Question Number 88137 by john santu last updated on 08/Apr/20 $${Mr}\:{mjs}\: \\ $$$${x},\:\mathrm{3},\mathrm{7},\mathrm{13},\mathrm{27},\mathrm{33},{y} \\ $$$${find}\:{x}\:\&\:{y}\:?\:{any}\:{formula} \\ $$$${to}\:{generally}? \\ $$ Commented by MJS last updated on…
Question Number 88141 by A8;15: last updated on 08/Apr/20 Answered by MJS last updated on 08/Apr/20 $$\mathrm{squaring}\:\mathrm{and}\:\mathrm{transforming}\:\mathrm{3}\:\mathrm{times}\:\mathrm{leads}\:\mathrm{to} \\ $$$${x}^{\mathrm{8}} −\mathrm{28}{x}^{\mathrm{6}} +\mathrm{238}{x}^{\mathrm{4}} −\mathrm{588}{x}^{\mathrm{2}} +\mathrm{128}{x}−\mathrm{7}=\mathrm{0} \\ $$$$\mathrm{this}\:\mathrm{can}\:\mathrm{be}\:\mathrm{factorized}…
Question Number 88128 by john santu last updated on 08/Apr/20 $${given}\:\mathrm{27}^{{a}} \:=\:\mathrm{64}^{{b}} \:=\:\mathrm{216}^{{c}} \:=\:\mathrm{72} \\ $$$${find}\:\frac{\mathrm{2020}{abc}}{\mathrm{3}{ab}+\mathrm{3}{ac}+\mathrm{3}{bc}}\:+\:\frac{{ab}+{ac}+{bc}}{\mathrm{2020}{abc}} \\ $$ Answered by $@ty@m123 last updated on 08/Apr/20…
Question Number 153638 by mathdanisur last updated on 08/Sep/21 Commented by EDWIN88 last updated on 09/Sep/21 $${b}×{c}=\mathrm{12}{a} \\ $$$$\Rightarrow{a}^{\mathrm{2}} ={b}^{\mathrm{2}} +{c}^{\mathrm{2}} \\ $$$$\Rightarrow{a}^{\mathrm{2}} =\left({b}+{c}\right)^{\mathrm{2}} −\mathrm{24}{a}…
Question Number 153629 by mathdanisur last updated on 08/Sep/21 Commented by benhamimed last updated on 09/Sep/21 $$\mathrm{1}+{x}+…+{x}^{{n}} =\frac{\mathrm{1}−{x}^{{n}} }{\mathrm{1}−{x}}=\frac{\frac{{t}^{{n}} −\mathrm{1}}{{t}^{{n}} }}{\frac{{t}−\mathrm{1}}{{t}}}=\frac{\left({t}^{{n}} −\mathrm{1}\right)}{{t}^{{n}−\mathrm{1}} \left({t}−\mathrm{1}\right)}\:\:\:\:{tq}\:{x}=\frac{\mathrm{1}}{{t}} \\ $$$${si}\:{x}=\frac{\mathrm{1}}{\mathrm{2021}}\:\:;{t}=\mathrm{2021}…
Question Number 88088 by A8;15: last updated on 08/Apr/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 22547 by Tinkutara last updated on 20/Oct/17 $$\mathrm{If}\:\alpha\:=\:\frac{\mathrm{5}}{\mathrm{2}!\mathrm{3}}\:+\:\frac{\mathrm{5}.\mathrm{7}}{\mathrm{3}!\mathrm{3}^{\mathrm{2}} }\:+\:\frac{\mathrm{5}.\mathrm{7}.\mathrm{9}}{\mathrm{4}!\mathrm{3}^{\mathrm{3}} }\:,…\:\mathrm{then}\:\mathrm{find} \\ $$$$\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\alpha^{\mathrm{2}} \:+\:\mathrm{4}\alpha. \\ $$ Answered by ajfour last updated on 20/Oct/17 $$\left(\mathrm{1}+{x}\right)^{{n}}…
Question Number 153605 by bramlexs22 last updated on 09/Sep/21 $$\:\:\begin{cases}{\sqrt{\mathrm{x}}\:+\sqrt{\mathrm{y}+\mathrm{z}}\:=\mathrm{5}}\\{\sqrt{\mathrm{y}}+\sqrt{\mathrm{z}+\mathrm{x}}\:=\:\mathrm{7}}\\{\sqrt{\mathrm{z}}+\sqrt{\mathrm{x}+\mathrm{y}}\:=\:\mathrm{7}}\end{cases} \\ $$ Commented by Rasheed.Sindhi last updated on 08/Sep/21 $$\:\:\begin{cases}{\sqrt{\mathrm{x}}\:+\sqrt{\mathrm{y}+\mathrm{z}}\:=\mathrm{5}}\\{\sqrt{\mathrm{y}}+\sqrt{\mathrm{z}+\mathrm{x}}\:=\:\mathrm{7}}\\{\sqrt{{z}}+\sqrt{\mathrm{x}+\mathrm{y}}\:=\:\mathrm{7}}\end{cases} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:? \\ $$ Commented…
Question Number 88067 by A8;15: last updated on 08/Apr/20 Answered by MJS last updated on 08/Apr/20 $${x}=\pm\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} } \\ $$$$\mathrm{it}\:\mathrm{is}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{see} \\ $$ Commented…
Question Number 22517 by Tinkutara last updated on 19/Oct/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:{x}\:\mathrm{in}\:\mathrm{the}\:\mathrm{expansion} \\ $$$$\mathrm{of}\:\left[\sqrt{\mathrm{1}\:+\:{x}^{\mathrm{2}} }\:−\:{x}\right]^{−\mathrm{1}} \:\mathrm{in}\:\mathrm{ascending}\:\mathrm{power} \\ $$$$\mathrm{of}\:{x}\:\mathrm{when}\:\mid{x}\mid\:<\:\mathrm{1}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com