Question Number 161484 by bobhans last updated on 18/Dec/21 $$\:\:\begin{cases}{\frac{\mathrm{1}}{\mathrm{a}}+\frac{\mathrm{1}}{\mathrm{b}}=\mathrm{9}}\\{\left(\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{a}}}+\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{b}}}\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{a}}}\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{b}}}\right)=\mathrm{18}}\end{cases} \\ $$$$\:\:\:\mathrm{8a}+\mathrm{4b}=? \\ $$ Answered by mr W last updated on 18/Dec/21 $${let}\:{A}=\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{{a}}},\:{B}=\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{{b}}} \\ $$$${let}\:{p}={A}+{B},\:{q}={AB}…
Question Number 30405 by scientist last updated on 22/Feb/18 $${x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{13} \\ $$$${x}^{\mathrm{2}} −\mathrm{3}{xy}+{y}^{\mathrm{2}} =\mathrm{35} \\ $$$${find}\:{the}\:{value}\:{of}\:{x}\:{and}\:{y} \\ $$ Answered by mrW2 last updated…
Question Number 30401 by amit96 last updated on 22/Feb/18 $${is}\:{there}\:{exists}\:{a}\:{onto}\:{group}\:{homo}\:{from}\:{D}\mathrm{4}\:{to}\:{Z}\mathrm{4}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 161456 by mnjuly1970 last updated on 18/Dec/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 95919 by Abdulrahman last updated on 28/May/20 $$ \\ $$$$\int\mathrm{3}^{−\mathrm{4x}^{\mathrm{2}} } \mathrm{dx}=?\:\:\:\:\left(\mathrm{0},\infty\right) \\ $$ Answered by mathmax by abdo last updated on 28/May/20…
Question Number 95920 by bobhans last updated on 28/May/20 $$\sqrt[{\mathrm{3}\:\:}]{\mathrm{54}+\sqrt{\mathrm{x}}}\:+\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{54}−\sqrt{\mathrm{x}}}\:=\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{18}}\: \\ $$$$\mathrm{x}\:=\:?\: \\ $$ Answered by i jagooll last updated on 28/May/20 $$\mathrm{let}\:\mathrm{a}\:=\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{54}+\sqrt{\mathrm{x}}}\:,\:\mathrm{b}\:=\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{54}−\sqrt{\mathrm{x}}}\: \\ $$$$\mathrm{a}+\mathrm{b}\:=\:\frac{\mathrm{a}^{\mathrm{3}}…
Question Number 95898 by rb222 last updated on 28/May/20 $${x}^{\mathrm{2}} +{xy}+\frac{{y}^{\mathrm{3}} }{\mathrm{3}}=\mathrm{25} \\ $$$$\frac{{y}^{\mathrm{2}} }{\mathrm{3}}+{z}^{\mathrm{2}} =\mathrm{9} \\ $$$${z}^{\mathrm{2}} +{zx}+{x}^{\mathrm{2}} =\mathrm{16} \\ $$$${so}\:{xy}+\mathrm{2}{yz}+\mathrm{3}{zx}=? \\ $$ Terms…
Question Number 161433 by HongKing last updated on 17/Dec/21 $$\mathrm{if}\:\:\mathrm{x};\mathrm{y};\mathrm{z}>\mathrm{0}\:\:\mathrm{such}\:\mathrm{that}\:\:\mathrm{x}+\mathrm{y}+\mathrm{z}=\mathrm{3} \\ $$$$\mathrm{and}\:\:\boldsymbol{\lambda}\geqslant\mathrm{0}\:\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}: \\ $$$$\frac{\mathrm{x}}{\mathrm{y}^{\mathrm{3}} +\lambda\mathrm{y}^{\mathrm{2}} }\:+\:\frac{\mathrm{y}}{\mathrm{z}^{\mathrm{3}} +\lambda\mathrm{z}^{\mathrm{2}} }\:+\:\frac{\mathrm{z}}{\mathrm{x}^{\mathrm{3}} +\lambda\mathrm{x}^{\mathrm{2}} }\:\geqslant\:\frac{\mathrm{3}}{\lambda+\mathrm{1}} \\ $$ Terms of Service…
Question Number 161418 by geron last updated on 17/Dec/21 $$\mathrm{4}^{\mathrm{2021}\:} ={a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} ,\:\left({a}:{b}:{c}\right)\Rightarrow\:{natural}\:{numbers} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 161416 by mathlove last updated on 17/Dec/21 Terms of Service Privacy Policy Contact: info@tinkutara.com