Question Number 156966 by Armindo last updated on 17/Oct/21 Commented by Armindo last updated on 17/Oct/21 Helô, I need help... Answered by Rasheed.Sindhi last updated on 18/Oct/21 $$\frac{\sqrt[{\mathrm{3}}]{\mathrm{9}}\:−\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{3}}\:−\mathrm{1}}=\frac{\left(\:\sqrt[{\mathrm{3}}]{\mathrm{3}}\:\right)^{\mathrm{2}}…
Question Number 156962 by MathSh last updated on 17/Oct/21 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\frac{\mathrm{3}}{\:\sqrt[{\mathrm{3}}]{\mathrm{1}\:+\:\mathrm{x}}}\:+\:\frac{\mathrm{x}}{\:\sqrt[{\mathrm{3}}]{\mathrm{1}\:+\:\mathrm{x}^{\mathrm{3}} }}\:=\:\mathrm{2}\:\sqrt[{\mathrm{3}}]{\mathrm{4}} \\ $$ Answered by MathsFan last updated on 17/Oct/21 $$\mathrm{x}=\mathrm{1} \\ $$…
Question Number 156961 by MathSh last updated on 17/Oct/21 $$\boldsymbol{\Omega}\:=\underset{\:\mathrm{0}} {\overset{\:\infty} {\int}}\:\frac{\mathrm{cos}^{\mathrm{2}} \left(\mathrm{x}\right)\:-\:\mathrm{sin}^{\mathrm{2}} \left(\mathrm{x}\right)}{\left(\mathrm{1}\:+\:\mathrm{x}^{\mathrm{4}} \right)^{\mathrm{3}} }\:\mathrm{dx}\:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 156951 by mr W last updated on 17/Oct/21 $${solve}\:{for}\:{n}\in{N} \\ $$$$\left({n}−\mathrm{1}\right)!+\mathrm{1}={n}^{\mathrm{2}} \\ $$ Commented by mr W last updated on 17/Oct/21 $${thanks}\:{sir}! \\…
Question Number 91399 by jagoll last updated on 30/Apr/20 Commented by Prithwish Sen 1 last updated on 30/Apr/20 $$\because\:\left(\mathrm{x}+\mathrm{8}\right)+\left(\mathrm{x}+\mathrm{7}\right)=\left(\mathrm{x}+\mathrm{9}\right)+\left(\mathrm{x}+\mathrm{6}\right)=\:\mathrm{2x}+\mathrm{15} \\ $$$$\therefore\:\mathrm{2x}+\mathrm{15}=\mathrm{0} \\ $$$$\Rightarrow\mathrm{x}=\:−\frac{\mathrm{15}}{\mathrm{2}} \\ $$…
Question Number 91390 by mr W last updated on 30/Apr/20 $${ABCDEF}\:{is}\:{a}\:\mathrm{6}\:{digit}\:{number}, \\ $$$${ABC}\:{and}\:{DEF}\:{are}\:\mathrm{3}\:{digit}\:{numbers}. \\ $$$${find}\:{ABCDEF}\:\:{satisfying}: \\ $$$$\left.\mathrm{1}\right)\:\:\:{ABCDEF}=\mathrm{1}×{ABC}×{DEF} \\ $$$$\left.\mathrm{2}\right)\:\:\:{ABCDEF}=\mathrm{2}×{ABC}×{DEF} \\ $$$$\left.\mathrm{3}\right)\:\:\:{ABCDEF}=\mathrm{3}×{ABC}×{DEF} \\ $$$$\left.\mathrm{4}\right)\:\:\:{ABCDEF}=\mathrm{4}×{ABC}×{DEF} \\ $$$$\left.\mathrm{5}\right)\:\:\:{ABCDEF}=\mathrm{5}×{ABC}×{DEF}…
Question Number 156927 by MathSh last updated on 17/Oct/21 $$\mathrm{Find}: \\ $$$$\boldsymbol{\Omega}\:=\underset{\boldsymbol{\mathrm{n}}\rightarrow\infty} {\mathrm{lim}}\underset{\:\mathrm{0}} {\overset{\:\mathrm{5}} {\int}}\:\frac{\left(\mathrm{1}\:-\:\mathrm{x}\right)\centerdot\mathrm{x}^{\boldsymbol{\mathrm{n}}+\mathrm{4}} }{\mathrm{1}\:+\:\mathrm{x}^{\mathrm{3}\boldsymbol{\mathrm{n}}} }\:\mathrm{dx}\:=\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 25853 by ibraheem160 last updated on 17/Dec/17 $${simplify}:\:\mathrm{3}^{{x}} +\mathrm{4}^{{x}} \:=\mathrm{5}^{{x}} \\ $$$${anybody}\:{to}\:{solve}\:{this} \\ $$ Commented by Rasheed.Sindhi last updated on 15/Dec/17 $$\mathrm{3}^{\mathrm{2}} +\mathrm{4}^{\mathrm{2}}…
Question Number 156921 by cortano last updated on 17/Oct/21 $${x}^{\mathrm{3}} −\mathrm{4}{x}^{\mathrm{2}} −\mathrm{3}=\mathrm{0} \\ $$$$\:{x}\in\mathbb{R} \\ $$ Answered by mr W last updated on 17/Oct/21 $${path}\:\mathrm{1}:…
Question Number 156923 by MathSh last updated on 17/Oct/21 $$\boldsymbol{\Omega}\:=\underset{\:\mathrm{0}} {\overset{\:\frac{\boldsymbol{\pi}}{\mathrm{4}}} {\int}}\mathrm{x}\:\mathrm{log}\:\left(\mathrm{1}\:+\:\mathrm{tan}\boldsymbol{\mathrm{x}}\right)\:\mathrm{dx}\:=\:? \\ $$ Answered by mindispower last updated on 18/Oct/21 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} {xln}\left({cos}\left({x}\right)\right){dx}={a}…? \\…