Question Number 87533 by mr W last updated on 04/Apr/20 Commented by MJS last updated on 05/Apr/20 $${a}=\frac{\mathrm{49}}{\mathrm{76}}\pm\frac{\mathrm{457}\sqrt{\mathrm{87}}}{\mathrm{6612}} \\ $$$${b}=\frac{\mathrm{49}}{\mathrm{76}}\mp\frac{\mathrm{457}\sqrt{\mathrm{87}}}{\mathrm{6612}} \\ $$$${x}=−\mathrm{7}\pm\sqrt{\mathrm{87}} \\ $$$${y}=−\mathrm{7}\mp\sqrt{\mathrm{87}} \\…
Question Number 21990 by hi147 last updated on 08/Oct/17 $${i}\:{still}\:{search}\:{about}\:{a}\:{general}\:{and}\: \\ $$$${complete}\:{solution}\:{about}\:{this} \\ $$$${determine}\:{x}\:{in}\:{N}\:{where}\:\mathrm{7}\:{divise}\:\mathrm{2}^{{x}} +\mathrm{3}^{{x}} \\ $$$${note}\:=\:{it}\:{is}\:{just}\:{an}\:{exercise}\:{in}\:{secondary} \\ $$$${so}\:{dont}\:{go}\:{away}… \\ $$$${maybe}\:{we}\:{must}\:{use}\:{separation}\:{of}\:{cases} \\ $$$${methode}…. \\ $$…
Question Number 153046 by Tawa11 last updated on 04/Sep/21 Commented by Tawa11 last updated on 04/Sep/21 $$\mathrm{If}\:\mathrm{real}\:\mathrm{numbers}\:\:\mathrm{x}\:\:\mathrm{and}\:\:\mathrm{y}\:\:\:\mathrm{satisfies}\:\mathrm{the}\:\mathrm{system}\:\mathrm{shown},\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{x}^{\mathrm{3}} \:\:\:+\:\:\:\mathrm{y}^{\mathrm{3}} \\ $$ Answered by mr…
Question Number 87492 by unknown last updated on 04/Apr/20 $$\frac{\mathrm{2}+\mathrm{3}^{\mathrm{2}} }{\mathrm{1}!+\mathrm{2}!+\mathrm{3}!+\mathrm{4}!}+\frac{\mathrm{3}+\mathrm{4}^{\mathrm{2}} }{\mathrm{2}!+\mathrm{3}!+\mathrm{4}!+\mathrm{5}!}+…+\frac{\mathrm{2013}+\mathrm{2014}^{\mathrm{2}} }{\mathrm{2012}!+\mathrm{2013}!+\mathrm{2014}!+\mathrm{2015}!} \\ $$ Answered by mind is power last updated on 04/Apr/20 $$\underset{{k}\geqslant\mathrm{2}}…
Question Number 153012 by bobhans last updated on 04/Sep/21 $$\:{Find}\:{all}\:{ordered}\:{pairs}\:{of}\:{real}\: \\ $$$$\:{numbers}\:\left({x},{y}\right)\:{for}\:{which} \\ $$$$\:\:\begin{cases}{\left(\mathrm{1}+{x}^{\mathrm{4}} \right)\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{1}+{x}\right)=\mathrm{1}+{y}^{\mathrm{7}} }\\{\left(\mathrm{1}+{y}^{\mathrm{4}} \right)\left(\mathrm{1}+{y}^{\mathrm{2}} \right)\left(\mathrm{1}+{y}\right)=\mathrm{1}+{x}^{\mathrm{7}} }\end{cases} \\ $$ Commented by mr…
Question Number 153019 by mathdanisur last updated on 04/Sep/21 $$\mathrm{Determine}\:\mathrm{all}\:\mathrm{functions}\:\:\mathrm{f}:\mathbb{R}\rightarrow\left(\mathrm{1};+\infty\right) \\ $$$$\mathrm{continuous}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{f}\left(\mathrm{4x}\right)\:\centerdot\:\mathrm{f}\left(\mathrm{3x}\right)\:=\:\mathrm{2}^{\boldsymbol{\mathrm{x}}} \:\:;\:\:\forall\mathrm{x}\in\mathbb{R} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 21940 by Tinkutara last updated on 07/Oct/17 $$\mathrm{A}\:\mathrm{polynomial}\:\mathrm{function}\:{f}\left({x}\right)\:\mathrm{satisfies} \\ $$$${f}\left({x}\right){f}\left(\frac{\mathrm{1}}{{x}}\right)\:=\:\mathrm{2}{f}\left({x}\right)\:+\:\mathrm{2}{f}\left(\frac{\mathrm{1}}{{x}}\right);\:{x}\:\neq\:\mathrm{0}\:\mathrm{and} \\ $$$${f}\left(\mathrm{2}\right)\:=\:\mathrm{18},\:\mathrm{then}\:{f}\left(\mathrm{3}\right)\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$ Commented by ajfour last updated on 07/Nov/18 $${No}\:{one}\:{solved}\:{this},\:{if}\:{correct} \\…
Question Number 152980 by mr W last updated on 03/Sep/21 Commented by mathdanisur last updated on 03/Sep/21 $$\mathrm{a}^{\mathrm{7}} +\mathrm{b}^{\mathrm{7}} +\mathrm{c}^{\mathrm{7}} \:=\:\mathrm{7abc}\left(\mathrm{ab}+\mathrm{bc}+\mathrm{ca}\right)^{\mathrm{2}} \\ $$$$\mathrm{a}^{\mathrm{4}} +\mathrm{b}^{\mathrm{4}} +\mathrm{c}^{\mathrm{4}}…
Question Number 152960 by nitchyy last updated on 03/Sep/21 $$\:\: \\ $$$$\:\:\:\:\mathrm{Find}\:\mathrm{the}\:\mathrm{values}\:\mathrm{for}\:\mathrm{b}\:\mathrm{and}\:\mathrm{c}\:\mathrm{given} \\ $$$$\:\:\:\:\mathrm{that}\:\mathrm{the}\:\mathrm{quadratic}\:\mathrm{expression} \\ $$$$\:\:\:\:{x}^{\mathrm{2}} +\mathrm{b}{x}+\mathrm{c}<\mathrm{0}\: \\ $$$$\:\:\:\:\left\{{x}:−\mathrm{1}<{x}>\mathrm{3}\right\} \\ $$$$\: \\ $$ Answered by…
Question Number 21877 by FilupS last updated on 06/Oct/17 $${x}=^{\mathrm{3}} \sqrt{\mathrm{7}+\mathrm{5}\sqrt{\mathrm{2}}}+^{\mathrm{3}} \sqrt{\mathrm{7}−\mathrm{5}\sqrt{\mathrm{2}}} \\ $$$$\: \\ $$$$\mathrm{1}.\:\mathrm{According}\:\mathrm{to}\:\mathrm{a}\:\mathrm{video},\:{x}=\mathrm{2} \\ $$$$\: \\ $$$$\mathrm{2}.\:\mathrm{According}\:\mathrm{to}\:\mathrm{WolframAlpha}, \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{x}\approx\mathrm{0}.\mathrm{2071}+\mathrm{0}.\mathrm{3587}{i}\:\:\mathrm{for}\:“\mathrm{principal}\:\mathrm{root}'' \\ $$$$\mathrm{and}\:\:\:{x}=\mathrm{2}\sqrt{\mathrm{2}}\:\:\mathrm{for}\:“\mathrm{real}-\mathrm{valued}\:\mathrm{root}'' \\…