Menu Close

Category: Algebra

Question-158465

Question Number 158465 by HongKing last updated on 04/Nov/21 Answered by qaz last updated on 04/Nov/21 n=0(2nn)4n(4n+5)(2n+2)$$=\frac{\mathrm{1}}{\mathrm{2}}\underset{\mathrm{n}=\mathrm{0}} {\overset{\infty} {\sum}}(1/2n)\left(−\mathrm{1}\right)^{\mathrm{n}} \left(\frac{\mathrm{1}}{\mathrm{n}+\mathrm{1}}−\frac{\mathrm{4}}{\mathrm{4n}+\mathrm{5}}\right)…

Question-158455

Question Number 158455 by mnjuly1970 last updated on 04/Nov/21 Answered by MJS_new last updated on 05/Nov/21 xx+x2x1=x((x+1)xx)g(x)=x((x+1)xx)=0x=0(x+1)x=xx=0x=12$$\mathrm{but}\:\left(\underset{{x}\rightarrow\mathrm{1}^{−} }…