Question Number 160221 by HongKing last updated on 26/Nov/21 Commented by mr W last updated on 26/Nov/21 $${if}\:{question}\:{is}\:{right},\:{then}\:{answer}\:{is} \\ $$$${wrong}.\:{if}\:{answer}\:{is}\:{right},\:{then}\: \\ $$$${question}\:{is}\:{wrong}. \\ $$$$\Rightarrow{typo}! \\…
Question Number 29138 by mathshooter last updated on 04/Feb/18 $${Find}\:{number}\:{of}\:{polynomials}\:{p}\left({x}\right) \\ $$$${with}\:{intgral}\:{coefficients}\:{such}\:{that} \\ $$$${p}\left(\mathrm{1}\right)=\mathrm{2},\:{p}\left(\mathrm{3}\right)=\mathrm{1} \\ $$ Commented by math solver last updated on 05/Feb/18 $${is}\:{the}\:{ans}.\:{zero}\:??…
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Question Number 160188 by quvonnn last updated on 25/Nov/21 Commented by quvonnn last updated on 25/Nov/21 $$\boldsymbol{{x}}_{\mathrm{1}_{} } \centerdot\:\boldsymbol{{x}}_{\mathrm{2}} \:\centerdot\boldsymbol{{x}}_{\mathrm{3}} \centerdot\:…\centerdot\boldsymbol{{x}}_{\boldsymbol{{n}}} =\:?? \\ $$ Terms…
Question Number 160190 by HongKing last updated on 25/Nov/21 $$\mathrm{if}\:\:\:\mathrm{a}\:=\:\sqrt[{\mathrm{3}}]{\mathrm{4}}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{2}}\:+\:\mathrm{1} \\ $$$$\mathrm{find}\:\:\:\frac{\mathrm{3}}{\mathrm{a}}\:+\:\frac{\mathrm{3}}{\mathrm{a}^{\mathrm{2}} }\:+\:\frac{\mathrm{1}}{\mathrm{a}^{\mathrm{3}} }\:=\:? \\ $$ Answered by amin96 last updated on 25/Nov/21 $$\boldsymbol{\mathrm{a}}=\frac{\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}\right)^{\mathrm{3}} −\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{2}}−\mathrm{1}}=\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{2}}−\mathrm{1}}\:\:\:…
Question Number 160179 by cortano last updated on 25/Nov/21 $$\:\mathrm{5}^{\mathrm{2}\left({x}−\mathrm{2}\right)} \left(\mathrm{5}^{\mathrm{2}\left({x}−\mathrm{1}\right)} \right)^{\left({x}+\mathrm{1}\right)} \:>\:\mathrm{125}^{{x}−\mathrm{1}} \\ $$ Commented by yeti123 last updated on 25/Nov/21 $$\mathrm{5}^{\mathrm{2}\left({x}−\mathrm{2}\right)} \left(\mathrm{5}^{\mathrm{2}\left({x}−\mathrm{1}\right)} \right)^{\left({x}+\mathrm{1}\right)}…
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