Question Number 88881 by Power last updated on 13/Apr/20 Answered by mahdi last updated on 13/Apr/20 $$\mathrm{A}=\sqrt{\mathrm{4}+\sqrt{\mathrm{4}+\sqrt{\mathrm{4}−\sqrt{\mathrm{4}+\sqrt{\mathrm{4}+\sqrt{\mathrm{4}−…}}}}}} \\ $$$$\mathrm{A}=\sqrt{\mathrm{4}+\sqrt{\mathrm{4}+\sqrt{\mathrm{4}−\mathrm{A}}}}\Rightarrow\mathrm{A}^{\mathrm{2}} =\mathrm{4}+\sqrt{\mathrm{4}+\sqrt{\mathrm{4}−\mathrm{A}}} \\ $$$$\mathrm{A}\backsimeq\mathrm{2}.\mathrm{5070} \\ $$ Terms…
Question Number 88873 by jagoll last updated on 13/Apr/20 $$\mathrm{3}+\sqrt{{x}^{\mathrm{2}} −\mathrm{5}}\:>\:\mid{x}−\mathrm{1}\mid\: \\ $$ Commented by john santu last updated on 13/Apr/20 $$\Rightarrow\left(\mathrm{3}+\sqrt{{x}^{\mathrm{2}} −\mathrm{5}}\right)^{\mathrm{2}} \:>\:\left({x}−\mathrm{1}\right)^{\mathrm{2}} \\…
Question Number 23334 by math solver last updated on 28/Oct/17 Commented by math solver last updated on 28/Oct/17 $$\mathrm{find}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{above}\:\mathrm{series}\:? \\ $$ Commented by ajfour last…
Question Number 154400 by mathdanisur last updated on 18/Sep/21 $$\mathrm{x}\sqrt{\mathrm{y}}\:-\:\mathrm{y}\sqrt{\mathrm{x}}\:=\:\mathrm{82} \\ $$$$\mathrm{x}\sqrt{\mathrm{x}}\:+\:\mathrm{y}\sqrt{\mathrm{y}}\:=\:\mathrm{83} \\ $$$$\frac{\mathrm{9}}{\mathrm{5}}\:\centerdot\:\left(\mathrm{x}\:+\:\mathrm{y}\right)\:=\:? \\ $$ Answered by TheHoneyCat last updated on 20/Sep/21 $$\mathrm{just}\:\mathrm{so}\:\mathrm{you}\:\mathrm{understand}\:\mathrm{my}\:\mathrm{mess}\:\left(\mathrm{1}\right)\:\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{first}\:\mathrm{equation}\:\mathrm{and}\:\left(\mathrm{2}\right)\:\mathrm{the}\:\mathrm{other} \\…
Question Number 154401 by mathdanisur last updated on 18/Sep/21 $$\mathrm{prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{sum} \\ $$$$\mathrm{2}+\mathrm{2}^{\mathrm{2}} +\mathrm{2}^{\mathrm{3}} +\mathrm{2}^{\mathrm{4}} +…+\mathrm{2}^{\mathrm{2019}} +\mathrm{2}^{\mathrm{2020}} \\ $$$$\mathrm{is}\:\mathrm{divisible}\:\:\mathrm{by}\:\:\mathrm{30} \\ $$ Answered by talminator2856791 last updated…
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Question Number 23323 by Tinkutara last updated on 28/Oct/17 Commented by Tinkutara last updated on 28/Oct/17 $${Prove}\:{that}\uparrow. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 154385 by amin96 last updated on 17/Sep/21 $${if}\:\:\:\sqrt[{\mathrm{3}}]{{x}}−\sqrt[{\mathrm{3}}]{{x}−\mathrm{36}}=\mathrm{3}\:\:\:\:\:\:{find}\:\:\:\:{x}−\frac{\mathrm{1}}{{x}} \\ $$ Answered by amin96 last updated on 18/Sep/21 $${x}={t}^{\mathrm{3}} \:\:\:\Rightarrow\:\:\:{t}−\sqrt[{\mathrm{3}}]{{t}^{\mathrm{3}} −\mathrm{36}}=\mathrm{3}\:\:\Rightarrow\:\:\sqrt[{\mathrm{3}}]{{t}^{\mathrm{3}} −\mathrm{36}}={t}−\mathrm{3} \\ $$$${t}^{\mathrm{3}}…
Question Number 154384 by mathdanisur last updated on 17/Sep/21 $$\mathrm{If}\:\:\mathrm{x};\mathrm{y};\mathrm{z}>\mathrm{0}\:\:\mathrm{then}: \\ $$$$\frac{\mathrm{4x}^{\mathrm{2}} }{\mathrm{x}+\mathrm{y}}\:+\:\frac{\mathrm{8y}^{\mathrm{2}} }{\mathrm{y}+\mathrm{z}}\:+\:\frac{\mathrm{4z}^{\mathrm{2}} }{\mathrm{z}+\mathrm{x}}\:\geqslant\:\mathrm{2x}\:+\:\mathrm{5y}\:+\:\mathrm{z} \\ $$ Answered by ghimisi last updated on 18/Sep/21 $$\mathrm{4}\left(\frac{{x}^{\mathrm{2}}…
Question Number 154380 by liberty last updated on 17/Sep/21 Answered by EDWIN88 last updated on 18/Sep/21 Commented by Tawa11 last updated on 21/Sep/21 $$\mathrm{Nice}\:\mathrm{sir} \\…