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Question Number 163288 by HongKing last updated on 05/Jan/22 Answered by Ar Brandon last updated on 05/Jan/22 $${I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{{dx}}{\mathrm{1}+{a}^{\mathrm{2}} \mathrm{tan}^{\mathrm{2}} {x}}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{\mathrm{sec}^{\mathrm{2}} {x}}{\mathrm{sec}^{\mathrm{2}}…
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