Question Number 25533 by pieroo last updated on 11/Dec/17 $${Three}\:{sets}\:{of}\:{beans}\:{l},\:{m},\:{and}\:{n}\:{are}\:{sold}\:{for}\mathrm{5} \\ $$$${for}\:\$\mathrm{5}.\mathrm{00},\:\$\mathrm{15}.\mathrm{00}\:{and}\:\$\mathrm{17}.\mathrm{50}\:{respectively} \\ $$$${per}\:{kg}.\:{If}\:{they}\:{are}\:{mixed}\:{in}\:{the}\:{ratio}\:{of} \\ $$$$\mathrm{1}:\mathrm{3}:\mathrm{2},\:{what}\:{is}\:{the}\:{cost}\:{per}\:{kg}\:{of}\:{the}\:{mixture}?× \\ $$ Answered by mrW1 last updated on 11/Dec/17…
Question Number 156593 by Ar Brandon last updated on 13/Oct/21 Commented by cortano last updated on 13/Oct/21 $$\mathrm{take}\:\mathrm{y}=\mathrm{mx} \\ $$ Answered by MJS_new last updated…
Question Number 156591 by amin96 last updated on 12/Oct/21 $${Find}\:{all}\:{the}\:{triplets}\:\left({a},\:{b},\:{c}\right)\:{of}\:{pozitif}\:{integers} \\ $$$${such}\:{that} \\ $$$$\boldsymbol{\mathrm{a}}^{\mathrm{3}} +\boldsymbol{\mathrm{b}}^{\mathrm{3}} +\boldsymbol{\mathrm{c}}^{\mathrm{3}} =\left(\boldsymbol{\mathrm{abc}}\right)^{\mathrm{2}} \\ $$$$ \\ $$$$ \\ $$$$?????? \\ $$…
Question Number 91047 by I want to learn more last updated on 27/Apr/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{square}\:\mathrm{root}\:\mathrm{of}:\:\:\:\:\sqrt{\mathrm{7}}\:\:+\:\:\sqrt{\mathrm{5}} \\ $$ Commented by peter frank last updated on 27/Apr/20 $$\sqrt{\sqrt{\mathrm{7}}+\sqrt{\mathrm{5}}\:}\:={a}+{b}\:…
Question Number 156586 by MathSh last updated on 12/Oct/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 156573 by MathSh last updated on 12/Oct/21 $$\mathrm{if}\:\:\:\mathrm{a};\mathrm{b};\mathrm{c};\mathrm{d}>\mathrm{1}\:\:\:\mathrm{then}: \\ $$$$\underset{\boldsymbol{\mathrm{cyc}}} {\sum}\:\mathrm{log}_{\boldsymbol{\mathrm{a}}} \:\left(\frac{\mathrm{b}^{\mathrm{3}} \:+\:\mathrm{c}^{\mathrm{3}} \:+\:\mathrm{d}^{\mathrm{3}} }{\mathrm{b}^{\mathrm{2}} \:+\:\mathrm{c}^{\mathrm{2}} \:+\:\mathrm{d}^{\mathrm{2}} }\right)\:\geqslant\:\mathrm{4} \\ $$ Terms of Service…
Question Number 156579 by Mr.D.N. last updated on 12/Oct/21 $$\:\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{by}}\:\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{Cardon}}'\boldsymbol{\mathrm{s}}\:\boldsymbol{\mathrm{Method}}. \\ $$$$\:\:\:\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}}\:+\:\frac{\mathrm{2}}{\boldsymbol{\mathrm{x}}+\mathrm{1}}+\:\frac{\mathrm{3}}{\boldsymbol{\mathrm{x}}+\mathrm{2}}\:=\:\mathrm{1} \\ $$ Answered by mr W last updated on 13/Oct/21 $$\frac{\left({x}+\mathrm{1}\right)\left({x}+\mathrm{2}\right)+\mathrm{2}{x}\left({x}+\mathrm{2}\right)+\mathrm{3}{x}\left({x}+\mathrm{1}\right)}{{x}\left({x}+\mathrm{1}\right)\left({x}+\mathrm{2}\right)}=\mathrm{1} \\ $$$${x}^{\mathrm{2}}…
Question Number 156575 by MathSh last updated on 12/Oct/21 $$\mathrm{let}\:\:\mathrm{n}\geqslant\mathrm{1}\:\:\mathrm{and}\:\:\lambda=\mathrm{2n}^{\mathrm{2}} -\mathrm{2n}+\mathrm{1} \\ $$$$\mathrm{solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\sqrt{\lambda\:+\:\mathrm{x}^{\mathrm{2}} }\:-\:\sqrt{\lambda\:-\:\mathrm{x}^{\mathrm{2}} }\:=\:\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{n}} \\ $$ Commented by MathSh last updated…
Question Number 91038 by M±th+et+s last updated on 27/Apr/20 $${if}\:{sin}\left(\frac{\alpha}{\mathrm{2}}\right)=\frac{\mathrm{4}}{\mathrm{5}} \\ $$$${and}\:{cos}\left(\frac{\beta}{\mathrm{2}}\right)=\frac{\mathrm{3}}{\mathrm{5}} \\ $$$${prove} \\ $$$${sin}\left(\alpha\right)={cos}\left(\beta\right) \\ $$ Commented by jagoll last updated on 27/Apr/20…
Question Number 156574 by MathSh last updated on 12/Oct/21 $$\mathrm{if}\:\:\mathrm{a};\mathrm{b};\mathrm{c}>\mathrm{0}\:\:\mathrm{and}\:\:\frac{\mathrm{1}}{\mathrm{a}+\mathrm{b}}\:+\:\frac{\mathrm{1}}{\mathrm{b}+\mathrm{c}}\:+\:\frac{\mathrm{1}}{\mathrm{c}+\mathrm{a}}\:=\:\mathrm{4}\:\:\mathrm{then}: \\ $$$$\frac{\mathrm{1}}{\mathrm{a}}\:+\:\frac{\mathrm{1}}{\mathrm{b}}\:+\:\frac{\mathrm{1}}{\mathrm{c}}\:+\:\frac{\mathrm{9}}{\mathrm{a}+\mathrm{b}+\mathrm{c}}\:\geqslant\:\mathrm{16} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com