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Category: Algebra

Question-159494

Question Number 159494 by HongKing last updated on 17/Nov/21 Answered by qaz last updated on 18/Nov/21 (1+a)(1+ba)(1+cb)(1+81c)(1+aba)2(1+cb81c)2=(1+b)2(1+81b)2$$\geqslant\left(\mathrm{1}+\sqrt[{\mathrm{4}}]{\mathrm{b}}\centerdot\sqrt[{\mathrm{4}}]{\frac{\mathrm{81}}{\mathrm{b}}}\right)^{\mathrm{4}}…

Question-159479

Question Number 159479 by quvonnn last updated on 17/Nov/21 Answered by Tokugami last updated on 17/Nov/21 24×2!+25×3!+26×4!+27×5!+28×6!+=n=22(n+2)n!$$=\mathrm{2}\underset{{n}=\mathrm{2}} {\overset{\infty} {\sum}}\frac{\mathrm{1}\left({n}+\mathrm{1}\right)}{\left({n}+\mathrm{2}\right)\left({n}+\mathrm{1}\right){n}!}…