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Category: Algebra

Question-156164

Question Number 156164 by MathSh last updated on 08/Oct/21 Answered by ghimisi last updated on 09/Oct/21 x∣=12x+y+xy∣⩽12x+y+12yx(1)y∣=12y+x+yx∣⩽12x+y+12yx∣∣(2)3x+2y∣=∣4x+3y(x+y)∣⩽∣4x+3y+x+y(3)(1)+(2)+(3)$$\mid{x}\mid+\mid{y}\mid+\mid\mathrm{3}{x}+\mathrm{2}{y}\mid\leqslant\mid\mathrm{4}{x}+\mathrm{3}{y}\mid+\mathrm{2}\mid{x}+{y}\mid+\mid{y}−{x}\mid…