Question Number 153128 by mathdanisur last updated on 04/Sep/21 $$\mathrm{if}\:\:\:\frac{\mathrm{x}+\mathrm{y}}{\mathrm{2}}\:+\:\sqrt{\mathrm{xy}}\:=\:\frac{\mathrm{1}+\sqrt{\mathrm{5}}}{\mathrm{2}}\:\:\mathrm{and}\:\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} =\sqrt{\mathrm{5}} \\ $$$$\mathrm{find}\:\:\:\frac{\mathrm{1}}{\mathrm{x}}\:+\:\frac{\mathrm{1}}{\mathrm{y}}\:=\:? \\ $$ Answered by EDWIN88 last updated on 05/Sep/21 $$\:\:\begin{cases}{{x}+{y}={u}}\\{{xy}={v}}\end{cases}\Rightarrow\begin{cases}{{u}+\mathrm{2}\sqrt{{v}}\:=\mathrm{1}+\sqrt{\mathrm{5}}}\\{{u}^{\mathrm{2}} −\mathrm{2}{v}=\sqrt{\mathrm{5}}}\end{cases}…
Question Number 153130 by mathdanisur last updated on 04/Sep/21 $$\mathrm{if}\:\:\:\mathrm{x}^{\mathrm{5}} +\mathrm{x}^{\mathrm{4}} +\mathrm{x}^{\mathrm{3}} +\mathrm{2x}^{\mathrm{2}} +\mathrm{x}+\mathrm{1}=\mathrm{0} \\ $$$$\mathrm{find}\:\:\:\mathrm{x}^{\mathrm{3}} \:-\:\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{3}} }\:=\:? \\ $$ Answered by ajfour last updated…
Question Number 22057 by FilupS last updated on 10/Oct/17 $$\int{f}\left({x}\right){dx}=\left(\frac{{d}}{{dx}}\right)^{\mathrm{2}} \\ $$$${f}\left({x}\right)=??? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 87586 by manr last updated on 05/Apr/20 $${l}.{c}.{m}\:{of}\:{two}\:{numbers}\:{is}\:{p}^{\mathrm{2}} {q}^{\mathrm{4}} {r}^{\mathrm{4}} \:{p}\:{q}\:{r}\:{are} \\ $$$${primes}.{find}\:{the}\:{possible}\:{no}.\:{of}\:{pairs} \\ $$ Answered by mr W last updated on 05/Apr/20…
Question Number 22047 by Tinkutara last updated on 10/Oct/17 $$\mathrm{If}\:{x}\:>\:\mathrm{0}\:\mathrm{and}\:\mathrm{the}\:\mathrm{4}^{\mathrm{th}} \:\mathrm{term}\:\mathrm{in}\:\mathrm{the}\:\mathrm{expansion} \\ $$$$\mathrm{of}\:\left(\mathrm{2}\:+\:\frac{\mathrm{3}}{\mathrm{8}}{x}\right)^{\mathrm{10}} \:\mathrm{has}\:\mathrm{maximum}\:\mathrm{value} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:{x}. \\ $$ Commented by Tinkutara last updated on 10/Oct/17…
Question Number 87581 by peter frank last updated on 05/Apr/20 Commented by TANMAY PANACEA. last updated on 05/Apr/20 $${i}\left[{shall}\:{solve}\:{in}\:{paper}\right. \\ $$ Answered by TANMAY PANACEA.…
Question Number 153103 by amin96 last updated on 04/Sep/21 $$\frac{\mathrm{1}}{\mathrm{2}\centerdot\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}\centerdot\mathrm{5}\centerdot\mathrm{6}}+\frac{\mathrm{1}}{\mathrm{7}\centerdot\mathrm{8}\centerdot\mathrm{9}}+\ldots \\ $$ Answered by puissant last updated on 04/Sep/21 $${S}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\left(\mathrm{3}{n}+\mathrm{1}\right)\left(\mathrm{3}{n}+\mathrm{2}\right)\left(\mathrm{3}{n}+\mathrm{3}\right)} \\ $$$$=\underset{{n}=\mathrm{0}} {\overset{\infty}…
Question Number 87553 by TawaTawa1 last updated on 05/Apr/20 Answered by ajfour last updated on 05/Apr/20 $${let}\:{no}.\:{of}\:{boys}\:{in}\:{A}=\mathrm{3}{k} \\ $$$$\:\:\:\:………..{girls}\:\:….\:{A}\:=\:\mathrm{2}{k} \\ $$$${let}\:\:{no}.\:{of}\:{girls}\:{in}\:{B}=\:{x} \\ $$$$\&\:\:\:{no}.\:{of}\:{boys}\:{in}\:{B}\:=\:{y} \\ $$$${no}.\:{of}\:{girls}\:{in}\:{C}\:=\:{z}…
Question Number 22014 by Tinkutara last updated on 09/Oct/17 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{solution}\left(\mathrm{s}\right)\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{equation}\:\mid\mathrm{log}_{{e}} \left(\mid{x}\mid\right)\mid\:+\:\mid{x}\mid\:=\:\mathrm{10}\:\mathrm{is} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 153079 by mathdanisur last updated on 04/Sep/21 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$\sqrt{\mathrm{1}-\boldsymbol{{z}}}\:=\:\mathrm{2}\boldsymbol{{z}}^{\mathrm{2}} \:-\:\mathrm{1}\:+\:\mathrm{2}\boldsymbol{{z}}\:\sqrt{\mathrm{1}-\boldsymbol{{z}}^{\mathrm{2}} } \\ $$ Commented by MJS_new last updated on 04/Sep/21 $$\mathrm{I}\:\mathrm{get}\:{z}=\mathrm{sin}\:\frac{\pi}{\mathrm{5}}\:=\frac{\sqrt{\mathrm{10}−\mathrm{2}\sqrt{\mathrm{5}}}}{\mathrm{4}} \\…