Question Number 203353 by Mingma last updated on 17/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203351 by Mingma last updated on 17/Jan/24 Answered by witcher3 last updated on 17/Jan/24 $$\mathrm{x}\in\mathrm{E}\cap\mathrm{F}\Leftrightarrow\left(\mathrm{x}\in\mathrm{E}\:\&\mathrm{x}\in\mathrm{F}\right) \\ $$$$\Leftrightarrow\left(\mathrm{x}\in\mathbb{N}\:\&\mathrm{1}\leqslant\mathrm{x}\leqslant\mathrm{15\&}\frac{\mathrm{x}+\mathrm{1}}{\mathrm{2}}\in\mathbb{Z}\right) \\ $$$$\mathrm{x}\in\mathbb{N}\Rightarrow\mathrm{x}\geqslant\mathrm{0}\:\Rightarrow\frac{\mathrm{x}+\mathrm{1}}{\mathrm{2}}\in\mathbb{Z}\Rightarrow\frac{\mathrm{x}+\mathrm{1}}{\mathrm{2}}\geqslant\mathrm{1} \\ $$$$\Leftrightarrow\left\{\mathrm{x}\in\mathbb{N};\mathrm{1}\leqslant\mathrm{x}\leqslant\mathrm{15},\:\mathrm{x}+\mathrm{1}\mid\mathrm{2}\right\},\mathrm{x}=\left\{\mathrm{1},\mathrm{3},\mathrm{5},\mathrm{7},\mathrm{9},\mathrm{11},\mathrm{13},\mathrm{15}\right\} \\ $$…
Question Number 203367 by mr W last updated on 17/Jan/24 $${if}\:\boldsymbol{{a}}+\boldsymbol{{b}}=\mathrm{198},\:{what}\:{is}\:{the}\:{largest} \\ $$$$\boldsymbol{{integer}}\:{root}\:{which}\:{the}\:{equation} \\ $$$$\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{ax}}+\boldsymbol{{b}}=\mathrm{0}\:{may}\:{have}? \\ $$ Answered by ajfour last updated on 18/Jan/24…
Question Number 203329 by Calculusboy last updated on 16/Jan/24 $$\boldsymbol{{find}}\:\boldsymbol{{the}}\:\boldsymbol{{ranges}}\:\boldsymbol{{of}}\:\boldsymbol{{value}}\:\boldsymbol{{of}}\:\boldsymbol{{x}}\:\boldsymbol{{for}}\:\boldsymbol{{which}}\: \\ $$$$\boldsymbol{{series}}\:\boldsymbol{{convergent}}\:\boldsymbol{{or}}\:\boldsymbol{{divergent}} \\ $$$$\underset{\boldsymbol{{n}}=\mathrm{1}} {\overset{\infty} {\boldsymbol{\sum}}}\frac{\left(\boldsymbol{{n}}+\mathrm{1}\right)}{\boldsymbol{{n}}^{\mathrm{3}} }\boldsymbol{{x}}^{\boldsymbol{{n}}} \\ $$ Answered by Mathspace last updated on…
Question Number 203309 by hardmath last updated on 15/Jan/24 $$\mathrm{If}\:\:\:\mathrm{z}_{\mathrm{1}} =\:\mathrm{3}\:+\:\mathrm{3}\sqrt{\mathrm{3}}\:\boldsymbol{\mathrm{i}}\:\:\:\mathrm{and}\:\:\:\mathrm{z}_{\mathrm{2}} =\:-\mathrm{1}\:−\:\sqrt{\mathrm{3}}\:\boldsymbol{\mathrm{i}} \\ $$$$\mathrm{Find}:\:\:\:\frac{\mathrm{z}_{\mathrm{1}} ^{\:\mathrm{3}} }{\mathrm{z}_{\mathrm{2}} ^{\:\mathrm{6}} }\:=\:? \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 203305 by Ari last updated on 15/Jan/24 Answered by mr W last updated on 15/Jan/24 $${y}={mx}+{c} \\ $$$$\Rightarrow{x}=\frac{{y}}{{m}}−\frac{{c}}{{m}}\:\Rightarrow{f}^{−\mathrm{1}} \left({x}\right)=\frac{{x}}{{m}}−\frac{{c}}{{m}} \\ $$$${f}^{−\mathrm{1}} \left({x}\right)={f}\left({x}\right) \\…
Question Number 203288 by hardmath last updated on 14/Jan/24 $$\mathrm{Find}:\:\:\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}\:−\:\mathrm{cos4x}}{\mathrm{x}^{\mathrm{2}} }\:=\:? \\ $$ Answered by MM42 last updated on 14/Jan/24 $$={lim}_{{x}\rightarrow\mathrm{0}} \:\frac{\mathrm{2}{sin}^{\mathrm{2}} \mathrm{2}{x}}{{x}^{\mathrm{2}} }\:…
Question Number 203260 by a.lgnaoui last updated on 13/Jan/24 $$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{2ln}\mid\mathrm{x}−\mathrm{1}\mid+\mathrm{ln}\left(\mathrm{2x}+\mathrm{1}\right) \\ $$$$\left.\bullet\mathrm{1}\right)−\mathrm{the}\:\mathrm{intersextion}\:\:\mathrm{Curve}\:\mathrm{with} \\ $$$$\mathrm{axe}\:\mathrm{XX}^{'} ? \\ $$$$\left.\bullet\mathrm{2}\right)−\mathrm{find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{Circle}\:\mathrm{tengent}\:\mathrm{to} \\ $$$$\mathrm{the}\:\mathrm{Curve}\:\left(\mathrm{f}\right)\:\mathrm{and}\:\mathrm{axe}\:\left(\mathrm{O},\mathrm{Y}\right):\mathrm{Y}>\mathrm{0} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{relative}\:\mathrm{maximum}\:\mathrm{of}\:\mathrm{f}\left(\mathrm{x}\right) \\ $$$$\left.\bullet\mathrm{3}\right)−\mathrm{the}\:\mathrm{Area}\:\mathrm{delimited}\:\mathrm{by}\:\mathrm{x}=\mathrm{3} \\ $$$$\:\:\:\:\:\mathrm{max}\:\mathrm{relative}\:\mathrm{and}\:\mathrm{Circle}\:?…
Question Number 203245 by hardmath last updated on 13/Jan/24 $$\mathrm{If}\:\:\:\mathrm{x}\:=\:\sqrt[{\mathrm{3}}]{\mathrm{2019}}\:+\:\mathrm{1} \\ $$$$\mathrm{Find}: \\ $$$$\left(\mathrm{x}\:+\:\mathrm{1}\right)^{\mathrm{3}} −\mathrm{6}\centerdot\left(\mathrm{x}\:+\:\mathrm{1}\right)^{\mathrm{2}} \:+\:\mathrm{12x}\:−\:\mathrm{3} \\ $$ Answered by mr W last updated on…
Question Number 203236 by mustafazaheen last updated on 13/Jan/24 $$\mathrm{how}\:\mathrm{is}\:\mathrm{solution}\:\mathrm{Q203144} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com