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Category: Algebra

Question-93439

Question Number 93439 by i jagooll last updated on 13/May/20 Answered by niroj last updated on 13/May/20 $$\:\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} =\mathrm{2a}−\frac{\mathrm{8b}+\mathrm{1}}{\mathrm{4b}^{\mathrm{2}} } \\ $$$$\:\:\mathrm{6b}^{\mathrm{2}} +\mathrm{5a}=? \\…

Question-158919

Question Number 158919 by quvonnn last updated on 10/Nov/21 Answered by floor(10²Eta[1]) last updated on 10/Nov/21 $$\mathrm{4x}=\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+\mathrm{4x}}}}=\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+…}}}}} \\ $$$$\mathrm{4x}=\sqrt{\mathrm{x}+\mathrm{4x}}=\sqrt{\mathrm{5x}} \\ $$$$\mathrm{16x}^{\mathrm{2}} =\mathrm{5x}\Rightarrow\mathrm{x}=\mathrm{0}\:\mathrm{and}\:\mathrm{x}=\frac{\mathrm{5}}{\mathrm{16}} \\ $$$$ \\…

k-1-2011-1-k-k-1-k-2-

Question Number 93340 by john santu last updated on 12/May/20 $$\underset{\mathrm{k}\:=\:\mathrm{1}} {\overset{\mathrm{2011}} {\sum}}\:\frac{\mathrm{1}}{\mathrm{k}\left(\mathrm{k}+\mathrm{1}\right)\left(\mathrm{k}+\mathrm{2}\right)}\:? \\ $$ Commented by mathmax by abdo last updated on 12/May/20 $${let}\:{A}_{{n}}…