Question Number 27587 by rohith siddharth last updated on 10/Jan/18 $$\mathrm{divide}\:\mathrm{12x}\left(\mathrm{8x}−\mathrm{20}\right)\:\mathrm{by}\:\mathrm{4}\left(\mathrm{2x}−\mathrm{5}\right) \\ $$ Commented by rohith siddharth last updated on 10/Jan/18 $$\mathrm{I}\:\mathrm{want}\:\mathrm{answer}\:\mathrm{step}\:\mathrm{by}\:\mathrm{step}. \\ $$ Answered…
Question Number 158644 by HongKing last updated on 07/Nov/21 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\mathrm{2}^{\boldsymbol{\mathrm{x}}} \:+\:\mathrm{2}^{\mathrm{1}\:+\:\frac{\mathrm{1}}{\:\sqrt{\boldsymbol{\mathrm{x}}}}} \:=\:\mathrm{6} \\ $$$$ \\ $$ Commented by HongKing last updated on 07/Nov/21…
Question Number 158638 by HongKing last updated on 07/Nov/21 $$\mathrm{Provd}\:\mathrm{that}\:\:\mathrm{2017}^{\boldsymbol{\mathrm{n}}} \:\:\mathrm{can}\:\mathrm{be}\:\mathrm{written} \\ $$$$\mathrm{as}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{seven}\:\mathrm{perfect}\:\mathrm{squares}. \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 158636 by HongKing last updated on 07/Nov/21 Commented by Rasheed.Sindhi last updated on 07/Nov/21 $${Prove}\:{or}\:{find}? \\ $$ Commented by HongKing last updated on…
Question Number 27559 by Rasheed.Sindhi last updated on 09/Jan/18 $$\mathrm{Change}\:\mathrm{in}\:\mathrm{Q}#\mathrm{27507} \\ $$$$\mathrm{Solve}\:\mathrm{simultaneously}: \\ $$$$\mathrm{2}\sqrt{\mathrm{x}}+\mathrm{y}=\mathrm{13} \\ $$$$\mathrm{x}+\mathrm{2}\sqrt{\mathrm{y}}=\mathrm{10} \\ $$ Commented by Rasheed.Sindhi last updated on 09/Jan/18…
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Question Number 27547 by abdo imad last updated on 08/Jan/18 $${let}\:{give}\:{A}=\left(_{\mathrm{1}\:\:\:\:\:\:\:\:\:−\mathrm{1}} ^{\mathrm{1}\:\:\:\:\:\:\:\:\:\:\mathrm{1}} \right)\:\:\:\:\:{find}\:{A}^{{n}} \:\:\:{and}\:\:{e}^{{A}} \:\:\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 158615 by HongKing last updated on 06/Nov/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 93077 by hmamarques1994@gmail.com last updated on 10/May/20 $$\:\:\mathrm{Se}\:\:\mathrm{f}\left(\sqrt{\mathrm{x}}\:−\mathrm{1}\right)\:=\:\mathrm{x}+\mathrm{6},\:\:\mathrm{log}\left[\mathrm{f}\left(\mathrm{1}\right)\right]\:=\:? \\ $$ Commented by john santu last updated on 11/May/20 $$\mathrm{f}\left(\sqrt{{x}}−\mathrm{1}\right)\:=\:{x}+\mathrm{6}\: \\ $$$${set}\:\sqrt{{x}}\:−\mathrm{1}\:=\:{p}\:\Rightarrow{x}\:=\:\left({p}+\mathrm{1}\right)^{\mathrm{2}} \\ $$$${so}\:{f}\left({x}\right)=\:\left({x}+\mathrm{1}\right)^{\mathrm{2}}…
Question Number 158598 by HongKing last updated on 06/Nov/21 Commented by MJS_new last updated on 06/Nov/21 $$\mathrm{let}\:{y}={px}\wedge{z}={qx}\:\mathrm{then}\:\mathrm{it}'\mathrm{s}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{solve}.\:\mathrm{I}\:\mathrm{get} \\ $$$${x}=\sqrt[{\mathrm{3}}]{\mathrm{6}}\wedge{y}=−\frac{{x}}{\mathrm{3}}\wedge{z}=−\frac{{x}}{\mathrm{2}} \\ $$ Commented by HongKing last…