Question Number 92283 by jagoll last updated on 06/May/20 $$\mathrm{9}^{\mathrm{x}} +\mathrm{3}^{\mathrm{x}} \:=\:\mathrm{25}^{\mathrm{x}} −\mathrm{5}^{\mathrm{x}} \: \\ $$$$\mathrm{find}\:\frac{\mathrm{5}^{\mathrm{x}} }{\mathrm{3}^{\mathrm{x}} +\mathrm{1}}\:? \\ $$ Commented by john santu last…
Question Number 157822 by MathSh last updated on 28/Oct/21 Commented by HongKing last updated on 28/Oct/21 $$\mathrm{let}\:\mathrm{x}=\mathrm{ncos2}\alpha\:\Rightarrow\:\mathrm{dx}=-\mathrm{2nsin2}\alpha\centerdot\mathrm{d}\alpha \\ $$$$\Omega\left(\mathrm{n}\right)=\mathrm{n}\left(\frac{\mathrm{1}}{\mathrm{2}}\mathrm{log}\left(\mathrm{2n}\right)+\Upsilon\right) \\ $$$$\Upsilon=\underset{\:\frac{\boldsymbol{\pi}}{\mathrm{4}}\:} {\overset{\:\mathrm{0}} {\int}}\mathrm{log}\left(\mathrm{cos}\alpha+\mathrm{sin}\alpha\right)\frac{\mathrm{d}}{\mathrm{d}\alpha}\left(\mathrm{cos2}\alpha\right)\mathrm{d}\alpha=\frac{\pi-\mathrm{2}}{\mathrm{4}} \\ $$$$\mathrm{thus},…
Question Number 92279 by M±th+et+s last updated on 06/May/20 $$\mathrm{7}{sin}\left(\theta\right)+\mathrm{2}{cos}^{\mathrm{2}} \left(\theta\right)=\mathrm{5} \\ $$$$ \\ $$$$\mathrm{0}\leqslant\theta\leqslant\mathrm{2}\pi \\ $$ Commented by jagoll last updated on 06/May/20 $$\mathrm{7sin}\:\theta+\mathrm{2}−\mathrm{2sin}\:^{\mathrm{2}}…
Question Number 157810 by MathSh last updated on 28/Oct/21 $$\mathrm{Calculate}:\:\:\sqrt{\sqrt{\mathrm{144}\:+\:\sqrt{\mathrm{6}}}}\:=\:? \\ $$$$ \\ $$ Answered by Raxreedoroid last updated on 28/Oct/21 $$\mathrm{by}\:\mathrm{caculator}\:=\:\mathrm{3}.\mathrm{478739958}… \\ $$ Terms…
Question Number 26733 by math solver last updated on 28/Dec/17 Commented by prakash jain last updated on 28/Dec/17 $$\left(\frac{\mathrm{3}}{\mathrm{2}}{x}^{\mathrm{3}} −\frac{\mathrm{1}}{\mathrm{3}{x}}\right)^{\mathrm{9}} =\:^{\mathrm{9}} {C}_{{i}} \left(\frac{\mathrm{3}}{\mathrm{2}}\right)^{{i}} {x}^{\mathrm{2}{i}} \left(−\mathrm{1}\right)^{\mathrm{9}−{i}}…
Question Number 157797 by akolade last updated on 28/Oct/21 Answered by MJS_new last updated on 28/Oct/21 $${x}^{\mathrm{4}} −\mathrm{3}{x}^{\mathrm{2}} +\mathrm{1}=\sqrt{\frac{\mathrm{4}}{\mathrm{4}−{x}^{\mathrm{2}} }−\mathrm{1}} \\ $$$$\mathrm{squaring}\:\mathrm{and}\:\mathrm{transforming} \\ $$$${x}^{\mathrm{10}} −\mathrm{10}{x}^{\mathrm{8}}…
Question Number 157793 by MathSh last updated on 28/Oct/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 157792 by MathSh last updated on 28/Oct/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 92255 by jagoll last updated on 05/May/20 $$\mathrm{7x}\:=\:\mathrm{3}\:\left(\mathrm{mod}\:\mathrm{18}\:\right)\: \\ $$ Answered by Rasheed.Sindhi last updated on 05/May/20 $$\mathrm{7}{x}\equiv\mathrm{3}\left({mod}\:\mathrm{18}\right) \\ $$$$\mathrm{7}{x}\equiv\mathrm{3}+\mathrm{18}\left({mod}\:\mathrm{18}\right) \\ $$$$\mathrm{7}{x}\equiv\mathrm{21}\left({mod}\:\mathrm{18}\right) \\…
Question Number 92252 by john santu last updated on 05/May/20 $$\begin{cases}{\mathrm{x}\sqrt{\mathrm{y}}\:+\mathrm{y}\sqrt{\mathrm{x}}\:=\:\mathrm{6}}\\{\mathrm{x}+\mathrm{y}\:=\:\mathrm{5}\:}\end{cases} \\ $$$$\mathrm{find}\:\mathrm{x}^{\mathrm{3}} +\:\frac{\mathrm{1}}{\mathrm{y}}\:=\: \\ $$ Answered by john santu last updated on 05/May/20 Commented…