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Category: Algebra

S-x-2x-2-nx-n-

Question Number 153847 by mathdanisur last updated on 11/Sep/21 $$\boldsymbol{\mathrm{S}}\:=\:\mathrm{x}\:+\:\mathrm{2x}^{\mathrm{2}} \:+\:…\:+\:\mathrm{nx}^{\boldsymbol{\mathrm{n}}} \\ $$$$ \\ $$ Answered by liberty last updated on 11/Sep/21 $$\:{S}={x}+\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}{x}^{\mathrm{3}} +\mathrm{4}{x}^{\mathrm{4}}…

Question-153839

Question Number 153839 by liberty last updated on 11/Sep/21 Commented by mathdanisur last updated on 11/Sep/21 $$\mathrm{x}\left(\mathrm{1}\:+\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{2}}\:+\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{2}+\mathrm{3}}\:+\:…\:+\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{2}+…+\mathrm{4041}}\right)\:=\:\mathrm{4041} \\ $$$$\blacktriangle\:\boldsymbol{\mathrm{A}}\:=\:\mathrm{1}\:+\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{2}}\:+\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{2}+\mathrm{3}}\:+\:…\:+\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{2}+…+\boldsymbol{\mathrm{n}}}\:=\:\frac{\mathrm{2}\boldsymbol{\mathrm{n}}}{\boldsymbol{\mathrm{n}}\:+\:\mathrm{1}} \\ $$$$\boldsymbol{\mathrm{n}}\:=\:\mathrm{4041}\:\Rightarrow\:\boldsymbol{\mathrm{A}}\:=\:\frac{\mathrm{2}\:\centerdot\:\mathrm{4041}}{\mathrm{4041}\:+\:\mathrm{1}}\:=\:\frac{\mathrm{2}\:\centerdot\:\mathrm{4041}}{\mathrm{2}\:\centerdot\:\mathrm{2021}}\:=\:\frac{\mathrm{4041}}{\mathrm{2021}} \\ $$$$\Rightarrow\:\boldsymbol{\mathrm{x}}\:\centerdot\:\frac{\mathrm{4041}}{\mathrm{2021}}\:=\:\mathrm{4041}\:\Rightarrow\:\boldsymbol{\mathrm{x}}\:=\:\mathrm{2021}\:\blacktriangle \\ $$…

L-x-6-pi-2-Li-2-x-1-2-log-x-log-1-x-Find-0-1-L-x-Li-2-x-dx-

Question Number 153829 by mathdanisur last updated on 10/Sep/21 $$\mathrm{L}\left(\mathrm{x}\right)\:=\:\frac{\mathrm{6}}{\pi^{\mathrm{2}} }\left(\mathrm{Li}_{\mathrm{2}} \left(\mathrm{x}\right)\:+\:\frac{\mathrm{1}}{\mathrm{2}}\:\mathrm{log}\left(\mathrm{x}\right)\mathrm{log}\left(\mathrm{1}-\mathrm{x}\right)\right. \\ $$$$\mathrm{Find}:\:\:\boldsymbol{\Omega}\:=\underset{\:\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:\mathrm{L}\left(\mathrm{x}\right)\centerdot\mathrm{Li}_{\mathrm{2}} \left(\mathrm{x}\right)\:\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact:…