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Category: Algebra

if-y-2x-5-3-x-4-then-3x-y-

Question Number 95309 by i jagooll last updated on 24/May/20 $$\mathrm{if}\:\mathrm{y}\:=\:\left[\:\mathrm{2x}+\mathrm{5}\:\right]\:=\:\mathrm{3}\left[\mathrm{x}−\mathrm{4}\right]\: \\ $$$$\mathrm{then}\:\left[\:\mathrm{3x}+\mathrm{y}\:\right]\:=\:?\: \\ $$ Answered by mr W last updated on 24/May/20 $${let}\:{u}={x}−\mathrm{4}={n}+{f}\:{with}\:\mathrm{0}\leqslant{f}<\mathrm{1} \\…

2021-2-2021-2-2021-2x-x-x-

Question Number 160832 by cortano last updated on 07/Dec/21 $$\:\sqrt{\mathrm{2021}−\mathrm{2}\sqrt{\mathrm{2021}−\mathrm{2}\sqrt{\mathrm{2021}−\mathrm{2x}}}}\:=\:\mathrm{x} \\ $$$$\:\mathrm{x}=? \\ $$ Answered by Raxreedoroid last updated on 07/Dec/21 $${x}=\sqrt{\mathrm{2021}−\mathrm{2}{x}} \\ $$$${x}^{\mathrm{2}} =\mathrm{2021}−\mathrm{2}{x}…

3-men-4-women-amp-6-boy-together-working-a-job-within-25-day-if-2-men-3-women-and-4-boy-working-the-same-job-complete-in-

Question Number 95294 by i jagooll last updated on 24/May/20 $$\mathrm{3}\:\mathrm{men},\:\mathrm{4}\:\mathrm{women}\:\&\:\mathrm{6}\:\mathrm{boy}\:\mathrm{together} \\ $$$$\mathrm{working}\:\mathrm{a}\:\mathrm{job}\:\mathrm{within}\:\mathrm{25}\:\mathrm{day}.\:\mathrm{if}\:\mathrm{2}\:\mathrm{men}\: \\ $$$$,\:\mathrm{3}\:\mathrm{women}\:\mathrm{and}\:\mathrm{4}\:\mathrm{boy}\:\mathrm{working}\:\mathrm{the}\: \\ $$$$\mathrm{same}\:\mathrm{job},\:\mathrm{complete}\:\mathrm{in}\:? \\ $$ Commented by mr W last updated…

Question-160821

Question Number 160821 by mathlove last updated on 07/Dec/21 Commented by Mathematification last updated on 07/Dec/21 $${Ln}\frac{{x}}{{Ln}\frac{{x}}{{Ln}\frac{{x}}{{Ln}\:….}}}\:\:=\:\:{e}\: \\ $$$${Ln}\frac{{x}}{{e}}\:=\:{e} \\ $$$${Ln}\left({x}\right)\:−\:{Ln}\left({e}\right)\:=\:{e}\: \\ $$$${Ln}\left({x}\right)\:=\:{e}\:+\:\mathrm{1}\: \\ $$$${x}\:=\:{e}^{{e}+\mathrm{1}\:}…

Question-95277

Question Number 95277 by bobhans last updated on 24/May/20 Commented by mr W last updated on 24/May/20 $$\frac{\mathrm{15}}{\mathrm{10}×\mathrm{10}}+\frac{\mathrm{6}}{\mathrm{12}×\mathrm{10}}=\frac{\mathrm{1}}{{x}} \\ $$$${x}=\mathrm{5}\:{days} \\ $$ Commented by bobhans…

Question-95269

Question Number 95269 by Farruxjano last updated on 24/May/20 Commented by bobhans last updated on 24/May/20 Which is the solution to this question? Commented by Farruxjano last updated on 24/May/20 $$\boldsymbol{{Sorry}}\:\boldsymbol{{I}}\:\boldsymbol{{wanted}}\:\boldsymbol{{to}}\:\boldsymbol{{send}}\:\boldsymbol{{another}}\:…