Question Number 154948 by mathdanisur last updated on 23/Sep/21 $$\mathrm{If}\:\:\overset{\rightarrow} {\mathrm{a}}\:=\:\left(-\mathrm{1};\mathrm{0};-\mathrm{3};\mathrm{4}\right) \\ $$$$\:\:\:\:\:\:\overset{\rightarrow} {\mathrm{b}}\:=\:\left(\mathrm{1};-\mathrm{4};\mathrm{0};-\mathrm{3}\right) \\ $$$$\:\:\:\:\:\:\overset{\rightarrow} {\mathrm{c}}\:=\:\frac{\mid\overset{\rightarrow} {\mathrm{a}}\mid}{\mid\overset{\rightarrow} {\mathrm{b}}\mid}\:\centerdot\:\left(\mathrm{2}\overset{\rightarrow} {\mathrm{a}}\:+\:\overset{\rightarrow} {\mathrm{b}}\right) \\ $$$$\:\:\:\:\:\:\:\overset{\rightarrow} {\mathrm{d}}\:=\:\frac{\mid\overset{\rightarrow} {\mathrm{b}}\mid}{\mid\overset{\rightarrow}…
Question Number 154942 by Tawa11 last updated on 23/Sep/21 Answered by prakash jain last updated on 23/Sep/21 $$\mathrm{You}\:\mathrm{need}\:\mathrm{to}\:\mathrm{take}\:\mathrm{16}\:\mathrm{steps},\:\mathrm{8}\:\mathrm{down} \\ $$$$\mathrm{and}\:\mathrm{8}\:\mathrm{right}. \\ $$$$\mathrm{The}\:\mathrm{problem}\:\mathrm{is}\:\mathrm{simply}\:\mathrm{choosing} \\ $$$$\mathrm{8}\:\mathrm{down}\:\mathrm{steps}\:\mathrm{among}\:\mathrm{available}\:\mathrm{16} \\…
Question Number 89385 by pete last updated on 17/Apr/20 Commented by pete last updated on 17/Apr/20 $$\:\mathrm{I}\:\mathrm{need}\:\mathrm{help}\:\mathrm{on}\:\mathrm{the}\:\mathrm{above}\:\mathrm{question},\:\mathrm{please}. \\ $$ Answered by Joel578 last updated on…
Question Number 154893 by mathdanisur last updated on 22/Sep/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 154892 by mathdanisur last updated on 22/Sep/21 $$\mathrm{Find}: \\ $$$$\mathrm{cos}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right)\:+\:\mathrm{cos}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right)\:\sqrt{\mathrm{2}\:-\:\mathrm{2cos}\left(\frac{\mathrm{3}\pi}{\mathrm{7}}\right)}\:=\:? \\ $$ Commented by MJS_new last updated on 23/Sep/21 $$\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Commented…
Question Number 23814 by tawa tawa last updated on 06/Nov/17 Commented by tawa tawa last updated on 06/Nov/17 $$\mathrm{please}\:\mathrm{help}. \\ $$ Answered by mrW1 last…
Question Number 89344 by jagoll last updated on 17/Apr/20 $$\left(\mathrm{2}{x}−\mathrm{1}\right)^{\mathrm{2}} +\mathrm{8}\sqrt{\mathrm{2}{xy}}\:=\:\mathrm{4} \\ $$$$\mathrm{4}{y}−\sqrt{\mathrm{8}{xy}−\mathrm{1}}\:=\:\mathrm{1} \\ $$ Commented by john santu last updated on 17/Apr/20 $$\mathrm{8}{xy}−\mathrm{1}\:=\:\mathrm{16}{y}^{\mathrm{2}} −\mathrm{8}{y}+\mathrm{1}…
Question Number 154875 by mathdanisur last updated on 22/Sep/21 Answered by mindispower last updated on 23/Sep/21 $${u}={log}\left({x}+\frac{\mathrm{5}}{{x}}\right) \\ $$$$\Omega\Leftrightarrow\int{e}^{\mathrm{2}{u}} {sin}\left({u}\right){du} \\ $$ Commented by mathdanisur…
Question Number 89300 by I want to learn more last updated on 16/Apr/20 $$. \\ $$ Commented by I want to learn more last updated…
Question Number 89292 by student work last updated on 16/Apr/20 Answered by jagoll last updated on 16/Apr/20 $${x}+{y}\:=\:\mathrm{20}\:\left({i}\right) \\ $$$${y}+{z}\:=\:\mathrm{10}\:\left({ii}\right) \\ $$$${x}+{u}\:=\:\mathrm{24}\:\left({iii}\right) \\ $$$$\frac{{u}}{{z}}\:=\:\mathrm{7}\:\Rightarrow{u}\:=\:\mathrm{7}{z}\:\left({iv}\right) \\…