Question Number 166372 by mathlove last updated on 19/Feb/22 Answered by MJS_new last updated on 19/Feb/22 $$\mathrm{Yes}\:\mathrm{I}\:\mathrm{can}. \\ $$ Commented by mr W last updated…
Question Number 35291 by 123 45 polytechnicien last updated on 17/May/18 $${solve}\:\:{in}\:{Z}\:\:{x}^{\mathrm{3}} +\mathrm{6}{y}^{\mathrm{3}} =\mathrm{4}{z}^{\mathrm{3}} \\ $$ Commented by 123 45 polytechnicien last updated on 17/May/18…
Question Number 100815 by john santu last updated on 28/Jun/20 Answered by mr W last updated on 28/Jun/20 $${see}\:{Q}\mathrm{47657} \\ $$$$ \\ $$$$\delta=\left(\mathrm{2}+\mathrm{3}+\sqrt{\mathrm{7}}\right)\left(−\mathrm{2}+\mathrm{3}+\sqrt{\mathrm{7}}\right)\left(\mathrm{2}−\mathrm{3}+\sqrt{\mathrm{7}}\right)\left(\mathrm{2}+\mathrm{3}−\sqrt{\mathrm{7}}\right) \\ $$$$=\mathrm{108}…
Question Number 100806 by I want to learn more last updated on 28/Jun/20 Commented by I want to learn more last updated on 28/Jun/20 $$\mathrm{33}\:\:\mathrm{sir}.…
Question Number 100793 by bramlex last updated on 28/Jun/20 Commented by bobhans last updated on 28/Jun/20 $$\mathrm{The}\:\mathrm{perimeter}\:\mathrm{of}\:\mathrm{isosceles}\:\Delta\mathrm{MBC}\:=\:\mathrm{5}+\mathrm{5}+\mathrm{6}\:=\:\mathrm{16}\: \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 100792 by bramlex last updated on 28/Jun/20 Answered by bobhans last updated on 28/Jun/20 $$\frac{{x}+{xy}}{{y}}\:=\:\frac{{y}+{xy}}{{x}}\:\Rightarrow\:{x}^{\mathrm{2}} +{x}^{\mathrm{2}} {y}\:=\:{y}^{\mathrm{2}} +{xy}^{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} −{y}^{\mathrm{2}} \:=\:{xy}^{\mathrm{2}} −{x}^{\mathrm{2}}…
Question Number 35256 by bivekverma last updated on 17/May/18 $$\mathrm{Factorize}\::\mathrm{x}^{\mathrm{5}} −\mathrm{y}^{\mathrm{5}} \\ $$ Commented by abdo mathsup 649 cc last updated on 18/May/18 $${let}\:{factorize}\:{x}^{{n}} \:−{y}^{{n}}…
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Question Number 166273 by MikeH last updated on 17/Feb/22 Commented by MikeH last updated on 17/Feb/22 $$\mathrm{The}\:\mathrm{figure}\:\mathrm{above}\:\mathrm{is}\:\mathrm{a}\:\mathrm{circumcircle} \\ $$$$\mathrm{ABC}\:\mathrm{with}\:\mathrm{centre}\:\mathrm{O}\:\mathrm{and}\:\mathrm{angle}\: \\ $$$$\mathrm{AOB}\:=\:\mathrm{50}°.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{angles} \\ $$$$\mathrm{marked}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}. \\ $$…
Question Number 100730 by john santu last updated on 28/Jun/20 $$\frac{\mathrm{2}{z}^{\mathrm{2}} }{{z}^{\mathrm{2}} +\mid{z}+\mathrm{1}\mid}\:<\:\mathrm{1}\: \\ $$ Commented by bemath last updated on 28/Jun/20 $$\mathrm{since}\:\mathrm{z}^{\mathrm{2}} +\mid\mathrm{z}+\mathrm{1}\mid\:>\:\mathrm{0}\:\mathrm{then}\:\mathrm{2z}^{\mathrm{2}} \:<\:\mathrm{z}^{\mathrm{2}}…