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Category: Algebra

true-or-false-1-1-1-3-1-1-2-3-1-1-3-3-1-1-n-3-lt-3-

Question Number 89794 by M±th+et£s last updated on 19/Apr/20 $${true}\:{or}\:{false} \\ $$$$\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{3}} }\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{3}} }\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{3}} }\right)…..\left(\mathrm{1}+\frac{\mathrm{1}}{{n}^{\mathrm{3}} }\right)<\mathrm{3} \\ $$ Commented by mr W last updated on…

Question-89795

Question Number 89795 by A8;15: last updated on 19/Apr/20 Answered by MJS last updated on 19/Apr/20 $$\left({x}^{\mathrm{2}} +\mathrm{1}\right)\left({x}+\mathrm{1}\right)^{\mathrm{2}} +{x}^{\mathrm{2}} =\left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right)^{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} \left({x}^{\mathrm{2}} +\mathrm{1}\right)+\mathrm{1}=\left({x}^{\mathrm{2}}…

Evaluate-lim-n-n-n-2-

Question Number 155295 by mathdanisur last updated on 28/Sep/21 $$\mathrm{Evaluate}:\:\:\:\underset{\boldsymbol{\mathrm{n}}\rightarrow\infty} {\mathrm{lim}}\frac{\Sigma\:\boldsymbol{\mathrm{n}}}{\boldsymbol{\mathrm{n}}^{\mathrm{2}} }\:=\:? \\ $$ Commented by mathdanisur last updated on 28/Sep/21 $$\mathrm{Very}\:\mathrm{nice}\:\boldsymbol{\mathrm{S}}\mathrm{er},\:\mathrm{thank}\:\mathrm{you} \\ $$ Commented…

If-x-1-x-6-then-x-3-1-x-3-

Question Number 155259 by Fridunatjan08 last updated on 27/Sep/21 $${If}:\:{x}+\frac{\mathrm{1}}{{x}}=\mathrm{6}\:\:{then}\:\:{x}^{\mathrm{3}} +\frac{\mathrm{1}}{{x}^{\mathrm{3}} }=? \\ $$ Commented by puissant last updated on 27/Sep/21 $$\left({x}+\frac{\mathrm{1}}{{x}}\right)^{\mathrm{3}} =\:\mathrm{6}^{\mathrm{3}} \:=\:\mathrm{216} \\…

Solve-the-equation-sinx-3-sinx-cosx-

Question Number 155244 by mathdanisur last updated on 27/Sep/21 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$ \\ $$$$\left(\mathrm{sin}\boldsymbol{\mathrm{x}}\right)^{\mathrm{3}} \:+\:\mathrm{sin}\boldsymbol{\mathrm{x}}\:=\:\mathrm{cos}\boldsymbol{\mathrm{x}} \\ $$ Answered by ajfour last updated on 27/Sep/21 $$\mathrm{tan}\:{x}\left(\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{tan}\:^{\mathrm{2}}…