Question Number 88678 by Cheyboy last updated on 12/Apr/20 $$\boldsymbol{\mathrm{F}}{ind}\:\:\:\sqrt{\boldsymbol{{i}}}+\sqrt{−\boldsymbol{\mathrm{i}}} \\ $$ Commented by mr W last updated on 12/Apr/20 $${both}\:{definitions}\:{are}\:{used}\:\left({in}\:{different}\right. \\ $$$$\left.{countries}\right): \\ $$$$−\pi<{Arg}\left({z}\right)\leqslant\pi\:{or}…
Question Number 154204 by mathdanisur last updated on 15/Sep/21 Commented by Rasheed.Sindhi last updated on 16/Sep/21 $$\boldsymbol{\mathrm{Sorry}}\:\mathrm{that}\:\mathrm{I}\:\mathrm{neglect}\:“\:\frac{\mathrm{tan}\alpha\:}{\mathrm{tan}\beta\:}\:\in\mathbb{Z}^{+} \:''. \\ $$$$\mathrm{Now}\:\mathrm{the}\:\mathrm{question}\:\mathrm{can}\:\mathrm{be}\:\mathrm{solved}\:\mathrm{for} \\ $$$$\mathrm{some}\:\mathrm{fixed}\:\mathrm{answers}. \\ $$ Answered…
Question Number 154200 by amin96 last updated on 15/Sep/21 $${g}\left(\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}\right)=\frac{\mathrm{7}{x}+\mathrm{3}}{{x}+\mathrm{1}}\:\:{and}\:\:{f}\left({x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{3}\right)=\mathrm{3}{x}^{\mathrm{2}} −\mathrm{6}{x}+\mathrm{7} \\ $$$${find}\:\:\left({f}+{g}\right)\left({x}\right)=?\:\:\: \\ $$ Answered by Rasheed.Sindhi last updated on 15/Sep/21 $${g}\left(\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}\right)=\frac{\mathrm{7}{x}+\mathrm{3}}{{x}+\mathrm{1}}\:\:{and}\:\:{f}\left({x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{3}\right)=\mathrm{3}{x}^{\mathrm{2}}…
Question Number 154202 by mathdanisur last updated on 15/Sep/21 $$\boldsymbol{\Omega}\:\:=\underset{\:\mathrm{0}} {\overset{\:\infty} {\int}}\:\frac{\mathrm{ln}\centerdot\left(\mathrm{1}\:+\:\mathrm{x}\right)}{\mathrm{x}\centerdot\left(\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{x}\:+\:\mathrm{1}\right)}\:\mathrm{dx}\:=\:? \\ $$ Answered by qaz last updated on 15/Sep/21 $$\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{ln}\left(\mathrm{1}+\mathrm{x}\right)}{\mathrm{x}\left(\mathrm{x}^{\mathrm{2}}…
Question Number 88642 by M±th+et£s last updated on 11/Apr/20 Commented by ajfour last updated on 11/Apr/20 $${x}=\frac{\pi}{\mathrm{4}}\:,\:\:{of}\:{course}\:{qualifies}. \\ $$$${both}\:{terms}\:{are}\:{zero}. \\ $$ Commented by M±th+et£s last…
Question Number 154177 by EDWIN88 last updated on 15/Sep/21 Commented by Tawa11 last updated on 15/Sep/21 $$\mathrm{nice} \\ $$ Commented by EDWIN88 last updated on…
Question Number 23096 by tawa tawa last updated on 26/Oct/17 $$\mathrm{Solve}:\:\:\mathrm{3}^{\mathrm{x}\:} =\:\frac{\mathrm{27}}{\mathrm{x}}\:+\:\mathrm{18} \\ $$ Commented by Physics lover last updated on 26/Oct/17 $${i}\:{just}\:{used}\:{hit}\:{and}\:{trial}\:{method} \\ $$$${and}\:{got}\:{x}\:=\:\mathrm{3}…
Question Number 154148 by mathdanisur last updated on 14/Sep/21 $$\boldsymbol{{z}}^{\mathrm{4}} \:-\:\frac{\mathrm{50}}{\mathrm{2}\boldsymbol{{z}}^{\mathrm{4}} \:-\:\mathrm{7}}\:=\:\mathrm{14}\:\:\:\Rightarrow\:\:\:\boldsymbol{{z}}\:=\:? \\ $$ Answered by puissant last updated on 14/Sep/21 $$\Rightarrow\:\mathrm{2}{z}^{\mathrm{8}} −\mathrm{7}{z}^{\mathrm{4}} −\mathrm{50}=\mathrm{28}{z}^{\mathrm{4}} −\mathrm{98}…
Question Number 88611 by M±th+et£s last updated on 11/Apr/20 $${prove}\:{that} \\ $$$$\frac{\mathrm{1}+{p}^{\mathrm{2}} +{p}^{\mathrm{4}} +……+{p}^{\mathrm{2}{n}} }{{p}+{p}^{\mathrm{3}} +{p}^{\mathrm{5}} +…..{p}^{\mathrm{2}{n}−\mathrm{1}} }>\frac{{n}+\mathrm{1}}{{np}} \\ $$ Terms of Service Privacy Policy…
Question Number 88610 by M±th+et£s last updated on 11/Apr/20 $${is}\:\mathrm{1}×\mathrm{1}×\mathrm{1}×……….=\mathrm{1}^{\infty} \: \\ $$$${or} \\ $$$$\:\mathrm{1}×\mathrm{1}×\mathrm{1}×\mathrm{1}×\mathrm{1}×……….=\mathrm{1} \\ $$$$ \\ $$$$ \\ $$ Commented by mahdi last…