Question Number 89271 by jagoll last updated on 16/Apr/20 $$\frac{\mathrm{3}}{\mathrm{4}}×\frac{\mathrm{8}}{\mathrm{9}}×\frac{\mathrm{15}}{\mathrm{16}}×…×\frac{\mathrm{2499}}{\mathrm{2500}} \\ $$ Commented by john santu last updated on 16/Apr/20 $$\frac{\mathrm{2}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }×\frac{\mathrm{3}^{\mathrm{2}} −\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }×\frac{\mathrm{4}^{\mathrm{2}}…
Question Number 154791 by azadsir last updated on 21/Sep/21 Answered by Ar Brandon last updated on 24/Sep/21 $${S}=\mathrm{9}^{\mathrm{2}} +\mathrm{7}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} +\mathrm{1}^{\mathrm{2}} +\left(−\mathrm{1}\right)^{\mathrm{2}} +\left(−\mathrm{3}\right)^{\mathrm{2}} +\centerdot\centerdot\centerdot+\left(−\mathrm{25}\right)^{\mathrm{2}}…
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Question Number 89239 by Tinku Tara last updated on 16/Apr/20 $$\mathrm{A}\:\mathrm{new}\:\mathrm{update}\:\mathrm{has}\:\mathrm{been}\:\mathrm{released}\:\mathrm{to} \\ $$$$\mathrm{fix}\:\mathrm{issues}\:\mathrm{with}\:\mathrm{android}\:\mathrm{10}.\:\mathrm{If}\:\mathrm{you} \\ $$$$\mathrm{have}\:\mathrm{android}\:\mathrm{10}\:\mathrm{phone}\:\mathrm{please}\:\mathrm{download} \\ $$$$\mathrm{latest}\:\mathrm{update}. \\ $$ Commented by jagoll last updated on…
Question Number 23700 by Tinkutara last updated on 04/Nov/17 $$\mathrm{If}\:\left(\mathrm{1}\:−\:{x}^{\mathrm{3}} \right)^{{n}} \:=\:\underset{{r}=\mathrm{0}} {\overset{{n}} {\sum}}{a}_{{r}} {x}^{{r}} \left(\mathrm{1}\:−\:{x}\right)^{\mathrm{3}{n}−\mathrm{2}{r}} ,\:\mathrm{then} \\ $$$$\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{a}_{{r}} ,\:\mathrm{where}\:{n}\:\in\:{N}\:\mathrm{is} \\ $$$$\left(\mathrm{1}\right)\:^{{n}} {C}_{{r}} \centerdot\mathrm{3}^{{r}} \\…
Question Number 23687 by tawa tawa last updated on 03/Nov/17 $$\mathrm{Solve}\:\mathrm{for}\:\:\mathrm{x},\:\mathrm{y}\:\mathrm{and}\:\mathrm{z} \\ $$$$\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{yz}\:=\:\mathrm{1}\:\:\:\:\:\:……….\:\left(\mathrm{i}\right) \\ $$$$\mathrm{y}^{\mathrm{2}} \:−\:\mathrm{xz}\:=\:\mathrm{4}\:\:\:\:\:\:……….\:\left(\mathrm{i}\right) \\ $$$$\mathrm{z}^{\mathrm{2}} \:−\:\mathrm{xy}\:=\:\mathrm{9}\:\:\:\:\:\:……….\:\left(\mathrm{i}\right) \\ $$ Answered by ajfour…
Question Number 154758 by mathdanisur last updated on 21/Sep/21 $$\mathrm{if}\:\:\mathrm{x};\mathrm{y};\mathrm{z}\geqslant\mathrm{0}\:\:\mathrm{and}\:\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} =\mathrm{1} \\ $$$$\mathrm{then}\:\mathrm{prove}\:\mathrm{that}: \\ $$$$\frac{\mathrm{x}\:+\:\mathrm{y}\:+\:\mathrm{z}}{\mathrm{1}\:+\:\mathrm{xy}}\:\leqslant\:\sqrt{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 154740 by pete last updated on 21/Sep/21 $$\mathrm{A}\:\mathrm{man}\:\mathrm{will}\:\mathrm{be}\:\left({x}+\mathrm{10}\right)\:\mathrm{years}\:\mathrm{in}\:\mathrm{8}\:\mathrm{years}\:\mathrm{time}. \\ $$$$\mathrm{If}\:\mathrm{2}\:\mathrm{years}\:\mathrm{ago}\:\mathrm{he}\:\mathrm{was}\:\mathrm{63}\:\mathrm{years},\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{value}\:\mathrm{of}\:{x}. \\ $$ Answered by talminator2856791 last updated on 21/Sep/21 $$\: \\…
Question Number 154736 by mathdanisur last updated on 21/Sep/21 Commented by Tawa11 last updated on 21/Sep/21 $$\mathrm{Weldone}\:\mathrm{sir}. \\ $$ Answered by mr W last updated…