Question Number 154986 by mathdanisur last updated on 23/Sep/21 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{system}\:\mathrm{in}\:\mathbb{R} \\ $$$$\mathrm{2x}\:=\:\frac{\mathrm{y}^{\mathrm{2}} \:-\:\mathrm{4y}\:+\:\mathrm{1}}{\mathrm{y}^{\mathrm{2}} \:-\:\mathrm{y}\:+\:\mathrm{1}} \\ $$$$\mathrm{y}\:=\:\frac{-\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{6x}\:-\:\mathrm{1}}{\mathrm{3x}^{\mathrm{2}} \:-\:\mathrm{2x}\:+\:\mathrm{3}} \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 154973 by mathdanisur last updated on 23/Sep/21 $$\mathrm{If}\:\:\mathrm{x}\:+\:\frac{\mathrm{7}}{\:\sqrt{\mathrm{x}}}\:=\:\mathrm{50} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{expression} \\ $$$$\sqrt{\mathrm{x}}\:-\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{x}}}\:=\:? \\ $$ Answered by mr W last updated on 23/Sep/21 $${let}\:{t}=\sqrt{{x}}>\mathrm{0}…
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Question Number 154980 by mathdanisur last updated on 23/Sep/21 $$\mathrm{if}\:\:\boldsymbol{\mathrm{a}}\:\:\mathrm{and}\:\:\boldsymbol{\mathrm{b}}\:\:\mathrm{are}\:\mathrm{real}\:\mathrm{numbers} \\ $$$$\mathrm{determine}\:\mathrm{a}\:\mathrm{necessary}\:\mathrm{and}\:\mathrm{sufficient} \\ $$$$\mathrm{condition}\:\mathrm{so}\:\mathrm{as}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\mathrm{x}^{\mathrm{2}} \:+\:\frac{\mathrm{a}\sqrt{\mathrm{b}}}{\mathrm{x}}\:=\:\mathrm{a}\:+\:\mathrm{b} \\ $$$$\mathrm{to}\:\mathrm{have}\:\mathrm{three}\:\mathrm{real}\:\mathrm{distinct}\:\mathrm{roots}. \\ $$ Answered by mr W…
Question Number 154959 by mathdanisur last updated on 23/Sep/21 $$\mathrm{Consider}\:\mathrm{the}\:\mathrm{polynomial} \\ $$$$\mathrm{P}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{10}} -\mathrm{6x}^{\mathrm{9}} -\mathrm{11x}^{\mathrm{8}} +\mathrm{3x}^{\mathrm{2}} -\mathrm{18x}-\mathrm{7} \\ $$$$\mathrm{Calculate}:\:\:\mathrm{P}\left(\mathrm{3}+\mathrm{2}\sqrt{\mathrm{5}}\right) \\ $$ Commented by prakash jain last…
Question Number 23884 by Tinkutara last updated on 09/Nov/17 $$\mathrm{If}\:{C}_{{r}} \:\mathrm{stands}\:\mathrm{for}\:^{{n}} {C}_{{r}} \:=\:\frac{{n}!}{{r}!\:{n}\:−\:{r}!}\:\mathrm{and} \\ $$$$\underset{{r}=\mathrm{1}} {\overset{{n}} {\sum}}{r}.{C}_{{r}} ^{\mathrm{2}} \:=\:\lambda\:\mathrm{for}\:{n}\:\geqslant\:\mathrm{2},\:\mathrm{then}\:\lambda\:\mathrm{is}\:\mathrm{divisible} \\ $$$$\mathrm{by} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{3}\:\left({n}\:−\:\mathrm{1}\right) \\ $$$$\left(\mathrm{2}\right)\:{n}\:+\:\mathrm{1}…
Question Number 154948 by mathdanisur last updated on 23/Sep/21 $$\mathrm{If}\:\:\overset{\rightarrow} {\mathrm{a}}\:=\:\left(-\mathrm{1};\mathrm{0};-\mathrm{3};\mathrm{4}\right) \\ $$$$\:\:\:\:\:\:\overset{\rightarrow} {\mathrm{b}}\:=\:\left(\mathrm{1};-\mathrm{4};\mathrm{0};-\mathrm{3}\right) \\ $$$$\:\:\:\:\:\:\overset{\rightarrow} {\mathrm{c}}\:=\:\frac{\mid\overset{\rightarrow} {\mathrm{a}}\mid}{\mid\overset{\rightarrow} {\mathrm{b}}\mid}\:\centerdot\:\left(\mathrm{2}\overset{\rightarrow} {\mathrm{a}}\:+\:\overset{\rightarrow} {\mathrm{b}}\right) \\ $$$$\:\:\:\:\:\:\:\overset{\rightarrow} {\mathrm{d}}\:=\:\frac{\mid\overset{\rightarrow} {\mathrm{b}}\mid}{\mid\overset{\rightarrow}…
Question Number 154942 by Tawa11 last updated on 23/Sep/21 Answered by prakash jain last updated on 23/Sep/21 $$\mathrm{You}\:\mathrm{need}\:\mathrm{to}\:\mathrm{take}\:\mathrm{16}\:\mathrm{steps},\:\mathrm{8}\:\mathrm{down} \\ $$$$\mathrm{and}\:\mathrm{8}\:\mathrm{right}. \\ $$$$\mathrm{The}\:\mathrm{problem}\:\mathrm{is}\:\mathrm{simply}\:\mathrm{choosing} \\ $$$$\mathrm{8}\:\mathrm{down}\:\mathrm{steps}\:\mathrm{among}\:\mathrm{available}\:\mathrm{16} \\…
Question Number 89385 by pete last updated on 17/Apr/20 Commented by pete last updated on 17/Apr/20 $$\:\mathrm{I}\:\mathrm{need}\:\mathrm{help}\:\mathrm{on}\:\mathrm{the}\:\mathrm{above}\:\mathrm{question},\:\mathrm{please}. \\ $$ Answered by Joel578 last updated on…
Question Number 154893 by mathdanisur last updated on 22/Sep/21 Terms of Service Privacy Policy Contact: info@tinkutara.com