Question Number 29264 by bbbbbb last updated on 06/Feb/18 $$\mathrm{there}\:\mathrm{are}\:\mathrm{25}\:\mathrm{persons}\:\mathrm{in}\:\mathrm{a}\:\mathrm{conical}\:\mathrm{tent} \\ $$$$\mathrm{every}\:\mathrm{person}\:\mathrm{needs}\:\mathrm{an}\:\mathrm{area}\:\mathrm{of}\:\mathrm{4}\:\mathrm{sq}\:\mathrm{m}\: \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{ground}\:\mathrm{under}\:\mathrm{the}\:\mathrm{tent}.\:\mathrm{if} \\ $$$$\mathrm{height}\:\mathrm{if}\:\mathrm{the}\:\mathrm{tent}\:\mathrm{is}\:\mathrm{18m}.\mathrm{find}\:\mathrm{the}\:\mathrm{volume} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{tent}. \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 29259 by Abdul Gani last updated on 06/Feb/18 $${solve}\:{the}\:{equation} \\ $$$$\mathrm{2}{x}+\mathrm{3}{y}=\mathrm{5} \\ $$$$\mathrm{3}{x}+\mathrm{4}{y}=\mathrm{4}\: \\ $$ Answered by Joel578 last updated on 06/Feb/18 $$\mathrm{2}{x}\:+\:\mathrm{3}{y}\:=\:\mathrm{5}\:…\:\left({i}\right)…
Question Number 160327 by HongKing last updated on 27/Nov/21 $$\mathrm{y}\:=\:\mathrm{kx}\:\:;\:\:\mathrm{y}\:=\:\frac{\mathrm{k}}{\mathrm{x}}\:\:;\:\:\mathrm{x}\:=\:\mathrm{k}\:+\:\mathrm{1} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{surrounded}\:\mathrm{figure} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 94786 by MJS last updated on 21/May/20 $${x},\:{y}\:\in\mathbb{N}\backslash\left\{\mathrm{0},\:\mathrm{1}\right\}\:\wedge\:{x}\leqslant{y} \\ $$$$\mathrm{find}\:{z}\in\mathbb{N}\:\mathrm{with}\:{z}!={x}!{y}! \\ $$ Commented by hknkrc46 last updated on 21/May/20 $$\left(\mathrm{a}\right)\:\mathrm{x}!=\mathrm{y}+\mathrm{1}\:\Rightarrow\:\mathrm{z}!=\left(\mathrm{y}+\mathrm{1}\right)!\:\Rightarrow\:\mathrm{z}=\mathrm{y}+\mathrm{1}\: \\ $$$$\left(\mathrm{a}.\mathrm{1}\right)\:\mathrm{x}=\mathrm{3}\Rightarrow\mathrm{y}=\mathrm{5}\Rightarrow\mathrm{z}=\mathrm{6} \\…
Question Number 160317 by quvonnn last updated on 27/Nov/21 Commented by quvonnn last updated on 27/Nov/21 $$\boldsymbol{{x}}=? \\ $$ Answered by MathsFan last updated on…
Question Number 94780 by Abdulrahman last updated on 20/May/20 $$\mathrm{x}!\left(\mathrm{x}−\mathrm{4}\right)!=\mathrm{12}\left(\mathrm{2x}−\mathrm{7}\right)! \\ $$$$\mathrm{x}=? \\ $$ Commented by MJS last updated on 21/May/20 $${x}\geqslant\mathrm{4} \\ $$$$\mathrm{trying} \\…
Question Number 160310 by HongKing last updated on 27/Nov/21 $$\mathrm{find}\:\mathrm{the}\:\mathrm{period}\:\mathrm{of}\:\mathrm{the}\:\mathrm{function}: \\ $$$$\mathrm{y}\:=\:\mathrm{tan}\:\frac{\pi\mathrm{x}}{\mathrm{k}}\:+\:\mathrm{cos}\:\frac{\mathrm{2}\pi\mathrm{x}}{\mathrm{k}\:+\:\mathrm{5}} \\ $$ Commented by mr W last updated on 27/Nov/21 $${period}={lcm}\left({k},\:{k}+\mathrm{5}\right) \\ $$…
Question Number 160296 by mathlove last updated on 27/Nov/21 Commented by bobhans last updated on 27/Nov/21 $$\:\:\:\:\:\:\:\:\:\:\left(\mathrm{3}\right)^{\frac{\mathrm{3}}{\mathrm{x}+\mathrm{1}}} \:=\:\left(\mathrm{3}\right)^{\frac{\mathrm{2}}{\mathrm{x}}} \:\Leftrightarrow\:\mathrm{3x}=\mathrm{2x}+\mathrm{2}\:;\:\mathrm{x}=\mathrm{2} \\ $$ Answered by Rasheed.Sindhi last…
Question Number 160302 by cortano last updated on 27/Nov/21 Answered by Rasheed.Sindhi last updated on 27/Nov/21 $$\begin{cases}{\mathrm{8}{x}^{\mathrm{2}} −\mathrm{8}{y}^{\mathrm{2}} =\mathrm{24}}\\{\mathrm{3}{x}^{\mathrm{2}} +\mathrm{3}{xy}+\mathrm{6}{y}^{\mathrm{2}} =\mathrm{24}}\end{cases}\Rightarrow\mathrm{5}{x}^{\mathrm{2}} −\mathrm{3}{xy}−\mathrm{14}{y}^{\mathrm{2}} =\mathrm{0} \\ $$$$\Rightarrow\mathrm{5}{x}^{\mathrm{2}}…
Question Number 160289 by amin96 last updated on 27/Nov/21 $$\underset{{n}\geqslant\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{{n}\left(\mathrm{2}{n}+\mathrm{1}\right)^{\mathrm{2}} }=? \\ $$ Answered by qaz last updated on 27/Nov/21 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{n}\left(\mathrm{2n}+\mathrm{1}\right)^{\mathrm{2}}…