Question Number 93057 by gonzo last updated on 10/May/20 $${y}={b}\mathrm{1}{x}\mathrm{1}+{b}\mathrm{2}{x}\mathrm{2}+{c} \\ $$$${i}\:{need}\:{to}\:{arrange}\:{the}\:{equation}\:{for}\:{thd}\:{value}\:{of}\:{x}\mathrm{2} \\ $$ Commented by gonzo last updated on 10/May/20 $${i}\:{have}\:{discalcula}\:{and}\:{it}\:{helps}\:{me}\:{work}\:{kt}\:{through} \\ $$ Answered…
Question Number 27507 by NECx last updated on 07/Jan/18 $$\mathrm{2}\sqrt{{x}\:}+{y}=\mathrm{9}….\left(\mathrm{1}\right) \\ $$$${x}+\:\mathrm{2}\sqrt{{y}}=\mathrm{3}….\left(\mathrm{2}\right) \\ $$$$ \\ $$$${solve}\:{the}\:{simultaneous}\:{equation} \\ $$ Commented by Rasheed.Sindhi last updated on 08/Jan/18…
Question Number 27503 by Rasheed.Sindhi last updated on 07/Jan/18 $$\mathrm{If}\:\mathrm{x}=\mathrm{cy}+\mathrm{bz}\:,\mathrm{y}=\mathrm{az}+\mathrm{cx}\:\&\:\mathrm{z}=\mathrm{bx}+\mathrm{ay} \\ $$$$\mathrm{prove}\:\mathrm{that}\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{1}−\mathrm{a}^{\mathrm{2}} }=\frac{\mathrm{y}^{\mathrm{2}} }{\mathrm{1}−\mathrm{b}^{\mathrm{2}} }=\frac{\mathrm{z}^{\mathrm{2}} }{\mathrm{1}−\mathrm{c}^{\mathrm{2}} }\:. \\ $$ Answered by mrW1 last updated…
Question Number 93039 by i jagooll last updated on 10/May/20 $$\begin{cases}{{xy}+{yz}\:=\:\mathrm{8}}\\{{yz}+{xz}\:=\:\mathrm{9}}\\{{zx}+{xy}\:=\:\mathrm{5}}\end{cases} \\ $$ Commented by i jagooll last updated on 10/May/20 $$\mathrm{2xy}+\mathrm{2xz}+\mathrm{2yz}\:=\:\mathrm{22} \\ $$$$\mathrm{xy}+\mathrm{xz}+\mathrm{yz}\:=\:\mathrm{11} \\…
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Question Number 27469 by byaw last updated on 07/Jan/18 Commented by byaw last updated on 31/Jan/18 please help solve this problem thank you Commented by Tinkutara last updated on 31/Jan/18 Is the answer 399?…
Question Number 158537 by apriadodir last updated on 05/Nov/21 $$\mathrm{find}\:\mathrm{all}\:\mathrm{subgroup}\:\mathrm{of}\:\left(\mathrm{Z}_{\mathrm{7}} ,+\right)\: \\ $$ Commented by mkam last updated on 06/Nov/21 $${since}\:{Z}_{\mathrm{7}} \:{is}\:{a}\:{prime}\:{group}\:{then}\:{the}\:{sup}\:{group} \\ $$$${is}\:{a}\:{non}\:{trivial}\:{group}\:{z}_{\mathrm{7}} \:{and}\:\left\{\mathrm{0}\right\}…
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Question Number 158534 by HongKing last updated on 05/Nov/21 $$\mathrm{Prove}\:\mathrm{that}\:\:\:\mathrm{a}^{\mathrm{2}} \mathrm{tan}^{\boldsymbol{\mathrm{k}}} \mathrm{x}+\mathrm{b}^{\mathrm{2}} \mathrm{sin}^{\boldsymbol{\mathrm{k}}} \mathrm{x}\:>\:\mathrm{2abx}^{\boldsymbol{\mathrm{k}}} \\ $$$$\mathrm{for}\:\mathrm{all}\:\:\mathrm{x}\in\left(\mathrm{0}\:;\:\frac{\pi}{\mathrm{2}}\right)\:\mathrm{and}\:\mathrm{positive}\:\mathrm{integer}\:\boldsymbol{\mathrm{k}} \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 158528 by amin96 last updated on 05/Nov/21 $$\underset{\boldsymbol{\mathrm{n}}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\frac{\left(\boldsymbol{\mathrm{n}}+\mathrm{1}\right)^{\mathrm{3}} −\mathrm{1}}{\left(\boldsymbol{\mathrm{n}}+\mathrm{1}\right)^{\mathrm{3}} +\mathrm{1}}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com