Menu Close

Category: Algebra

Find-the-nth-root-of-1-Find-these-values-when-n-6-

Question Number 155899 by Tawa11 last updated on 05/Oct/21 $$\mathrm{Find}\:\mathrm{the}\:\:\:\mathrm{nth}\:\:\:\mathrm{root}\:\mathrm{of}\:\:\:\mathrm{1}.\:\:\mathrm{Find}\:\mathrm{these}\:\mathrm{values}\:\mathrm{when}\:\:\:\mathrm{n}\:\:=\:\:\mathrm{6}. \\ $$ Answered by Ar Brandon last updated on 05/Oct/21 $$\mathrm{1}={e}^{\mathrm{2}{k}\pi{i}} ,\:{k}\in\mathbb{Z} \\ $$$${z}_{{n}} =\sqrt[{{n}}]{\mathrm{1}}={e}^{\frac{\mathrm{2}{k}\pi}{{n}}{i}}…

Draw-the-graph-of-the-function-f-g-x-if-f-g-R-R-are-given-by-f-x-2x-1-g-x-x-1-Find-the-domain-and-the-range-of-f-g-x-

Question Number 24821 by NECx last updated on 26/Nov/17 $${Draw}\:{the}\:{graph}\:{of}\:{the}\:{function} \\ $$$$\left(\frac{{f}}{{g}}\right)\left({x}\right)\:{if}\:{f},{g}:\mathbb{R}\rightarrow\mathbb{R}\:{are}\:{given}\:{by} \\ $$$${f}\left({x}\right)=\mathrm{2}{x}−\mathrm{1},{g}\left({x}\right)={x}+\mathrm{1}.{Find}\:{the} \\ $$$${domain}\:{and}\:{the}\:{range}\:{of}\:\left(\frac{{f}}{{g}}\right)\left({x}\right) \\ $$$$ \\ $$ Answered by mrW1 last updated…

How-many-natural-number-from-1-to-900-which-are-not-divisible-2-3-and-5-

Question Number 155856 by peter frank last updated on 05/Oct/21 $$\mathrm{How}\:\mathrm{many}\:\mathrm{natural}\:\mathrm{number}\:\mathrm{from} \\ $$$$\mathrm{1}\:\mathrm{to}\:\mathrm{900}\:\mathrm{which}\:\mathrm{are}\:\mathrm{not}\:\mathrm{divisible} \\ $$$$\mathrm{2},\mathrm{3}\:\mathrm{and}\:\mathrm{5} \\ $$ Answered by TheSupreme last updated on 05/Oct/21 $$\mathrm{2},\mathrm{3}\:{and}…

Please-can-this-be-resolve-in-partial-fraction-sec-2-x-2-x-2-tan-x-1-x-2-

Question Number 90318 by I want to learn more last updated on 22/Apr/20 $$\mathrm{Please}\:\mathrm{can}\:\mathrm{this}\:\mathrm{be}\:\mathrm{resolve}\:\mathrm{in}\:\mathrm{partial}\:\mathrm{fraction}? \\ $$$$\:\:\:\:\:\:\frac{\mathrm{sec}^{\mathrm{2}} \mathrm{x}\:\:−\:\:\frac{\mathrm{2}}{\mathrm{x}^{\mathrm{2}} }}{\left(\mathrm{tan}\:\mathrm{x}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{x}}\right)^{\mathrm{2}} } \\ $$ Terms of Service Privacy…