Question Number 154012 by mathdanisur last updated on 13/Sep/21 $$\mathrm{Determine}\:\mathrm{all}\:\mathrm{the}\:\mathrm{perfect}\:\mathrm{squares}\:\mathrm{on} \\ $$$$\mathrm{form}\:\:\boldsymbol{\mathrm{p}}^{\boldsymbol{\mathrm{n}}} \:+\:\mathrm{1}\:\:\mathrm{where}\:\:\boldsymbol{\mathrm{p}}\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{prime}\:\mathrm{number} \\ $$$$\mathrm{and}\:\:\boldsymbol{\mathrm{n}}\:\:\mathrm{a}\:\mathrm{positive}\:\mathrm{integer}. \\ $$ Commented by Rasheed.Sindhi last updated on 13/Sep/21 $$\mathrm{For}\:\mathrm{some}\:\mathrm{cases}…
Question Number 154013 by mathdanisur last updated on 13/Sep/21 $$\mathrm{Prove}\:\mathrm{without}\:\mathrm{any}\:\mathrm{software} \\ $$$$\underset{\:\frac{\mathrm{1}}{\mathrm{2}}} {\overset{\:\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}} {\int}}\:\frac{\mathrm{1}}{\mathrm{x}}\:\mathrm{log}\left(\mathrm{1}+\mathrm{2x}^{\mathrm{2}} +\mathrm{x}^{\mathrm{4}} \right)\mathrm{dx}\:<\:\sqrt{\mathrm{7}}\:-\:\sqrt{\mathrm{5}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 154015 by mathdanisur last updated on 13/Sep/21 $$\mathrm{If}\:\:\mathrm{x};\mathrm{y};\mathrm{z}>\mathrm{0}\:\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}: \\ $$$$\frac{\mathrm{x}}{\mathrm{x}^{\mathrm{2}} +\mathrm{yz}}\:+\:\frac{\mathrm{y}}{\mathrm{y}^{\mathrm{2}} +\mathrm{zx}}\:+\:\frac{\mathrm{z}}{\mathrm{z}^{\mathrm{2}} +\mathrm{xy}}\:\leqslant\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} }{\mathrm{2xyz}} \\ $$ Terms of Service Privacy Policy…
Question Number 154011 by mathdanisur last updated on 13/Sep/21 $$\Omega\:=\underset{\:\mathrm{0}} {\overset{\:\frac{\boldsymbol{\pi}}{\mathrm{12}}} {\int}}\mathrm{x}\left(\mathrm{tan}\boldsymbol{\mathrm{x}}\:+\:\mathrm{cot}\boldsymbol{\mathrm{x}}\right)\:\mathrm{dx}\:=\:? \\ $$ Commented by alisiao last updated on 13/Sep/21 $$\Omega\:=\:\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{12}}} \:{x}\:{sec}^{\mathrm{2}} {x}\:{dx}…
Question Number 88458 by TawaTawa1 last updated on 10/Apr/20 $$\mathrm{Using}\:\mathrm{the}\:\mathrm{principle}\:\mathrm{of}\:\mathrm{mathematical}\:\mathrm{induction}\:\mathrm{to}\:\mathrm{prove} \\ $$$$\mathrm{that}\:\:\:\mathrm{a}_{\mathrm{1}} \:,\:\:\:\mathrm{a}_{\mathrm{2}} \:,\:\:…\:,\:\mathrm{a}_{\mathrm{n}} \:,\:\:\frac{\mathrm{a}_{\mathrm{1}} \:+\:\mathrm{a}_{\mathrm{2}} \:+\:…\:+\:\mathrm{a}_{\mathrm{n}} }{\mathrm{n}}\:\:\:\:\geqslant\:\:\:\sqrt[{\mathrm{n}}]{\mathrm{a}_{\mathrm{1}} \:,\:\:\mathrm{a}_{\mathrm{2}} \:,\:\:…\:,\:\mathrm{a}_{\mathrm{n}} } \\ $$ Terms of…
Question Number 153988 by mathdanisur last updated on 12/Sep/21 $$\mathrm{let}\:\:\mathrm{a};\mathrm{b}\:\:\mathrm{be}\:\mathrm{positive}\:\mathrm{real}\:\mathrm{numbers} \\ $$$$\mathrm{such}\:\mathrm{that}\:\:\mathrm{a}+\mathrm{b}=\mathrm{2}\:\:\mathrm{prove}\:\mathrm{that}: \\ $$$$\frac{\mathrm{1}}{\mathrm{a}^{\boldsymbol{\mathrm{n}}} }\:+\:\frac{\mathrm{1}}{\mathrm{b}^{\boldsymbol{\mathrm{n}}} }\:\geqslant\:\mathrm{a}^{\boldsymbol{\mathrm{n}}+\mathrm{1}} \:+\:\mathrm{b}^{\boldsymbol{\mathrm{n}}+\mathrm{1}} \:\:;\:\:\forall\mathrm{n}\in\mathbb{N}^{\ast} \\ $$ Answered by metamorfose last updated…
Question Number 153989 by mathdanisur last updated on 12/Sep/21 $$\mathrm{find}\:\mathrm{all}\:\mathrm{functions}\:\:\mathrm{f}\::\:\mathbb{R}\rightarrow\mathbb{R}\:\:\mathrm{with}\:\mathrm{the} \\ $$$$\mathrm{property}\:\mathrm{that} \\ $$$$\mathrm{f}\left(\mathrm{f}\left(\mathrm{x}\right)\:+\:\mathrm{2y}\:=\:\mathrm{10x}\:+\:\mathrm{f}\left(\mathrm{f}\left(\mathrm{y}\right)-\mathrm{3x}\right)\right. \\ $$$$\mathrm{holds}\:\mathrm{for}\:\mathrm{all}\:\:\mathrm{a};\mathrm{b}\in\mathbb{R} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 22856 by FilupS last updated on 23/Oct/17 $$\mathrm{solve}:\:\mathrm{sin}\left({x}\right)=\mathrm{2},\:\:\:{x}\in\mathbb{C} \\ $$ Commented by Tinkutara last updated on 23/Oct/17 $${Write}\:{as}\:{e}^{{i}\theta} =\mathrm{cos}\:\theta+{i}\mathrm{sin}\:\theta\:{and} \\ $$$${e}^{−{i}\theta} =\mathrm{cos}\:\theta−{i}\mathrm{sin}\:\theta \\…
Question Number 153920 by alisiao last updated on 12/Sep/21 Terms of Service Privacy Policy Contact: info@tinkutara.com