\frac{\mathrm{2}{x}^{\mathrm{2}} +\mathrm{8}}{\mathrm{8}{x}^{\mathrm{2}} −\mathrm{11}}=\frac{\mathrm{2}{x}^{\mathrm{2}} }{\mathrm{3}} \\ $$ Commented by Rasheed.Sindhi last updated on 18/May/18 $$\mathrm{Let}\:{x}^{\mathrm{2}} ={y}…
Question Number 166403 by mathls last updated on 19/Feb/22 $${fog}_{\left(\mathrm{3}\right)} =\mathrm{10} \\ $$$${f}\left(\mathrm{3}\right)=\mathrm{4} \\ $$$${g}\left({x}\right)=? \\ $$ Commented by mathls last updated on 19/Feb/22 $$?…
Question Number 166402 by mathls last updated on 19/Feb/22 $${f}\left({x}\right)={x}^{\mathrm{3}} +{x}^{\mathrm{2}} +\mathrm{13} \\ $$$${g}\left({x}\right)=\sqrt{\mathrm{5}} \\ $$$${gof}_{\left({x}\right)} =? \\ $$ Answered by alephzero last updated on…
Question Number 166398 by mathlove last updated on 19/Feb/22 $$\frac{\mathrm{1}}{{x}+\frac{\mathrm{1}}{{y}+\frac{\mathrm{1}}{{z}}}}=\frac{\mathrm{16}}{\mathrm{37}} \\ $$$${then}\:{faind}\:{volve}\:{of}\:\:\:\:{x}+{y}+{z}=? \\ $$ Answered by floor(10²Eta[1]) last updated on 19/Feb/22 $$\frac{\mathrm{16}}{\mathrm{37}}=\frac{\mathrm{1}}{\frac{\mathrm{37}}{\mathrm{16}}}=\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{5}}{\mathrm{16}}}=\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{1}}{\frac{\mathrm{16}}{\mathrm{5}}}}=\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{1}}{\mathrm{3}+\frac{\mathrm{1}}{\mathrm{5}}}} \\ $$$$\mathrm{x}+\mathrm{y}+\mathrm{z}=\mathrm{10} \\…
Question Number 166391 by mnjuly1970 last updated on 19/Feb/22 $$ \\ $$$$\:\:{solve}\:{in}\:\:\mathbb{R} \\ $$$$\:\:\:\sqrt{{x}.\lfloor{x}\rfloor}\:−\:\sqrt{\lfloor{x}\rfloor}\:=\:\mathrm{1} \\ $$$$\:\:−−−−−−− \\ $$ Answered by mr W last updated on…