Question Number 90195 by I want to learn more last updated on 21/Apr/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 90194 by behi83417@gmail.com last updated on 21/Apr/20 $$\frac{\boldsymbol{\mathrm{x}}^{\mathrm{2}} }{\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{a}}}+\sqrt{\boldsymbol{\mathrm{x}}}=\boldsymbol{\mathrm{a}}\:\:\:\:\:\left(\boldsymbol{\mathrm{a}}\in\boldsymbol{\mathrm{R}}\right) \\ $$$$\mathrm{solve}\:\mathrm{for}:\:\:\mathrm{x}\:\:. \\ $$ Answered by ajfour last updated on 22/Apr/20 $${let}\:\sqrt{{x}}={t} \\ $$$${t}^{\mathrm{4}}…
Question Number 155724 by mathdanisur last updated on 03/Oct/21 $$\mathrm{Find}: \\ $$$$\frac{\mathrm{1}}{\mathrm{sin}^{\mathrm{2}} \mathrm{6}^{°} }\:+\:\frac{\mathrm{1}}{\mathrm{sin}^{\mathrm{2}} \mathrm{42}°}\:+\:\frac{\mathrm{1}}{\mathrm{sin}^{\mathrm{2}} \mathrm{66}°}\:+\:\frac{\mathrm{1}}{\mathrm{sin}^{\mathrm{2}} \mathrm{78}°}\:=\:? \\ $$ Answered by som(math1967) last updated on…
Question Number 90178 by I want to learn more last updated on 21/Apr/20 Commented by I want to learn more last updated on 21/Apr/20 $$\mathrm{I}\:\mathrm{got}\:\:\mathrm{26}.\mathrm{6}\:\mathrm{degree},\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{check}.…
Question Number 24641 by math solver last updated on 23/Nov/17 Commented by math solver last updated on 23/Nov/17 $$? \\ $$ Answered by ajfour last…
Question Number 90160 by A8;15: last updated on 21/Apr/20 Answered by TANMAY PANACEA. last updated on 21/Apr/20 $${put}\:{x}=\mathrm{1}\:{in}\:{RHS} \\ $$$$\sqrt{\mathrm{61}+\mathrm{6}−\mathrm{3}}\:=\mathrm{8} \\ $$$${put}\:{x}=\mathrm{1}\:{LHS} \\ $$$$\mathrm{16}^{\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\right)^{\mathrm{2}} }…
Question Number 90162 by I want to learn more last updated on 21/Apr/20 Answered by maths mind last updated on 21/Apr/20 $${x}={y}−\mathrm{1} \\ $$$$\Leftrightarrow\left({y}−\mathrm{2}\right)^{\mathrm{5}} +\left({y}+\mathrm{2}\right)^{\mathrm{5}}…
Question Number 90139 by jagoll last updated on 21/Apr/20 $$\mathrm{x}\:=\:\mathrm{2021}^{\mathrm{3}} −\mathrm{2019}^{\mathrm{3}} \\ $$$$\sqrt{\frac{\mathrm{x}−\mathrm{2}}{\mathrm{6}}}\:=\:? \\ $$ Commented by jagoll last updated on 21/Apr/20 $$\mathrm{x}\:=\:\left(\mathrm{p}+\mathrm{2}\right)^{\mathrm{3}} −\mathrm{p}^{\mathrm{3}} \:,\:\mathrm{p}\:=\:\mathrm{2019}…
Question Number 155667 by amin96 last updated on 03/Oct/21 Commented by Tawa11 last updated on 03/Oct/21 $$\mathrm{weldone}\:\mathrm{sir} \\ $$ Commented by amin96 last updated on…
Question Number 155650 by mathdanisur last updated on 03/Oct/21 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\sqrt{\frac{\mathrm{x}-\mathrm{a}}{\mathrm{x}-\mathrm{b}}}\:+\:\frac{\mathrm{a}}{\mathrm{x}}\:=\:\sqrt{\frac{\mathrm{x}-\mathrm{b}}{\mathrm{x}-\mathrm{a}}}\:+\:\frac{\mathrm{b}}{\mathrm{x}} \\ $$$$\mathrm{a};\mathrm{b}\in\mathbb{R}\:\:\mathrm{and}\:\:\mathrm{a}\neq\mathrm{b} \\ $$ Answered by som(math1967) last updated on 03/Oct/21 $$\sqrt{\frac{{x}−{a}}{{x}−{b}}}−\sqrt{\frac{{x}−{b}}{{x}−{a}}}=\frac{{b}−{a}}{{x}} \\…