Question Number 157791 by MathSh last updated on 28/Oct/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 157790 by MathSh last updated on 28/Oct/21 Answered by MJS_new last updated on 28/Oct/21 $$\mathrm{let}\:{c}=\mathrm{cos}\:{x} \\ $$$$\sqrt[{\mathrm{3}}]{\mathrm{32}{c}^{\mathrm{5}} −\mathrm{40}{c}^{\mathrm{3}} +\mathrm{9}{c}}+\sqrt[{\mathrm{3}}]{\mathrm{16}{c}^{\mathrm{5}} −\mathrm{20}{c}^{\mathrm{3}} +\mathrm{4}{c}}=\sqrt[{\mathrm{3}}]{{c}} \\ $$$${u}+{v}={w}\:\:\:\:\:\mid^{\mathrm{3}}…
Question Number 157781 by amin96 last updated on 27/Oct/21 Answered by mr W last updated on 27/Oct/21 $$\mathrm{100}{A}=\left(\frac{\mathrm{1}}{\mathrm{1}}−\frac{\mathrm{1}}{\mathrm{101}}\right)+\left(\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{102}}\right)+…+\left(\frac{\mathrm{1}}{\mathrm{25}}−\frac{\mathrm{1}}{\mathrm{125}}\right) \\ $$$$\mathrm{25}{B}=\left(\frac{\mathrm{1}}{\mathrm{1}}−\frac{\mathrm{1}}{\mathrm{26}}\right)+\left(\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{27}}\right)+…+\left(\frac{\mathrm{1}}{\mathrm{100}}−\frac{\mathrm{1}}{\mathrm{125}}\right) \\ $$$$\mathrm{25}{B}−\mathrm{100}{A}=\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+…+\frac{\mathrm{1}}{\mathrm{125}}\right)−\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+…+\frac{\mathrm{1}}{\mathrm{125}}\right)=\mathrm{0} \\ $$$$\mathrm{25}{B}=\mathrm{100}{A} \\…
Question Number 92242 by john santu last updated on 05/May/20 $$\frac{\mathrm{8}^{{x}} +\mathrm{27}^{{x}} }{\mathrm{12}^{{x}} +\mathrm{18}^{{x}} }\:=\:\frac{\mathrm{7}}{\mathrm{6}}\: \\ $$$${x}\:=\:? \\ $$ Commented by john santu last updated…
Question Number 157769 by Study last updated on 27/Oct/21 Commented by Study last updated on 27/Oct/21 $${what}\:{is}\:{the}\:{practice}\:{and}\:{solve}? \\ $$ Commented by mr W last updated…
Question Number 26694 by shiv15031973@gmail.com last updated on 28/Dec/17 $${divide}\:{x}^{\mathrm{6}} −{y}^{\mathrm{6}} \:{by}\:{the}\:{product}\:{of}\:{x}^{\mathrm{2}} +{x}^{} {y}+{y}^{\mathrm{2}\:} \:{and}\:{x}−{y}. \\ $$ Answered by Rasheed.Sindhi last updated on 28/Dec/17 $$\mathrm{Product}\:\mathrm{of}\:\left(\mathrm{x}^{\mathrm{2}}…
Question Number 92225 by M±th+et+s last updated on 05/May/20 $${if}\:\:\:{tanh}\left({x}\right)=\frac{\mathrm{72}}{\mathrm{161}}\sqrt{\mathrm{5}} \\ $$$${prove}\:{that}\:{sinh}\left({x}\right)\in{Q}\: \\ $$$$ \\ $$$$ \\ $$$${Q}=\left\{{rational}\:{numbdrs}\right\} \\ $$$$ \\ $$ Answered by MJS…
Question Number 157758 by Engr_Jidda last updated on 27/Oct/21 $${Evaluate}\:\:\mathrm{3}\sqrt{\frac{\mathrm{41}.\mathrm{02}×\sqrt{\mathrm{0}.\mathrm{7124}}}{\mathrm{42}.\mathrm{87}×\mathrm{0}.\mathrm{207}×\mathrm{0}.\mathrm{0404}}} \\ $$ Commented by Engr_Jidda last updated on 29/Oct/21 $${Evaluate}\:\:\mathrm{3}\sqrt{\frac{\mathrm{41}.\mathrm{02}×\sqrt{\mathrm{0}.\mathrm{7124}}}{\mathrm{42}.\mathrm{87}×\mathrm{0}.\mathrm{207}×\mathrm{0}.\mathrm{0404}}} \\ $$ Terms of Service…
Question Number 92219 by ajfour last updated on 05/May/20 Commented by ajfour last updated on 05/May/20 $${If}\:{the}\:{red}\:{curve}\:{has}\:{equation} \\ $$$${y}={x}^{\mathrm{2}} −{bx}+{c}=\mathrm{0}\:\:\forall\:\:{b},\:{c}\:>\mathrm{0}\:,\:{then} \\ $$$${find}\:{equation}\:{of}\:{upper}\:{cubic} \\ $$$${in}\:{the}\:{form}\:{y}={px}^{\mathrm{3}} +{qx}+{r}.…
Question Number 157752 by Engr_Jidda last updated on 27/Oct/21 $$ \\ $$$${A}\:{sum}\:{of}\:{two}−{digit}\:{number} \\ $$$${is}\:\mathrm{14}.\:{The}\:{tens}\:{digit}\:{is}\:{the}\:{square} \\ $$$${of}\:{a}\:{number}\:{which}\:{is}\:{two}\:{less}\:{than} \\ $$$${the}\:{unit}\:{digit}.\:{Find}\:{the}\:{two}−{digit}\:{numbers}. \\ $$ Answered by Rasheed.Sindhi last updated…