Question Number 159943 by quvonnn last updated on 22/Nov/21 Answered by MJS_new last updated on 22/Nov/21 $$\mathrm{approximate} \\ $$$${x}\approx\mathrm{1}.\mathrm{93655285430} \\ $$$${y}\approx−\mathrm{1}.\mathrm{14855627122} \\ $$ Terms of…
Question Number 94406 by Power last updated on 18/May/20 Commented by Tony Lin last updated on 18/May/20 $$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{x}^{{n}} }{{n}!}={e}^{{x}} \\ $$$$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{3}^{{n}}…
Question Number 28857 by Ruchinna1 last updated on 31/Jan/18 Answered by amit96 last updated on 31/Jan/18 $$\mathrm{1}{and}\mathrm{6} \\ $$$$ \\ $$ Terms of Service Privacy…
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Question Number 159863 by HongKing last updated on 21/Nov/21 $$\mathrm{Dertermine}\:\mathrm{all}\:\mathrm{pairs}\:\left(\boldsymbol{\mathrm{x}};\boldsymbol{\mathrm{y}}\right)\:\mathrm{of}\:\mathrm{integers} \\ $$$$\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{2010x}\:-\:\mathrm{xy}\:+\:\mathrm{2012y}\:+\:\mathrm{1}\:=\:\mathrm{0} \\ $$ Answered by mr W last updated on 21/Nov/21 $$\left({x}−\mathrm{2012}\right){y}=\mathrm{1}+\mathrm{2010}{x}…
Question Number 159860 by Khalmohmmad last updated on 21/Nov/21 Commented by MJS_new last updated on 22/Nov/21 $${t}+{t}^{−\mathrm{1}} =−\mathrm{1} \\ $$$${t}^{\mathrm{2}} +{t}+\mathrm{1}=\mathrm{0}\:\Rightarrow\:\mathrm{no}\:\mathrm{real}\:\mathrm{solution} \\ $$$${t}=−\frac{\mathrm{1}}{\mathrm{2}}\pm\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\mathrm{i} \\ $$$${t}^{\mathrm{1402}}…
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Question Number 159842 by abdullah_ff last updated on 21/Nov/21 $$\mathrm{if}\:{p}−\mathrm{5}\:=\:\mathrm{2}\sqrt{\mathrm{6}}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$${p}\sqrt{{p}}−\frac{\mathrm{1}}{{p}\sqrt{{p}}}\:=\:\mathrm{22}\sqrt{\mathrm{2}} \\ $$ Commented by tounghoungko last updated on 21/Nov/21 $${false} \\ $$ Commented…
Question Number 28739 by NECx last updated on 29/Jan/18 $${if}\:{S}_{{n}} =\frac{{a}\left({r}^{{n}} −\mathrm{1}\right)}{{r}−\mathrm{1}}\: \\ $$$$ \\ $$$${make}\:{r}\:{the}\:{subject}\:{of}\:{formula} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$ Answered…