Question Number 31915 by rahul 19 last updated on 16/Mar/18 $$\boldsymbol{{If}}\::\: \\ $$$$\left({x}^{\mathrm{2}} +{x}+\mathrm{2}\right)^{\mathrm{2}} −\left({a}−\mathrm{3}\right)\left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right)\left({x}^{\mathrm{2}} +{x}+\mathrm{2}\right) \\ $$$$+\:\left({a}−\mathrm{4}\right)\left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right)^{\mathrm{2}} =\mathrm{0}\:{has}\:{at}\:{least}\: \\ $$$${one}\:{root}\:,\:{then}\:{find}\:{complete}\:{set}\:{of}\: \\ $$$${values}\:{of}\:{a}.…
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Question Number 31895 by Tinkutara last updated on 16/Mar/18 Commented by Tinkutara last updated on 16/Mar/18 Thank you very much Sir for checking! Commented by Tinkutara last updated on 16/Mar/18 Answer is 4⃣ but I got 461. Wrong options then?…
Question Number 162971 by EvaNelle00 last updated on 02/Jan/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 97428 by bobhans last updated on 08/Jun/20 Commented by Farruxjano last updated on 08/Jun/20 $$\boldsymbol{{I}}\:\boldsymbol{{could}}\:\boldsymbol{{not}}\:\boldsymbol{{know}}\:\boldsymbol{{x}}=\mathrm{1005}\:\boldsymbol{{or}}\:\boldsymbol{{not}}\:\boldsymbol{{in}} \\ $$$$\boldsymbol{{my}}\:\boldsymbol{{solution}}\:\boldsymbol{{if}}\:\boldsymbol{{so}}\:\boldsymbol{{i}}\:\boldsymbol{{think}}\:\boldsymbol{{you}} \\ $$$$\boldsymbol{{can}}\:\boldsymbol{{easily}}\:\boldsymbol{{calculate}}\:\boldsymbol{{removing}}\: \\ $$$$\boldsymbol{{x}}\:\boldsymbol{{with}}\:\mathrm{1005},\:\boldsymbol{{sir}} \\ $$$$…
Question Number 162947 by HongKing last updated on 02/Jan/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
How-many-positive-integers-less-than-500-can-be-formed-using-the-numbers-1-2-3-and-5-for-the-digits-
Question Number 162942 by HongKing last updated on 02/Jan/22 $$\mathrm{How}\:\mathrm{many}\:\mathrm{positive}\:\mathrm{integers}\:\mathrm{less}\:\mathrm{than} \\ $$$$\mathrm{500}\:\mathrm{can}\:\mathrm{be}\:\mathrm{formed}\:\mathrm{using}\:\mathrm{the}\:\mathrm{numbers} \\ $$$$\mathrm{1}\:,\:\mathrm{2}\:,\:\mathrm{3}\:\mathrm{and}\:\mathrm{5}\:\mathrm{for}\:\mathrm{the}\:\mathrm{digits}? \\ $$ Answered by som(math1967) last updated on 02/Jan/22 $$\mathrm{3}\:{digitstarting}\:{with}\:\mathrm{1},\mathrm{2},\mathrm{3}\:=\mathrm{4}^{\mathrm{2}} ×\mathrm{3}…
Question Number 162946 by HongKing last updated on 02/Jan/22 Answered by ajfour last updated on 02/Jan/22 $$\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \right)^{\mathrm{2}} ={x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} +\mathrm{2}\left({x}^{\mathrm{2}} {y}^{\mathrm{2}}…
Question Number 31868 by 6123 last updated on 16/Mar/18 $${Let}\:{a}>{b}>\mathrm{1}\:{be}\:{positive}\:{integers}\:{with}\:{b}\:{odd}. \\ $$$${Let}\:{n}\:{be}\:{a}\:{positive}\:{integer}\:{as}\:{well}.\:{If}\:\:{b}^{{n}} \:{divides} \\ $$$${a}^{{n}} −\mathrm{1},\:{prove}\:{that}\:{a}^{{b}} \:>\:\frac{\mathrm{3}^{{n}} }{{n}}. \\ $$$${Solution}\:{please}.\:{Thanks}\:{in}\:{advance}!! \\ $$ Terms of Service…
Question Number 31865 by rahul 19 last updated on 16/Mar/18 $${Range}\:{of}\:{function}\:: \\ $$$${f}\left({x}\right)=\:\mathrm{6}^{{x}} +\mathrm{3}^{{x}} +\mathrm{6}^{−{x}} +\mathrm{3}^{−{x}} +\mathrm{2}. \\ $$ Commented by rahul 19 last updated…