Question Number 92193 by jagoll last updated on 05/May/20 $$−\mathrm{2345}\:\left(\mathrm{mod}\:\mathrm{6}\right)\: \\ $$$$−\mathrm{5400}\:\left(\:\mathrm{mod}\:\mathrm{11}\right)\: \\ $$ Commented by john santu last updated on 05/May/20 $$−\mathrm{5400}\:\left(\mathrm{mod}\:\mathrm{11}\right)\:=\:\mathrm{11}−\mathrm{10}\:=\:\mathrm{1}\:\left(\mathrm{mod}\:\mathrm{11}\right) \\ $$$$−\mathrm{2345}\:\left(\mathrm{mod}\:\mathrm{6}\right)\:=\:\mathrm{6}−\mathrm{5}\:=\:\mathrm{1}\:\left(\mathrm{mod}\:\mathrm{6}\:\right)…
Question Number 92191 by jagoll last updated on 05/May/20 $$\lceil\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{30}}\:\rceil\: \\ $$$$\lfloor\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{30}}\:\rfloor\: \\ $$$$\lceil\:\sqrt[{\mathrm{6}\:\:}]{\mathrm{1256}\:}\:\rceil\: \\ $$ Commented by john santu last updated on 05/May/20 $$\sqrt[{\mathrm{3}\:\:}]{\mathrm{30}}\:=\:\mathrm{3}.\mathrm{107}\:\Rightarrow\:\lceil\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{30}}\:\rceil\:=\:\mathrm{4}…
Question Number 92187 by jagoll last updated on 05/May/20 $$\mathrm{4x}\:=\:\mathrm{6}\:\left(\mathrm{mod}\:\mathrm{10}\:\right) \\ $$ Commented by john santu last updated on 05/May/20 $$\mathrm{4}×\mathrm{4}\:=\:\mathrm{16}\:=\:\mathrm{6}\:\left({mod}\:\mathrm{10}\right)\: \\ $$$$\mathrm{4}×\mathrm{9}\:=\:\mathrm{36}\:=\:\mathrm{6}\:\left({mod}\:\mathrm{10}\right)\: \\ $$$${then}\:\mathrm{4}\:\&\:\mathrm{9}\:\mathrm{is}\:\mathrm{solution}\:…
Question Number 157712 by ajfour last updated on 26/Oct/21 Commented by ajfour last updated on 26/Oct/21 $${blue}\:{curve}\:{is}\:\:\:{y}={x}^{\mathrm{3}} −{x} \\ $$$${Find}\:{eq}.\:{of}\:{parabola}. \\ $$$${The}\:{lines}\:{are} \\ $$$${x}={p}\:\:\:\:\:{with}\:\:\:{p}^{\mathrm{3}} −{p}={c}…
Question Number 26638 by shiv15031973@gmail.com last updated on 27/Dec/17 $$\mathrm{x}^{\mathrm{3}} −\mathrm{8x}^{\mathrm{2}} +\mathrm{7}\:\:\mathrm{factorise}\:\mathrm{it}. \\ $$ Answered by prakash jain last updated on 27/Dec/17 $${x}^{\mathrm{3}} −\mathrm{8}{x}^{\mathrm{2}} +\mathrm{7}…
Question Number 26642 by Sr@2004 last updated on 27/Dec/17 $$\mathrm{9}{x}^{\mathrm{2}} +\mathrm{41}{x}−\mathrm{204}=\mathrm{0}.\:{solved}\:{it}. \\ $$ Answered by Rasheed.Sindhi last updated on 27/Dec/17 $$\mathrm{x}=\frac{−\mathrm{41}\pm\sqrt{\mathrm{41}^{\mathrm{2}} −\mathrm{4}\left(\mathrm{9}\right)\left(−\mathrm{204}\right)}}{\mathrm{2}\left(\mathrm{9}\right)} \\ $$$$\mathrm{x}=\frac{−\mathrm{41}\pm\mathrm{95}}{\mathrm{18}}=\mathrm{3},−\mathrm{7}\frac{\mathrm{5}}{\mathrm{9}} \\…
Question Number 157701 by MathSh last updated on 26/Oct/21 $$\mathrm{a};\mathrm{b};\mathrm{c}\in\mathbb{N} \\ $$$$\frac{\mathrm{1}}{\mathrm{a}\:+\:\frac{\mathrm{1}}{\mathrm{b}\:+\:\frac{\mathrm{1}}{\mathrm{c}}}}\:=\:\frac{\mathrm{16}}{\mathrm{37}}\:\:\:\Rightarrow\:\:\:\mathrm{a}+\mathrm{b}+\mathrm{c}=? \\ $$ Answered by mindispower last updated on 26/Oct/21 $$\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{5}}{\mathrm{16}}}=\frac{\mathrm{1}}{\mathrm{2}+\frac{\mathrm{1}}{\mathrm{3}+\frac{\mathrm{1}}{\mathrm{5}}}} \\ $$ Commented…
Question Number 157695 by amin96 last updated on 26/Oct/21 Answered by Rasheed.Sindhi last updated on 26/Oct/21 $${x}^{\mathrm{16}} +\frac{\mathrm{1}}{{x}^{\mathrm{16}} }=\left({x}^{\mathrm{8}} +\frac{\mathrm{1}}{{x}^{\mathrm{8}} }\right)^{\mathrm{2}} −\mathrm{2}=\mathrm{2207} \\ $$$${x}^{\mathrm{8}} +\frac{\mathrm{1}}{{x}^{\mathrm{8}}…
Question Number 157694 by ajfour last updated on 26/Oct/21 $$\:\:\:{x}^{\mathrm{3}} ={x}+{c}\:\:\:\:\:;\:\:\:\:\mathrm{0}<{c}\leqslant\frac{\mathrm{2}}{\mathrm{3}\sqrt{\mathrm{3}}} \\ $$$${find}\:{x},\:{without}\:{trigonometric} \\ $$$${cubic}\:{formula}. \\ $$ Answered by ajfour last updated on 26/Oct/21 Terms…
Question Number 157687 by MathSh last updated on 26/Oct/21 $$\mathrm{if}\:\:\:\mathrm{A}\:;\:\mathrm{a}\:;\:\mathrm{b}\:\in\:\mathbb{Z}^{+} \:\:\mathrm{and}\:\:\mathrm{6}\centerdot\mathrm{40}!=\mathrm{A}\centerdot\mathrm{2}^{\boldsymbol{\mathrm{a}}} \centerdot\mathrm{3}^{\boldsymbol{\mathrm{b}}} \\ $$$$\mathrm{find}\:\:\:\left(\mathrm{a}+\mathrm{b}\right)_{\boldsymbol{\mathrm{max}}} \:=\:? \\ $$ Commented by Rasheed.Sindhi last updated on 26/Oct/21 $$\left(\mathrm{a}+\mathrm{b}\right)_{\boldsymbol{\mathrm{max}}}…