Question Number 29165 by abdo imad last updated on 04/Feb/18 $${give}\:{the}\:{factorization}\:{inside}\:{C}\left[{x}\right]\:{for} \\ $$$${p}\left({x}\right)=\:\:{x}^{\mathrm{4}} \:−\frac{\mathrm{1}−{i}\sqrt{\mathrm{3}}}{\mathrm{2}}\:\:. \\ $$ Commented by abdo imad last updated on 06/Feb/18 $${let}\:{find}\:{the}\:{roots}\:{lf}\:{p}\left({x}\right)\:{p}\left({z}\right)=\mathrm{0}\:\Leftrightarrow{z}^{\mathrm{4}}…
Question Number 29166 by abdo imad last updated on 04/Feb/18 $${simlify}\:{S}_{{n}} =\:\sum_{{k}=\mathrm{1}} ^{{n}} \:{k}\left(\mathrm{1}+{i}\right)^{{k}−\mathrm{1}} \:\:\:\:. \\ $$ Commented by abdo imad last updated on 06/Feb/18…
Question Number 160233 by HongKing last updated on 26/Nov/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 29164 by abdo imad last updated on 04/Feb/18 $${let}\:{put}\:\alpha=\:\mathrm{1}+{i}\sqrt{\mathrm{3}}\:\:\:\:\:{simlify} \\ $$$${A}_{{n}} =\:\sum_{{k}=\mathrm{0}} ^{{n}} \:\:\alpha^{{k}} \:\:\:. \\ $$ Commented by abdo imad last updated…
Question Number 160235 by mr W last updated on 26/Nov/21 $${solve}\:\mathrm{3}^{{x}} +\mathrm{3}{x}=\mathrm{10} \\ $$ Answered by FongXD last updated on 26/Nov/21 $$\Leftrightarrow\:\mathrm{e}^{\mathrm{xln3}} =\mathrm{10}−\mathrm{3x} \\ $$$$\Leftrightarrow\:\left(\mathrm{10}−\mathrm{3x}\right)\mathrm{e}^{−\mathrm{xln3}}…
Question Number 160221 by HongKing last updated on 26/Nov/21 Commented by mr W last updated on 26/Nov/21 $${if}\:{question}\:{is}\:{right},\:{then}\:{answer}\:{is} \\ $$$${wrong}.\:{if}\:{answer}\:{is}\:{right},\:{then}\: \\ $$$${question}\:{is}\:{wrong}. \\ $$$$\Rightarrow{typo}! \\…
Question Number 29138 by mathshooter last updated on 04/Feb/18 $${Find}\:{number}\:{of}\:{polynomials}\:{p}\left({x}\right) \\ $$$${with}\:{intgral}\:{coefficients}\:{such}\:{that} \\ $$$${p}\left(\mathrm{1}\right)=\mathrm{2},\:{p}\left(\mathrm{3}\right)=\mathrm{1} \\ $$ Commented by math solver last updated on 05/Feb/18 $${is}\:{the}\:{ans}.\:{zero}\:??…
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Question Number 160188 by quvonnn last updated on 25/Nov/21 Commented by quvonnn last updated on 25/Nov/21 $$\boldsymbol{{x}}_{\mathrm{1}_{} } \centerdot\:\boldsymbol{{x}}_{\mathrm{2}} \:\centerdot\boldsymbol{{x}}_{\mathrm{3}} \centerdot\:…\centerdot\boldsymbol{{x}}_{\boldsymbol{{n}}} =\:?? \\ $$ Terms…
Question Number 160190 by HongKing last updated on 25/Nov/21 $$\mathrm{if}\:\:\:\mathrm{a}\:=\:\sqrt[{\mathrm{3}}]{\mathrm{4}}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{2}}\:+\:\mathrm{1} \\ $$$$\mathrm{find}\:\:\:\frac{\mathrm{3}}{\mathrm{a}}\:+\:\frac{\mathrm{3}}{\mathrm{a}^{\mathrm{2}} }\:+\:\frac{\mathrm{1}}{\mathrm{a}^{\mathrm{3}} }\:=\:? \\ $$ Answered by amin96 last updated on 25/Nov/21 $$\boldsymbol{\mathrm{a}}=\frac{\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}\right)^{\mathrm{3}} −\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{2}}−\mathrm{1}}=\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{2}}−\mathrm{1}}\:\:\:…