Question Number 154734 by imjagoll last updated on 21/Sep/21 $$\:\begin{cases}{\mathrm{x}=\left(\mathrm{y}−\mathrm{2}\right)\left(\mathrm{y}+\mathrm{2}\right)}\\{\mathrm{y}=\left(\mathrm{z}−\mathrm{2}\right)\left(\mathrm{z}+\mathrm{2}\right)}\\{\mathrm{z}=\left(\mathrm{x}−\mathrm{2}\right)\left(\mathrm{x}+\mathrm{2}\right)}\end{cases}\:;\:\mathrm{x}\neq\mathrm{0},\:\mathrm{y}\neq\mathrm{0},\:\mathrm{z}\neq\mathrm{0} \\ $$$$\Rightarrow\:\mathrm{x}^{\mathrm{5}} +\mathrm{y}^{\mathrm{5}} +\mathrm{z}^{\mathrm{5}} \:=? \\ $$ Answered by MJS_new last updated on 21/Sep/21 $$\mathrm{not}\:\mathrm{unique}…
Question Number 89187 by TawaTawa1 last updated on 16/Apr/20 Commented by jagoll last updated on 16/Apr/20 $$\sqrt{\mathrm{8}{xy}−\mathrm{1}}\:=\:{t}\: \\ $$$$\mathrm{8}{xy}\:=\:{t}^{\mathrm{2}} +\mathrm{1}\:\Rightarrow\sqrt{\mathrm{8}{xy}}\:=\:\sqrt{{t}^{\mathrm{2}} +\mathrm{1}} \\ $$$$\mathrm{4}{y}\:=\:\frac{{t}^{\mathrm{2}} +\mathrm{1}}{\mathrm{2}{x}}\: \\…
Question Number 89172 by M±th+et£s last updated on 15/Apr/20 Answered by mahdi last updated on 15/Apr/20 $$\left(\frac{\mathrm{x}^{\mathrm{1}} .\mathrm{x}^{\frac{−\mathrm{b}}{\mathrm{a}}} .\mathrm{x}^{\frac{\mathrm{1}}{\mathrm{a}}} .\mathrm{x}^{\frac{\mathrm{b}}{\mathrm{a}^{\mathrm{2}} }} }{\mathrm{x}^{\frac{\mathrm{b}}{\mathrm{a}^{\mathrm{2}} }} .\mathrm{x}^{\frac{\mathrm{a}}{\mathrm{a}}} }\right)^{\frac{\mathrm{1}}{\mathrm{b}−\mathrm{1}}}…
Question Number 23644 by Tinkutara last updated on 03/Nov/17 $${Prove}\:{that}\:\underset{{r}=\mathrm{0}} {\overset{{n}} {\sum}}{r}.^{{n}} {C}_{{r}} \:{z}^{{r}} \:=\:{nz}\left(\mathrm{1}\:+\:{z}\right)^{{n}−\mathrm{1}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 154710 by mathdanisur last updated on 20/Sep/21 $$\mathrm{Find}: \\ $$$$\underset{\boldsymbol{\mathrm{n}}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\left(\mathrm{n}+\mathrm{1}\right)^{\mathrm{2}} }{\:\sqrt[{\boldsymbol{\mathrm{n}}+\mathrm{1}}]{\mathrm{2}\left(\mathrm{n}+\mathrm{1}\right)!}}\:-\:\frac{\mathrm{n}^{\mathrm{2}} }{\:\sqrt[{\boldsymbol{\mathrm{n}}}]{\mathrm{2n}!}}\right)\:=\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 89153 by Jidda28 last updated on 15/Apr/20 $$\mathrm{If}\:\mathrm{P}=\frac{\mathrm{RE}^{\mathrm{2}} }{\left(\mathrm{R}+\mathrm{B}\right)^{\mathrm{2}} }\:\mathrm{make}\:\mathrm{R}\:\mathrm{the}\:\mathrm{subject}\:\mathrm{of}\:\mathrm{the}\:\mathrm{formula}. \\ $$ Answered by MJS last updated on 15/Apr/20 $${p}\left({r}+{b}\right)^{\mathrm{2}} ={re}^{\mathrm{2}} \\ $$$$\left({r}+{b}\right)^{\mathrm{2}}…
Question Number 154677 by mathdanisur last updated on 20/Sep/21 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\frac{\mathrm{x}^{\mathrm{9}} \:-\:\mathrm{256x}^{\mathrm{3}} \:-\:\mathrm{791}}{\mathrm{84x}^{\mathrm{3}} }\:=\:\sqrt[{\mathrm{3}}]{\mathrm{4x}\:+\:\mathrm{7}} \\ $$ Commented by MJS_new last updated on 20/Sep/21 $$\frac{{x}^{\mathrm{9}}…
Question Number 154675 by mathdanisur last updated on 20/Sep/21 $$\mathrm{if}\:\mathrm{we}\:\mathrm{let} \\ $$$$\mathrm{f}\left(\mathrm{n}\right)\:=\:\frac{\mathrm{n}}{\mathrm{2}}\:\left(\mathrm{n}\:+\:\mathrm{1}\right) \\ $$$$\mathrm{then}\:\mathrm{solve}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers} \\ $$$$\mathrm{f}\left(\mathrm{f}\left(\mathrm{f}\left(\mathrm{f}\left(\mathrm{n}\right)\right)\right)\right)\:=\:\frac{\mathrm{1}}{\mathrm{32}} \\ $$ Answered by MJS_new last updated on 20/Sep/21…
Question Number 89130 by 43100Maryam last updated on 15/Apr/20 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 89125 by pete last updated on 15/Apr/20 Answered by MJS last updated on 15/Apr/20 $$\mathrm{We}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\ $$$${x}\approx\mathrm{1}.\mathrm{69010} \\ $$ Terms of Service Privacy…