Question Number 94257 by pete last updated on 17/May/20 $$\mathrm{If}\:\mathrm{9y}^{\mathrm{2}} +\:\frac{\mathrm{1}}{\mathrm{y}^{\mathrm{2}} }\:=\mathrm{3},\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{27y}^{\mathrm{3}} \:+\:\frac{\mathrm{1}}{\mathrm{y}^{\mathrm{3}} } \\ $$ Answered by niroj last updated on 17/May/20…
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Question Number 159777 by abdullah_ff last updated on 21/Nov/21 $$\mathrm{if}\:{x}\:+\:{y}\:=\:\sqrt{\mathrm{7}}\:\mathrm{and}\:{x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:=\:\sqrt{\mathrm{35}}\:; \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{16}{xy}\left({x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \right) \\ $$ Commented by abdullah_ff last updated on 21/Nov/21…
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Question Number 28642 by nimita last updated on 28/Jan/18 $${f}\left({x}\right)=\mathrm{4}{x}−\mathrm{1}{for}\mathrm{0}<{x}<\mathrm{4}\:{find}\:{f}\left(\mathrm{0}\right)\:,{f}\left(\mathrm{1}\right) \\ $$$${f}\left(\mathrm{1}.\mathrm{2}\right),{f}\left(\mathrm{4}\right),{f}\left(−\mathrm{1}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 94174 by i jagooll last updated on 17/May/20 $$\begin{cases}{\mathrm{x}+\mathrm{y}\:=\:\mathrm{10}}\\{\sqrt[{\mathrm{3}\:\:}]{\mathrm{x}}\:+\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{y}}\:=\:\frac{\mathrm{5}}{\mathrm{2}}\:\sqrt[{\mathrm{6}\:\:}]{\mathrm{xy}}}\end{cases}\: \\ $$$$\mathrm{find}\:\mathrm{x}\:\&\mathrm{y}?? \\ $$ Commented by behi83417@gmail.com last updated on 17/May/20 $$\mathrm{x}=\mathrm{t}^{\mathrm{6}} ,\mathrm{y}=\mathrm{s}^{\mathrm{6}} \\…
Question Number 159683 by SAMIRA last updated on 20/Nov/21 $$\mathrm{2}\:\leqslant\:\mid\boldsymbol{{x}}−\mathrm{2}\mid\:\leqslant\:\mathrm{6} \\ $$ Commented by tounghoungko last updated on 20/Nov/21 $$\:\mid{x}−\mathrm{2}\mid\geqslant\mathrm{2}\:\wedge\:\mid{x}−\mathrm{2}\mid\:\leqslant\:\mathrm{6} \\ $$$$\Rightarrow\left({x}−\mathrm{2}−\mathrm{2}\right)\left({x}−\mathrm{2}+\mathrm{2}\right)\geqslant\:\mathrm{0}\:\wedge\:\left({x}−\mathrm{2}−\mathrm{6}\right)\left({x}−\mathrm{2}+\mathrm{6}\right)\leqslant\:\mathrm{0} \\ $$$$\Rightarrow\left({x}−\mathrm{4}\right){x}\:\geqslant\:\mathrm{0}\:\wedge\:\left({x}−\mathrm{8}\right)\left({x}+\mathrm{4}\right)\leqslant\:\mathrm{0} \\…
Question Number 94124 by M±th+et+s last updated on 17/May/20 $$\mathrm{20}+{a}={a}\:{cosh}\left(\frac{\mathrm{75}}{{a}}\right) \\ $$$${a}=? \\ $$ Commented by MJS last updated on 17/May/20 $$\mathrm{we}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\ $$$$\mathrm{I}\:\mathrm{get}\:{a}\approx\mathrm{143}.\mathrm{84} \\…
Question Number 159654 by HongKing last updated on 19/Nov/21 $$\mathrm{Find}:\:\:\boldsymbol{\Omega}\:=\underset{\:\mathrm{0}} {\overset{\:\infty} {\int}}\:\frac{\mathrm{x}\:\centerdot\:\mathrm{arctan}^{\mathrm{2}} \left(\mathrm{x}\right)}{\left(\mathrm{x}\:+\:\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{1}\right)}\:\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com