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Category: Algebra

Question-162946

Question Number 162946 by HongKing last updated on 02/Jan/22 Answered by ajfour last updated on 02/Jan/22 $$\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \right)^{\mathrm{2}} ={x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} +\mathrm{2}\left({x}^{\mathrm{2}} {y}^{\mathrm{2}}…