Question Number 99796 by harckinwunmy last updated on 23/Jun/20 Answered by 1549442205 last updated on 30/Jun/20 $$\mathrm{Our}\:\mathrm{problem}\:\mathrm{is}\:\mathrm{equivalent}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{the} \\ $$$$\mathrm{system}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equations}:\begin{cases}{\mathrm{y}^{\mathrm{2}} =\mathrm{4}^{\mathrm{x}} \:\left(\mathrm{1}\right)}\\{\mathrm{y}^{\mathrm{x}} =\mathrm{16}\:\left(\mathrm{2}\right)}\end{cases}\:\left(\ast\right) \\ $$$$\left(\mathrm{1}\right)\Leftrightarrow\mathrm{y}^{\mathrm{2}} =\left(\mathrm{2}^{\mathrm{x}}…
Question Number 99789 by bemath last updated on 23/Jun/20 $$\begin{cases}{\mathrm{2}^{{x}} .\mathrm{3}^{{y}} \:=\:\mathrm{6}}\\{\mathrm{3}^{{x}} .\mathrm{4}^{{y}} \:=\:\mathrm{12}}\end{cases} \\ $$ Commented by john santu last updated on 23/Jun/20 $$\begin{cases}{\mathrm{3}^{{y}−\mathrm{1}}…
Question Number 165322 by Ari last updated on 29/Jan/22 $${who}\:{can}\:{prove}\:{that}\:\mathrm{2}^{{n}} −\mathrm{1}{produces} \\ $$$${a}\:{prime}\:{number}\:{when}\:\:{n}\:\:{is}\:{a}\: \\ $$$${prime}\:{number} \\ $$ Commented by mr W last updated on 30/Jan/22…
Question Number 165309 by cortano1 last updated on 29/Jan/22 $$\:\frac{\mathrm{6}}{\mathrm{6}+\sqrt{\mathrm{6}}}\:+\:\frac{\mathrm{6}}{\mathrm{6}^{\mathrm{2}} +\sqrt{\mathrm{6}}}\:+\frac{\mathrm{6}}{\mathrm{6}^{\mathrm{3}} +\sqrt{\mathrm{6}}}\:+…+\frac{\mathrm{6}}{\mathrm{6}^{\mathrm{1000}} +\sqrt{\mathrm{6}}}\:=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 165307 by mathlove last updated on 29/Jan/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 165291 by HongKing last updated on 28/Jan/22 Answered by mahdipoor last updated on 29/Jan/22 $$\frac{{sin}\rho+{cos}\varphi}{{sin}\varphi+{cos}\rho}=\frac{{sin}\rho+{cos}\left(\mathrm{90}−\left(\theta+\rho\right)\right)}{{sin}\left(\mathrm{90}−\left(\theta+\rho\right)\right)+{cos}\rho}= \\ $$$$\frac{{sin}\rho+{sin}\left(\theta+\rho\right)}{{cos}\left(\theta+\rho\right)+{cos}\rho}=\frac{\mathrm{2}{sin}\left(\rho+\frac{\theta}{\mathrm{2}}\right){cos}\left(\frac{\theta}{\mathrm{2}}\right)}{\mathrm{2}{cos}\left(\rho+\frac{\theta}{\mathrm{2}}\right){cos}\left(\frac{\theta}{\mathrm{2}}\right)}= \\ $$$${tan}\left(\rho+\frac{\theta}{\mathrm{2}}\right)={k} \\ $$ Commented by…
Question Number 34211 by candre last updated on 02/May/18 $${let}\:{x}\:{and}\:{y}\:{such}\:{that} \\ $$$$\mathrm{2}{x}^{\mathrm{2}} +\mathrm{4}{x}−\mathrm{2}{y}=\mathrm{0} \\ $$$${y}^{\mathrm{2}} −\left({x}+\mathrm{6}\right)^{\mathrm{2}} =\mathrm{0} \\ $$$${find}\:{the}\:{possibles}\:{value}\:{of}\:{x}+{y} \\ $$ Answered by MJS last…
Question Number 34215 by abdo imad last updated on 02/May/18 $${find}\:{the}\:{polynome}\:{p}_{{n}} \:{wich}\:{verify}\:{p}_{{n}} \left(\mathrm{0}\right)=\mathrm{0}\:{and} \\ $$$$\forall\:{x}\:\in\:{R}\:\:{p}_{{n}} \left({x}\right)−{p}_{{n}} \left({x}−\mathrm{1}\right)\:={x}^{{n}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 99744 by Rio Michael last updated on 23/Jun/20 $$\mathrm{A}\:\mathrm{wire}\:\mathrm{that}\:\mathrm{is}\:\mathrm{highly}\:\mathrm{insulated}\:\mathrm{has}\:\mathrm{a}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{2}.\mathrm{1}\:\mathrm{mm}\:\mathrm{and}\:\mathrm{a}\:\mathrm{current} \\ $$$$\mathrm{of}\:\mathrm{6}\:\mathrm{Agoes}\:\mathrm{through}\:\mathrm{it}.\:\mathrm{The}\:\mathrm{material}\:\mathrm{used}\:\mathrm{in}\:\mathrm{insulation}\:\mathrm{has}\:\mathrm{thickness} \\ $$$$\mathrm{of}\:\mathrm{2}.\mathrm{1}\:\mathrm{mm}\:\mathrm{with}\:\mathrm{a}\:\mathrm{thermal}\:\mathrm{conductivity}\:\mathrm{of}\:\mathrm{0}.\mathrm{2}\:\mathrm{W}/\mathrm{Km}.\:\mathrm{the}\:\mathrm{material}\:\mathrm{used} \\ $$$$\mathrm{in}\:\mathrm{constructing}\:\mathrm{the}\:\mathrm{wire}\:\mathrm{has}\:\mathrm{a}\:\mathrm{resistivity}\:\mathrm{of}\:\mathrm{4}.\mathrm{2}\:×\:\mathrm{10}^{−\mathrm{7}} \Omega\mathrm{m}.\:\mathrm{assume}\:\mathrm{the}\: \\ $$$$\mathrm{the}\:\mathrm{materials}\:\mathrm{reach}\:\mathrm{steady}\:\mathrm{state}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{difference}\:\mathrm{in}\:\mathrm{temperature} \\ $$$$\mathrm{between}\:\mathrm{the}\:\mathrm{outer}\:\mathrm{suface}\:\mathrm{and}\:\mathrm{inner}\:\mathrm{surface}. \\ $$ Answered…
Question Number 99737 by bemath last updated on 23/Jun/20 $$\frac{\mathrm{3}−\mathrm{9x}^{\mathrm{2}} }{\mathrm{5}−\mathrm{25x}^{\mathrm{2}} }\:=\:\frac{\mathrm{5}−\mathrm{125x}^{\mathrm{3}} }{\mathrm{1}−\mathrm{x}^{\mathrm{2}} } \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com