Question Number 159436 by HongKing last updated on 17/Nov/21 Commented by cortano last updated on 17/Nov/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28364 by abdo imad last updated on 24/Jan/18 $${let}\:{give}\:{F}\left({x}\right)\:=\:\frac{\mathrm{1}}{{x}^{\mathrm{2}} +\mathrm{1}}\:{prove}\:{that}\:\exists\:{P}_{{n}} \in\:{Z}_{{n}} \left[{x}\right]\:/ \\ $$$${F}^{\left({n}\right)} \left({x}\right)=\:\:\frac{{P}_{{n}} \left({x}\right)}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{{n}} }\:\:\:{find}\:{a}\:{relation}\:{of}\:{recurence}\:{between}\: \\ $$$${the}\:\:{P}_{{n}} \:.{prove}\:{that}\:{all}\:{roots}\:{of}\:{P}_{{n}} \:{are}\:{reals}\:{and}\:{smples}. \\…
Question Number 28363 by abdo imad last updated on 24/Jan/18 $${simlify}\:{the}\:{sum}\:\:\:{S}=\:\sum_{{k}=\mathrm{0}} ^{{n}−\mathrm{1}} \:\:\frac{{x}+\:{e}^{{i}\mathrm{2}{k}\pi} }{{x}\:−{e}^{{i}\mathrm{2}{k}\pi} }\:\:. \\ $$ Answered by ajfour last updated on 24/Jan/18 $${S}=\frac{{n}\left({x}+\mathrm{1}\right)}{{x}−\mathrm{1}}\:.…
Question Number 159435 by HongKing last updated on 17/Nov/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 159421 by HongKing last updated on 16/Nov/21 Commented by mr W last updated on 17/Nov/21 $${the}\:{next}\:{chance}\:{is}\:{three}\:{days}\:{later}… \\ $$ Commented by Rasheed.Sindhi last updated…
Question Number 159396 by quvonnn last updated on 16/Nov/21 Answered by som(math1967) last updated on 16/Nov/21 $${area}\:{of}\:\bigtriangleup{BCE}={Area}\:{of}\:\bigtriangleup{ECF} \\ $$$$\:\:\:\:\:\:\:\:\:=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{4}×\mathrm{3}=\mathrm{6}\:{sq}.{unit} \\ $$$${CM}\:{is}\:{bisector}\:{of}\:\angle{C} \\ $$$$\:\therefore\frac{{EM}}{{MB}}\:=\frac{{EC}}{{CB}}=\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\frac{{Ar}\bigtriangleup{EMC}}{{Ar}\:\bigtriangleup{CMB}}=\frac{\mathrm{3}}{\mathrm{4}}…
Question Number 28327 by Rasheed.Sindhi last updated on 24/Jan/18 $$\mathrm{Given}\:\mathrm{that}\:\frac{{a}^{{n}+\mathrm{1}} +{b}^{{n}+\mathrm{1}} }{{a}^{{n}} +{b}^{{n}} }\:\mathrm{is}\:\mathrm{AM}\:\mathrm{between}\:{a} \\ $$$$\mathrm{and}\:{b}\:,\mathrm{where}\:{a}\neq{b}\:\wedge\:{a},{b}\neq\mathrm{0};\:\mathrm{find}\:\mathrm{out}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{n}. \\ $$ Answered by mrW2 last updated on 24/Jan/18…
Question Number 28320 by NECx last updated on 24/Jan/18 $${If}\:{the}\:{arithmetic}\:{mean}\:{of}\:{a}\:{and} \\ $$$${b}\:{is}\:\frac{{a}^{{n}+\mathrm{1}} +{b}^{{n}+\mathrm{1}} }{\mathrm{2}},\:{show}\:{that}\:{n}=\mathrm{0} \\ $$ Commented by mrW2 last updated on 24/Jan/18 $${this}\:{is}\:{not}\:{always}\:{true},\:{sir}. \\…
Question Number 159394 by azadsir last updated on 16/Nov/21 $$\mathrm{if}\:\mathrm{a}^{\mathrm{3}} −\mathrm{b}^{\mathrm{3}} =\mathrm{513},\:\mathrm{ab}=\mathrm{54} \\ $$$$\:\mathrm{than},\:\mathrm{a}−\mathrm{b}\:=\:? \\ $$ Commented by cortano last updated on 16/Nov/21 $${a}^{\mathrm{3}} −{b}^{\mathrm{3}}…