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Category: Algebra

Question-94868

Question Number 94868 by O Predador last updated on 21/May/20 Commented by john santu last updated on 21/May/20 $$\mathrm{n}^{\mathrm{2}} \:=\:\mathrm{2}^{\mathrm{2n}} \:\Rightarrow\:\mathrm{n}\:=\:\mathrm{2}^{\mathrm{n}} \: \\ $$$$\mathrm{ln}\left(\mathrm{n}\right)\:=\:\mathrm{n}\:\mathrm{ln}\left(\mathrm{2}\right)\: \\…

Find-0-log-x-1-x-3-1-dx-

Question Number 160398 by HongKing last updated on 29/Nov/21 $$\mathrm{Find}: \\ $$$$\boldsymbol{\Omega}\:=\underset{\:\mathrm{0}} {\overset{\:\infty} {\int}}\:\frac{\mathrm{log}\left(\mathrm{x}\:+\:\mathrm{1}\right)}{\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{1}}\:\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-160391

Question Number 160391 by akolade last updated on 29/Nov/21 Answered by FongXD last updated on 29/Nov/21 $$\bullet\:\left(\mathrm{x}^{\mathrm{x}} \right)'=\left(\mathrm{e}^{\mathrm{xlnx}} \right)'=\mathrm{e}^{\mathrm{xlnx}} \left(\mathrm{lnx}+\mathrm{1}\right)=\mathrm{x}^{\mathrm{x}} \left(\mathrm{lnx}+\mathrm{1}\right) \\ $$$$\bullet\:\left(\mathrm{x}^{\mathrm{x}^{\mathrm{x}} } \right)'=\left(\mathrm{e}^{\mathrm{x}^{\mathrm{x}}…

Compare-it-1-sin-10-cos-10-and-1-

Question Number 160373 by HongKing last updated on 28/Nov/21 $$\mathrm{Compare}\:\mathrm{it}: \\ $$$$\frac{\mathrm{1}\:-\:\mathrm{sin}\:\left(\mathrm{10}°\right)}{\mathrm{cos}\:\left(\mathrm{10}°\right)}\:\:\:\:\:\mathrm{and}\:\:\:\:\:\mathrm{1} \\ $$ Answered by ghimisi last updated on 28/Nov/21 $$\frac{{sin}\mathrm{90}−{sin}\mathrm{10}}{{cos}\mathrm{10}}=\frac{\mathrm{2}{sin}\mathrm{40}{cos}\mathrm{50}}{{sin}\mathrm{80}}= \\ $$$$\frac{\mathrm{2}{sin}\mathrm{40}{sin}\mathrm{40}}{\mathrm{2}{sin}\mathrm{40}{cos}\mathrm{40}}={tg}\mathrm{40}<{tg}\mathrm{45}=\mathrm{1} \\…

proof-or-disproof-that-if-a-quotient-group-G-H-is-abelian-then-G-must-be-abelian-

Question Number 94835 by Jidda28 last updated on 21/May/20 $$\mathrm{proof}\:\mathrm{or}\:\mathrm{disproof}\:\mathrm{that}\:\mathrm{if}\:\mathrm{a}\:\mathrm{quotient} \\ $$$$\mathrm{group}\:\frac{\mathrm{G}}{\mathrm{H}}\:\mathrm{is}\:\mathrm{abelian}\:\mathrm{then}\:\mathrm{G}\:\mathrm{must}\:\mathrm{be}\:\mathrm{abelian}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

find-such-a-polynomial-if-is-divided-by-x-2-then-the-remainder-is-5-if-it-isdivided-by-x-3-the-remainder-is-9-if-it-is-divided-by-x-4-the-remainder-is-13-if-divide-by-x-10-and-the-remaid

Question Number 94818 by student work last updated on 21/May/20 $$\:\mathrm{find}\:\mathrm{such}\:\mathrm{a}\:\mathrm{polynomial}\:\mathrm{if}\:\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{2}\right)\:\mathrm{then}\:\mathrm{the}\: \\ $$$$\mathrm{remainder}\:\mathrm{is}\:\mathrm{5},\:\mathrm{if}\:\mathrm{it}\:\mathrm{isdivided}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{3}\right)\:\mathrm{the}\:\mathrm{remainder} \\ $$$$\mathrm{is}\:\mathrm{9},\:\mathrm{if}\:\mathrm{it}\:\mathrm{is}\:\mathrm{divided}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{4}\right)\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{is}\:\mathrm{13},\:\mathrm{if}\: \\ $$$$\mathrm{divide}\:\mathrm{by}\:\left(\mathrm{x}−\mathrm{10}\right)\:\mathrm{and}\:\mathrm{the}\:\mathrm{remaider}\:\mathrm{becomes}\:\mathrm{37}\:\mathrm{and} \\ $$$$\mathrm{if}\:\left(\mathrm{x}−\frac{\mathrm{3}}{\mathrm{4}}\right)\:\mathrm{divided}\:\mathrm{by}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{becomes}\:\mathrm{zero}? \\ $$ Commented by Rasheed.Sindhi last…

dx-x-x-2-3-

Question Number 94811 by Abdulrahman last updated on 21/May/20 $$\int\frac{\mathrm{dx}}{\mathrm{x}+\sqrt{\mathrm{x}}}\:\:\:\left(\mathrm{2},\mathrm{3}\right)=? \\ $$ Answered by ElOuafi last updated on 21/May/20 $$\int\frac{{dx}}{{x}+\sqrt{{x}}}=\int\frac{{dx}}{\:\sqrt{{x}}\left(\sqrt{{x}}+\mathrm{1}\right)}=\int\frac{\frac{\mathrm{2}}{\mathrm{2}\sqrt{{x}}}}{\:\sqrt{{x}}+\mathrm{1}}\:{dx}=\mathrm{2}\int\frac{{d}\left(\sqrt{{x}}+\mathrm{1}\right)}{\:\sqrt{{x}}+\mathrm{1}} \\ $$$${put}\:{u}=\sqrt{{x}}+\mathrm{1}\Rightarrow=\mathrm{2}\int\frac{{du}}{{u}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{2}{ln}\left(\sqrt{{x}}+\mathrm{1}\right)+{c} \\…

Question-160342

Question Number 160342 by alf123 last updated on 28/Nov/21 Answered by Rasheed.Sindhi last updated on 28/Nov/21 $$\mathrm{4}^{{x}} =\mathrm{6};\:\frac{\mathrm{8}^{{x}} +\mathrm{8}^{−{x}} }{\mathrm{4}^{{x}} +\mathrm{4}^{−{x}} }=? \\ $$$$\mathrm{8}=\mathrm{4}^{\frac{\mathrm{3}}{\mathrm{2}}} \\…