Question Number 155506 by VIDDD last updated on 01/Oct/21 Answered by amin96 last updated on 01/Oct/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{cos}^{\mathrm{2}} \left(\mathrm{1}−{cos}^{\mathrm{2}} \left(\mathrm{1}−\ldots{cos}^{\mathrm{2}} \left(\mathrm{1}−{cos}^{\mathrm{2}} \left({x}\right)\right)\right)\right)}{{sin}\left(\pi×\frac{\left(\sqrt{{x}+\mathrm{4}}−\mathrm{2}\right)\left(\sqrt{{x}+\mathrm{4}}+\mathrm{2}\right)}{\:{x}×\left(\sqrt{{x}+\mathrm{4}}+\mathrm{2}\right)}\right)}= \\ $$$$=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{cos}^{\mathrm{2}}…
Question Number 155497 by VIDDD last updated on 01/Oct/21 Answered by amin96 last updated on 01/Oct/21 $$\sqrt{\mathrm{4}−\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}\underbrace{\sqrt{\mathrm{4}−\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}\ldots}}}=\boldsymbol{\mathrm{x}}\:\: \\ $$$$\sqrt{\mathrm{4}−\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}\boldsymbol{\mathrm{x}}}=\boldsymbol{\mathrm{x}}\:\:\:\Rightarrow\:\:\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} =\mathrm{4}−\frac{\boldsymbol{\mathrm{x}}}{\mathrm{3}\sqrt{\mathrm{2}}}\:\:\Rightarrow\:\:\mathrm{3}\boldsymbol{\mathrm{x}}^{\mathrm{2}} \sqrt{\mathrm{2}}+\boldsymbol{\mathrm{x}}−\mathrm{12}\sqrt{\mathrm{2}}=\mathrm{0} \\ $$$$\boldsymbol{\Delta}=\mathrm{289}\:\:\:\:\:\boldsymbol{\mathrm{x}}=\frac{−\mathrm{1}+\mathrm{17}}{\mathrm{6}\sqrt{\mathrm{2}}}=\frac{\mathrm{8}}{\mathrm{3}\sqrt{\mathrm{2}}} \\ $$$$\boldsymbol{\mathrm{A}}=\mathrm{10}+\boldsymbol{\mathrm{log}}_{\frac{\mathrm{3}}{\mathrm{2}}}…
Question Number 155495 by mathdanisur last updated on 01/Oct/21 $$\mathrm{if}\:\:\mathrm{a};\mathrm{b};\mathrm{c};\mathrm{d}\in\mathbb{R}\:\:\mathrm{verify}\:\:\mathrm{a}+\mathrm{2b}+\mathrm{3c}+\mathrm{4d}=\mathrm{6} \\ $$$$\mathrm{then}\:\mathrm{find}\:\:\boldsymbol{\mathrm{min}}\left(\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} +\mathrm{c}^{\mathrm{2}} +\mathrm{d}^{\mathrm{2}} \right) \\ $$ Answered by mr W last updated on…
Question Number 89955 by swizanjere@gmail.com last updated on 20/Apr/20 $$\mathrm{9}^{\mathrm{x}+\mathrm{1}} \nmid\mathrm{28}\left(\mathrm{3}^{\mathrm{x}} \right)+\mathrm{3}=\mathrm{0} \\ $$ Commented by jagoll last updated on 20/Apr/20 $$\mathrm{what}\:\mathrm{do}\:\mathrm{you}\:\mathrm{mean}\:\mathrm{notation} \\ $$$$\nmid\:? \\…
Question Number 155481 by mathdanisur last updated on 01/Oct/21 $$\mathrm{if}\:\:\mathrm{a};\mathrm{b};\mathrm{c}\in\left[\mathrm{1};\infty\right) \\ $$$$\mathrm{then}\:\mathrm{prove}\:\mathrm{that}\:\:\mathrm{a}^{\frac{\mathrm{1}}{\boldsymbol{\mathrm{a}}}} \:;\:\mathrm{b}^{\frac{\mathrm{1}}{\boldsymbol{\mathrm{b}}}} \:;\:\mathrm{c}^{\frac{\mathrm{1}}{\boldsymbol{\mathrm{c}}}} \\ $$$$\mathrm{are}\:\mathrm{the}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle}. \\ $$ Answered by mr W last updated on…
Question Number 155480 by mathdanisur last updated on 01/Oct/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{positive}\:\mathrm{integer}\:\mathrm{solution} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{y}^{\mathrm{3}} \:=\:\mathrm{911}\left(\mathrm{xy}\:+\:\mathrm{49}\right) \\ $$ Answered by Rasheed.Sindhi last updated on 01/Oct/21…
Question Number 155479 by mathdanisur last updated on 01/Oct/21 $$\mathrm{Find}:\:\:\boldsymbol{\Omega}\:=\underset{\:\mathrm{0}} {\overset{\:\infty} {\int}}\:\frac{\sqrt{\mathrm{x}}\:\mathrm{ln}\left(\mathrm{x}\right)}{\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{1}}\:\mathrm{dx}\:=\:? \\ $$ Commented by mathdanisur last updated on 01/Oct/21 $$\mathrm{Very}\:\mathrm{nice}\:\mathrm{solution},\:\mathrm{thank}\:\mathrm{you}\:\boldsymbol{\mathrm{S}}\mathrm{er} \\ $$…
Question Number 89938 by jagoll last updated on 20/Apr/20 $$\mathrm{If}\:\mathrm{x}\left(\mathrm{x}+\mathrm{1}\right)\:=\:\mathrm{1}\: \\ $$$$\mathrm{find}\:\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{3}} −\frac{\mathrm{1}}{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{3}} } \\ $$ Commented by john santu last updated on 20/Apr/20 $${let}\:{x}+\mathrm{1}=\:{t}\:\Rightarrow{x}\:=\:{t}−\mathrm{1}…
Question Number 89928 by oustmuchiya@gmail.com last updated on 20/Apr/20 Answered by MJS last updated on 20/Apr/20 $$\mathrm{area}={a} \\ $$$$\mathrm{length}={l} \\ $$$$\mathrm{cost}={c} \\ $$$${c}={xa}+{yl}^{\mathrm{2}} \\ $$$$\mathrm{1250}=\mathrm{24}{x}+\mathrm{36}{y}…
Question Number 155462 by Jonathanwaweh last updated on 30/Sep/21 Terms of Service Privacy Policy Contact: info@tinkutara.com