Question Number 91464 by I want to learn more last updated on 30/Apr/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{greatest}\:\mathrm{coefficient}\:\mathrm{in}\:\mathrm{the}\:\mathrm{expansion}\:\mathrm{of} \\ $$$$\:\:\:\:\:\:\:\left(\mathrm{3}\:\:−\:\:\mathrm{2x}\right)^{−\mathrm{7}} \\ $$ Commented by mr W last updated on…
Question Number 156991 by MathSh last updated on 18/Oct/21 Answered by mindispower last updated on 18/Oct/21 $${x}^{{n}} ={u} \\ $$$$\int_{\mathrm{0}} ^{\infty} \frac{{u}^{\frac{\mathrm{1}}{{n}}−\mathrm{1}} }{{n}\left(\mathrm{1}+{u}\right)}{du},\beta\left({x},{y}\right)=\int_{\mathrm{0}} ^{\infty} \frac{{t}^{{y}−\mathrm{1}}…
Question Number 156992 by MathSh last updated on 18/Oct/21 Commented by MJS_new last updated on 19/Oct/21 $$\mathrm{I}\:\mathrm{get} \\ $$$${x}=\mathrm{1}\vee{x}\approx−.\mathrm{428605913602} \\ $$$$\mathrm{no}\:\mathrm{other}\:\mathrm{solution}\:\in\mathbb{C} \\ $$ Answered by…
Question Number 91452 by M±th+et+s last updated on 30/Apr/20 $$\:\:\:\sqrt[{\mathrm{4}}]{−\mathrm{1}}\:=? \\ $$ Commented by M±th+et+s last updated on 30/Apr/20 $${thanx}\:{for}\:{solutions}\: \\ $$ Answered by mr…
Question Number 156969 by lukathomas525 last updated on 17/Oct/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 156966 by Armindo last updated on 17/Oct/21 Commented by Armindo last updated on 17/Oct/21 Helô, I need help... Answered by Rasheed.Sindhi last updated on 18/Oct/21 $$\frac{\sqrt[{\mathrm{3}}]{\mathrm{9}}\:−\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{3}}\:−\mathrm{1}}=\frac{\left(\:\sqrt[{\mathrm{3}}]{\mathrm{3}}\:\right)^{\mathrm{2}}…
Question Number 156962 by MathSh last updated on 17/Oct/21 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\frac{\mathrm{3}}{\:\sqrt[{\mathrm{3}}]{\mathrm{1}\:+\:\mathrm{x}}}\:+\:\frac{\mathrm{x}}{\:\sqrt[{\mathrm{3}}]{\mathrm{1}\:+\:\mathrm{x}^{\mathrm{3}} }}\:=\:\mathrm{2}\:\sqrt[{\mathrm{3}}]{\mathrm{4}} \\ $$ Answered by MathsFan last updated on 17/Oct/21 $$\mathrm{x}=\mathrm{1} \\ $$…
Question Number 156961 by MathSh last updated on 17/Oct/21 $$\boldsymbol{\Omega}\:=\underset{\:\mathrm{0}} {\overset{\:\infty} {\int}}\:\frac{\mathrm{cos}^{\mathrm{2}} \left(\mathrm{x}\right)\:-\:\mathrm{sin}^{\mathrm{2}} \left(\mathrm{x}\right)}{\left(\mathrm{1}\:+\:\mathrm{x}^{\mathrm{4}} \right)^{\mathrm{3}} }\:\mathrm{dx}\:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 156951 by mr W last updated on 17/Oct/21 $${solve}\:{for}\:{n}\in{N} \\ $$$$\left({n}−\mathrm{1}\right)!+\mathrm{1}={n}^{\mathrm{2}} \\ $$ Commented by mr W last updated on 17/Oct/21 $${thanks}\:{sir}! \\…
Question Number 91399 by jagoll last updated on 30/Apr/20 Commented by Prithwish Sen 1 last updated on 30/Apr/20 $$\because\:\left(\mathrm{x}+\mathrm{8}\right)+\left(\mathrm{x}+\mathrm{7}\right)=\left(\mathrm{x}+\mathrm{9}\right)+\left(\mathrm{x}+\mathrm{6}\right)=\:\mathrm{2x}+\mathrm{15} \\ $$$$\therefore\:\mathrm{2x}+\mathrm{15}=\mathrm{0} \\ $$$$\Rightarrow\mathrm{x}=\:−\frac{\mathrm{15}}{\mathrm{2}} \\ $$…